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Last updated on September 24, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 18 and 25.
The greatest common factor of 18 and 25 is 1. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 18 and 25, a few methods are described below
Steps to find the GCF of 18 and 25 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 18 = 1, 2, 3, 6, 9, 18. Factors of 25 = 1, 5, 25.
Step 2: Now, identify the common factors of them Common factor of 18 and 25: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1. The GCF of 18 and 25 is 1.
To find the GCF of 18 and 25 using the Prime Factorization method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 18: 18 = 2 × 3 × 3 = 2 × 3² Prime Factors of 25: 25 = 5 × 5 = 5²
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Multiply the common prime factors Since there are no common prime factors, the GCF is 1. The Greatest Common Factor of 18 and 25 is 1.
Find the GCF of 18 and 25 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 25 by 18 25 ÷ 18 = 1 (quotient), The remainder is calculated as 25 − (18×1) = 7 The remainder is 7, not zero, so continue the process
Step 2: Now divide the previous divisor (18) by the previous remainder (7) Divide 18 by 7 18 ÷ 7 = 2 (quotient), remainder = 18 − (7×2) = 4 Continue the process
Step 3: Now divide the previous divisor (7) by the previous remainder (4) Divide 7 by 4 7 ÷ 4 = 1 (quotient), remainder = 7 − (4×1) = 3 Continue the process
Step 4: Now divide the previous divisor (4) by the previous remainder (3) Divide 4 by 3 4 ÷ 3 = 1 (quotient), remainder = 4 − (3×1) = 1 Continue the process
Step 5: Now divide the previous divisor (3) by the previous remainder (1) Divide 3 by 1 3 ÷ 1 = 3 (quotient), remainder = 3 − (1×3) = 0 The remainder is zero, the divisor will become the GCF.
The GCF of 18 and 25 is 1.
Finding GCF of 18 and 25 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A farmer has 18 apple trees and 25 orange trees. He wants to arrange them in rows with the same number of trees in each row, with the maximum number of trees per row. How many trees will be in each row?
We should find the GCF of 18 and 25. The GCF of 18 and 25 is 1. There will be 1 tree in each row.
As the GCF of 18 and 25 is 1, the farmer can arrange the trees such that each row has 1 tree for both apple and orange trees.
A baker has 18 loaves of whole wheat bread and 25 loaves of rye bread. He wants to pack them in bags containing the same number of loaves, with the largest number of loaves per bag. How many loaves will each bag contain?
The GCF of 18 and 25 is 1. So each bag will have 1 loaf.
There are 18 loaves of whole wheat bread and 25 loaves of rye bread.
To find the total number of loaves in each bag, we should find the GCF of 18 and 25.
There will be 1 loaf in each bag.
A painter has 18 red paint cans and 25 blue paint cans. He wants to use them in projects with the same number of cans, using the maximum possible number of cans per project. How many cans will each project use?
For calculating the maximum number of cans, we have to calculate the GCF of 18 and 25. The GCF of 18 and 25 is 1. Each project will use 1 can.
For calculating the maximum number of cans per project, first, we need to calculate the GCF of 18 and 25, which is 1.
Each project will use 1 can.
A tailor has two pieces of cloth, one 18 meters long and the other 25 meters long. She wants to cut them into the longest possible equal pieces, without any cloth left over. What should be the length of each piece?
The tailor needs the longest piece of cloth. The GCF of 18 and 25 is 1. The longest length of each piece is 1 meter.
To find the longest length of each piece of the two cloths, 18 meters and 25 meters, respectively, we have to find the GCF of 18 and 25, which is 1 meter.
The longest length of each piece is 1 meter.
If the GCF of 18 and ‘b’ is 1, and the LCM is 450. Find ‘b’.
The value of ‘b’ is 25.
GCF × LCM = product of the numbers
1 × 450 = 18 × b
450 = 18b
b = 450 ÷ 18
= 25
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.