Summarize this article:
Last updated on September 9, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 3 and 5.
The greatest common factor of 3 and 5 is 1. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 3 and 5, a few methods are described below
Steps to find the GCF of 3 and 5 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 3 = 1, 3. Factors of 5 = 1, 5.
Step 2: Now, identify the common factors Common factors of 3 and 5: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1. The GCF of 3 and 5 is 1.
To find the GCF of 3 and 5 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 3: 3 = 3
Prime Factors of 5: 5 = 5
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Therefore, the GCF is 1, since there are no common prime factors other than 1.
Find the GCF of 3 and 5 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 5 by 3 5 ÷ 3 = 1 (quotient), The remainder is calculated as 5 − (3×1) = 2 The remainder is 2, not zero, so continue the process
Step 2: Now divide the previous divisor (3) by the previous remainder (2) 3 ÷ 2 = 1 (quotient), remainder = 3 − (2×1) = 1
Step 3: Now divide the previous divisor (2) by the previous remainder (1) 2 ÷ 1 = 2 (quotient), remainder = 2 − (1×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 3 and 5 is 1.
Finding the GCF of 3 and 5 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 3 apples and 5 oranges. She wants to group them into equal sets, with the largest number of fruits in each group. How many fruits will be in each group?
We should find the GCF of 3 and 5. The GCF of 3 and 5 is 1. There is 1 equal group with 3 apples and 5 oranges.
As the GCF of 3 and 5 is 1, the teacher can make only one group with all the fruits.
There is no further division possible.
A school has 3 red flags and 5 blue flags. They want to arrange them in rows with the same number of flags in each row, using the largest possible number of flags per row. How many flags will be in each row?
The GCF of 3 and 5 is 1, so each row can have 1 flag.
There are 3 red and 5 blue flags.
To find the total number of flags in each row, we should find the GCF of 3 and 5, which is 1.
So, there will be 1 flag in each row.
A tailor has 3 meters of red fabric and 5 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
To calculate the longest equal length, we have to calculate the GCF of 3 and 5. The GCF of 3 and 5 is 1. Each piece of fabric is 1 meter long.
For calculating the longest length of the fabric first, we need to calculate the GCF of 3 and 5, which is 1.
The length of each piece of fabric will be 1 meter.
A carpenter has two wooden planks, one 3 cm long and the other 5 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. The GCF of 3 and 5 is 1. The longest length of each piece is 1 cm.
To find the longest length of each piece of the two wooden planks, 3 cm and 5 cm, respectively, we have to find the GCF of 3 and 5, which is 1 cm.
The longest length of each piece is 1 cm.
If the GCF of 3 and ‘a’ is 1, and the LCM is 15, find ‘a’.
The value of ‘a’ is 5.
GCF × LCM = product of the numbers 1 × 15 = 3 × a 15 = 3a a = 15 ÷ 3 = 5
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.