Summarize this article:
Last updated on September 24, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 36 and 50.
The greatest common factor of 36 and 50 is 2. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 36 and 50, a few methods are described below:
Steps to find the GCF of 36 and 50 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18, 36. Factors of 50 = 1, 2, 5, 10, 25, 50.
Step 2: Now, identify the common factors of them Common factors of 36 and 50: 1, 2.
Step 3: Choose the largest factor The largest factor that both numbers have is 2. The GCF of 36 and 50 is 2.
To find the GCF of 36 and 50 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 36: 36 = 2 × 2 × 3 × 3 = 2² × 3² Prime Factors of 50: 50 = 2 × 5 × 5 = 2 × 5²
Step 2: Now, identify the common prime factors The common prime factor is: 2
Step 3: Multiply the common prime factors The Greatest Common Factor of 36 and 50 is 2.
Find the GCF of 36 and 50 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 50 by 36 50 ÷ 36 = 1 (quotient), The remainder is calculated as 50 − (36×1) = 14 The remainder is 14, not zero, so continue the process
Step 2: Now divide the previous divisor (36) by the previous remainder (14) Divide 36 by 14 36 ÷ 14 = 2 (quotient), remainder = 36 − (14×2) = 8 Continue the process
Step 3: Now divide 14 by 8 14 ÷ 8 = 1 (quotient), remainder = 14 − (8×1) = 6
Step 4: Now divide 8 by 6 8 ÷ 6 = 1 (quotient), remainder = 8 − (6×1) = 2
Step 5: Now divide 6 by 2 6 ÷ 2 = 3 (quotient), remainder = 6 − (2×3) = 0 The remainder is zero, so the divisor will become the GCF.
The GCF of 36 and 50 is 2.
Finding GCF of 36 and 50 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A painter has 36 cans of red paint and 50 cans of blue paint. He wants to distribute them into equal sets, with the largest number of items in each set. How many items will be in each set?
We should find GCF of 36 and 50 GCF of 36 and 50 is 2. There are 2 equal groups 36 ÷ 2 = 18 50 ÷ 2 = 25 There will be 2 groups, and each group gets 18 cans of red paint and 25 cans of blue paint.
As the GCF of 36 and 50 is 2, the painter can make 2 groups.
Now divide 36 and 50 by 2.
Each group gets 18 cans of red paint and 25 cans of blue paint.
A school has 36 red balls and 50 blue balls. They want to arrange them in rows with the same number of balls in each row, using the largest possible number of balls per row. How many balls will be in each row?
GCF of 36 and 50 is 2. So each row will have 2 balls.
There are 36 red and 50 blue balls.
To find the total number of balls in each row, we should find the GCF of 36 and 50.
There will be 2 balls in each row.
A tailor has 36 meters of red fabric and 50 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 36 and 50 The GCF of 36 and 50 is 2. The fabric is 2 meters long.
For calculating the longest length of the fabric first we need to calculate the GCF of 36 and 50 which is 2.
The length of each piece of the fabric will be 2 meters.
A carpenter has two wooden planks, one 36 cm long and the other 50 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 36 and 50 is 2. The longest length of each piece is 2 cm.
To find the longest length of each piece of the two wooden planks, 36 cm and 50 cm, respectively.
We have to find the GCF of 36 and 50, which is 2 cm.
The longest length of each piece is 2 cm.
If the GCF of 36 and ‘b’ is 2, and the LCM is 180. Find ‘b’.
The value of ‘b’ is 100.
GCF × LCM = product of the numbers
2 × 180 = 36 × b
360 = 36b ]
b = 360 ÷ 36
= 10
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.