Summarize this article:
Last updated on September 24, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 60 and 90.
The greatest common factor of 60 and 90 is 30. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 60 and 90, a few methods are described below:
Steps to find the GCF of 60 and 90 using the listing of factors:
Step 1: Firstly, list the factors of each number.
Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Factors of 90 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
Step 2: Now, identify the common factors of them. Common factors of 60 and 90: 1, 2, 3, 5, 6, 10, 15, 30.
Step 3: Choose the largest factor. The largest factor that both numbers have is 30. The GCF of 60 and 90 is 30.
To find the GCF of 60 and 90 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number.
Prime Factors of 60: 60 = 2 x 2 x 3 x 5 = 2² x 3 x 5
Prime Factors of 90: 90 = 2 x 3 x 3 x 5 = 2 x 3² x 5
Step 2: Now, identify the common prime factors. The common prime factors are: 2 x 3 x 5 = 2¹ x 3¹ x 5¹
Step 3: Multiply the common prime factors. 2¹ x 3¹ x 5¹ = 2 x 3 x 5 = 30.
The Greatest Common Factor of 60 and 90 is 30.
Find the GCF of 60 and 90 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number. Here, divide 90 by 60. 90 ÷ 60 = 1 (quotient), The remainder is calculated as 90 − (60×1) = 30. The remainder is 30, not zero, so continue the process.
Step 2: Now divide the previous divisor (60) by the previous remainder (30). Divide 60 by 30. 60 ÷ 30 = 2 (quotient), remainder = 60 − (30×2) = 0.
The remainder is zero, the divisor will become the GCF. The GCF of 60 and 90 is 30.
Finding the GCF of 60 and 90 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 60 roses and 90 tulips. She wants to group them into equal sets, with the largest number of flowers in each group. How many flowers will be in each group?
We should find the GCF of 60 and 90. GCF of 60 and 90 2 x 3 x 5 = 30.
There are 30 equal groups. 60 ÷ 30 = 2 90 ÷ 30 = 3
There will be 30 groups, and each group gets 2 roses and 3 tulips.
As the GCF of 60 and 90 is 30, the gardener can make 30 groups.
Now divide 60 and 90 by 30. Each group gets 2 roses and 3 tulips.
A school has 60 green chairs and 90 yellow chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 60 and 90 2 x 3 x 5 = 30. So each row will have 30 chairs.
There are 60 green and 90 yellow chairs.
To find the total number of chairs in each row, we should find the GCF of 60 and 90.
There will be 30 chairs in each row.
A tailor has 60 meters of green fabric and 90 meters of red fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 60 and 90.
The GCF of 60 and 90 2 x 3 x 5 = 30.
The fabric is 30 meters long.
For calculating the longest length of the fabric first, we need to calculate the GCF of 60 and 90, which is 30.
The length of each piece of the fabric will be 30 meters.
A carpenter has two wooden planks, one 60 cm long and the other 90 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 60 and 90 2 x 3 x 5 = 30.
The longest length of each piece is 30 cm.
To find the longest length of each piece of the two wooden planks, 60 cm and 90 cm,
respectively, we have to find the GCF of 60 and 90, which is 30 cm.
The longest length of each piece is 30 cm.
If the GCF of 60 and ‘a’ is 30, and the LCM is 180. Find ‘a’.
The value of ‘a’ is 90.
GCF x LCM = product of the numbers
30 × 180 = 60 × a
5400 = 60a
a = 5400 ÷ 60 = 90
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.