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103 LearnersLast updated on September 24, 2025
GCF of 48 and 27
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 48 and 27.
What is the GCF of 48 and 27?
The greatest common factor of 48 and 27 is 3. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
How to find the GCF of 48 and 27?
To find the GCF of 48 and 27, a few methods are described below -
- Listing Factors
- Prime Factorization
- Long Division Method / by Euclidean Algorithm
GCF of 48 and 27 by Using Listing of Factors
Steps to find the GCF of 48 and 27 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.
Factors of 27 = 1, 3, 9, 27.
Step 2: Now, identify the common factors of them Common factors of 48 and 27: 1, 3.
Step 3: Choose the largest factor The largest factor that both numbers have is 3.
The GCF of 48 and 27 is 3.
GCF of 48 and 27 Using Prime Factorization
To find the GCF of 48 and 27 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 48: 48 = 2 x 2 x 2 x 2 x 3 = 24 x 3
Prime Factors of 27: 27 = 3 x 3 x 3 = 33
Step 2: Now, identify the common prime factors The common prime factor is: 3
Step 3: Multiply the common prime factors 3 = 3. The Greatest Common Factor of 48 and 27 is 3.
GCF of 48 and 27 Using Division Method or Euclidean Algorithm Method
Find the GCF of 48 and 27 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 48 by 27 48 ÷ 27 = 1 (quotient), The remainder is calculated as 48 − (27×1) = 21 The remainder is 21, not zero, so continue the process
Step 2: Now divide the previous divisor (27) by the previous remainder (21) Divide 27 by 21 27 ÷ 21 = 1 (quotient), remainder = 27 − (21×1) = 6 Continue with the next step
Step 3: Divide the previous divisor (21) by the previous remainder (6) 21 ÷ 6 = 3 (quotient), remainder = 21 − (6×3) = 3
Step 4: Divide the previous divisor (6) by the previous remainder (3) 6 ÷ 3 = 2 (quotient), remainder = 6 − (3×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 48 and 27 is 3.
Common Mistakes and How to Avoid Them in GCF of 48 and 27
Finding GCF of 48 and 27 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
Mistake 1
Listing Incorrect Factors
Students may sometimes list incorrect factors. For example, while listing factors of 48, students may mention 10, which is incorrect. To avoid this, students should carefully divide the number and list the factors correctly.
Mistake 2
Choosing the Wrong Common Factor
Students may sometimes select the smallest common factor instead of the largest one. To avoid this confusion, students should list all the common factors and find the greatest one.
Mistake 3
Forgetting to Include 1 as a Factor
Sometimes students may forget 1 as a common factor of the numbers. However, it does not affect the GCF, but it tells about the incomplete understanding of the factors. Students should include 1 as a factor.
Mistake 4
Using Multiples Instead of Factors
Students confuse factors and multiples. In that confusion, sometimes they may write multiples instead of factors. To avoid this confusion, students should know the definitions of multiples and factors clearly.
Mistake 5
Assuming GCF is Always an Even Number
Students may assume that the GCF of two numbers will always be an even number. But it's not true that a GCF can also be an odd number. To avoid this, students should focus on common factors rather than focusing on even and odd numbers.
Greatest Common Factor of 48 and 27 Examples
Problem 1
A baker has 48 cookies and 27 cupcakes. She wants to pack them into boxes with the same number of pastries in each box, with the largest number of items per box. How many items will be in each box?
We should find the GCF of 48 and 27. GCF of 48 and 27: 3.
There are 3 equal groups. 48 ÷ 3 = 16 27 ÷ 3 = 9
There will be 3 groups, and each group gets 16 cookies and 9 cupcakes.
Explanation
As the GCF of 48 and 27 is 3, the baker can make 3 groups.
Now divide 48 and 27 by 3. Each group gets 16 cookies and 9 cupcakes.
Problem 2
A gardener has 48 roses and 27 tulips. She wants to arrange them in bouquets with the same number of flowers in each bouquet, using the largest possible number of flowers per bouquet. How many flowers will be in each bouquet?
GCF of 48 and 27: 3. So each bouquet will have 3 flowers.
Explanation
There are 48 roses and 27 tulips. To find the total number of flowers in each bouquet, we should find the GCF of 48 and 27.
There will be 3 flowers in each bouquet.
Problem 3
A tailor has 48 meters of silk fabric and 27 meters of linen fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 48 and 27.
The GCF of 48 and 27: 3. Each piece of fabric is 3 meters long.
Explanation
For calculating the longest length of the fabric, first, we need to calculate the GCF of 48 and 27, which is 3.
The length of each piece of fabric will be 3 meters.
Problem 4
A woodworker has two wooden boards, one 48 cm long and the other 27 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The woodworker needs the longest piece of wood. GCF of 48 and 27: 3. The longest length of each piece is 3 cm.
Explanation
To find the longest length of each piece of the two wooden boards, 48 cm and 27 cm, respectively,
we have to find the GCF of 48 and 27, which is 3 cm.
The longest length of each piece is 3 cm.
Problem 5
If the GCF of 48 and ‘b’ is 3, and the LCM is 432. Find ‘b’.
The value of ‘b’ is 27.
Explanation
GCF x LCM = product of the numbers
3 × 432 = 48 × b
1296 = 48b
b = 1296 ÷ 48 = 27
FAQs on the Greatest Common Factor of 48 and 27
1.What is the LCM of 48 and 27?
2.Is 48 divisible by 2?
3.What will be the GCF of any two prime numbers?
4.What is the prime factorization of 27?
5.Are 48 and 27 prime numbers?
Important Glossaries for GCF of 48 and 27
- Factors: Factors are numbers that divide the target number completely. For example, the factors of 18 are 1, 2, 3, 6, 9, and 18.
- Multiple: Multiples are the products we get by multiplying a given number by another. For example, the multiples of 5 are 5, 10, 15, 20, and so on.
- Prime Factors: These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 21 are 3 and 7.
- Remainder: The value left after division when the number cannot be divided evenly. For example, when 17 is divided by 5, the remainder is 2 and the quotient is 3.
- LCM: The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 48 and 27 is 432.
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Hiralee Lalitkumar Makwana
About the Author
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
Fun Fact
: She loves to read number jokes and games.
