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Last updated on September 25, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 68 and 56.
The greatest common factor of 68 and 56 is 4. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 68 and 56, a few methods are described below:
Steps to find the GCF of 68 and 56 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 68 = 1, 2, 4, 17, 34, 68. Factors of 56 = 1, 2, 4, 7, 8, 14, 28, 56.
Step 2: Now, identify the common factors of them Common factors of 68 and 56: 1, 2, 4.
Step 3: Choose the largest factor The largest factor that both numbers have is 4. The GCF of 68 and 56 is 4.
To find the GCF of 68 and 56 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 68: 68 = 2 x 2 x 17 = 2² x 17 Prime Factors of 56: 56 = 2 x 2 x 2 x 7 = 2³ x 7
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 2 = 2²
Step 3: Multiply the common prime factors 2² = 4. The Greatest Common Factor of 68 and 56 is 4.
Find the GCF of 68 and 56 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 68 by 56 68 ÷ 56 = 1 (quotient) The remainder is calculated as 68 − (56×1) = 12 The remainder is 12, not zero, so continue the process
Step 2: Now divide the previous divisor (56) by the previous remainder (12) Divide 56 by 12 56 ÷ 12 = 4 (quotient), remainder = 56 − (12×4) = 8
Step 3: Now divide the previous divisor (12) by the new remainder (8) 12 ÷ 8 = 1 (quotient), remainder = 12 − (8×1) = 4
Step 4: Now divide the previous divisor (8) by the new remainder (4) 8 ÷ 4 = 2 (quotient), remainder = 8 − (4×2) = 0 The remainder is zero, the divisor will become the GCF.
The GCF of 68 and 56 is 4.
Finding GCF of 68 and 56 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 68 markers and 56 highlighters. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 68 and 56 GCF of 68 and 56 is 4. There are 4 equal groups 68 ÷ 4 = 17 56 ÷ 4 = 14 There will be 4 groups, and each group gets 17 markers and 14 highlighters.
As the GCF of 68 and 56 is 4, the teacher can make 4 groups.
Now divide 68 and 56 by 4.
Each group gets 17 markers and 14 highlighters.
A school has 68 red chairs and 56 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 68 and 56 is 4. So each row will have 4 chairs.
There are 68 red and 56 blue chairs.
To find the total number of chairs in each row, we should find the GCF of 68 and 56.
There will be 4 chairs in each row.
A tailor has 68 meters of red ribbon and 56 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 68 and 56 The GCF of 68 and 56 is 4. The ribbon is 4 meters long.
For calculating the longest length of the ribbon first we need to calculate the GCF of 68 and 56 which is 4.
The length of each piece of the ribbon will be 4 meters.
A carpenter has two wooden planks, one 68 cm long and the other 56 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 68 and 56 is 4. The longest length of each piece is 4 cm.
To find the longest length of each piece of the two wooden planks, 68 cm and 56 cm, respectively.
We have to find the GCF of 68 and 56, which is 4 cm.
The longest length of each piece is 4 cm.
If the GCF of 68 and ‘a’ is 4, and the LCM is 952. Find ‘a’.
The value of ‘a’ is 56.
GCF x LCM = product of the numbers
4 × 952 = 68 × a
3808 = 68a
a = 3808 ÷ 68
= 56
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.