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Last updated on September 9, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, group or arrange items, and schedule events. In this topic, we will learn about the GCF of 25 and 60.
The greatest common factor of 25 and 60 is 5. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 25 and 60, a few methods are described below
Steps to find the GCF of 25 and 60 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 25 = 1, 5, 25. Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Step 2: Now, identify the common factors of them Common factors of 25 and 60: 1, 5.
Step 3: Choose the largest factor The largest factor that both numbers have is 5. The GCF of 25 and 60 is 5.
To find the GCF of 25 and 60 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 25: 25 = 5 × 5 = 5² Prime Factors of 60: 60 = 2 × 2 × 3 × 5 = 2² × 3 × 5
Step 2: Now, identify the common prime factors The common prime factor is: 5
Step 3: Multiply the common prime factors 5 = 5. The Greatest Common Factor of 25 and 60 is 5.
Find the GCF of 25 and 60 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 60 by 25 60 ÷ 25 = 2 (quotient), The remainder is calculated as 60 − (25×2) = 10 The remainder is 10, not zero, so continue the process
Step 2: Now divide the previous divisor (25) by the previous remainder (10) Divide 25 by 10 25 ÷ 10 = 2 (quotient), remainder = 25 − (10×2) = 5
Step 3: Now divide the previous divisor (10) by the previous remainder (5) Divide 10 by 5 10 ÷ 5 = 2 (quotient), remainder = 10 − (5×2) = 0 The remainder is zero, the divisor will become the GCF. The GCF of 25 and 60 is 5.
Finding the GCF of 25 and 60 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 25 markers and 60 notebooks. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 25 and 60. GCF of 25 and 60 is 5. There are 5 equal groups. 25 ÷ 5 = 5 60 ÷ 5 = 12 There will be 5 groups, and each group gets 5 markers and 12 notebooks.
As the GCF of 25 and 60 is 5, the teacher can make 5 groups.
Now divide 25 and 60 by 5.
Each group gets 5 markers and 12 notebooks.
A school has 25 chairs and 60 desks. They want to arrange them in rows with the same number of chairs and desks in each row, using the largest possible number of items per row. How many items will be in each row?
GCF of 25 and 60 is 5. So each row will have 5 chairs and 5 desks.
There are 25 chairs and 60 desks.
To find the total number of items in each row, we should find the GCF of 25 and 60.
There will be 5 items in each row.
A tailor has 25 meters of red fabric and 60 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 25 and 60. The GCF of 25 and 60 is 5. The fabric is 5 meters long.
For calculating the longest length of the fabric, first we need to calculate the GCF of 25 and 60, which is 5.
The length of each piece of the fabric will be 5 meters.
A carpenter has two wooden planks, one 25 cm long and the other 60 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 25 and 60 is 5. The longest length of each piece is 5 cm.
To find the longest length of each piece of the two wooden planks, 25 cm and 60 cm, respectively, we have to find the GCF of 25 and 60, which is 5 cm.
The longest length of each piece is 5 cm.
If the GCF of 25 and ‘b’ is 5, and the LCM is 300. Find ‘b’.
The value of ‘b’ is 60.
GCF × LCM = product of the numbers
5 × 300
= 25 × b 1500
= 25b b
= 1500 ÷ 25 = 60
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.