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Last updated on September 9, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items and schedule events. In this topic, we will learn about the GCF of 40 and 50.
The greatest common factor of 40 and 50 is 10. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 40 and 50, a few methods are described below
Steps to find the GCF of 40 and 50 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 40 = 1, 2, 4, 5, 8, 10, 20, 40. Factors of 50 = 1, 2, 5, 10, 25, 50.
Step 2: Now, identify the common factors of them Common factors of 40 and 50: 1, 2, 5, 10.
Step 3: Choose the largest factor The largest factor that both numbers have is 10. The GCF of 40 and 50 is 10.
To find the GCF of 40 and 50 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 40: 40 = 2 x 2 x 2 x 5 = 23 x 5 Prime Factors of 50: 50 = 2 x 5 x 5 = 2 x 52
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 5
Step 3: Multiply the common prime factors 2 x 5 = 10. The Greatest Common Factor of 40 and 50 is 10.
Find the GCF of 40 and 50 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 50 by 40 50 ÷ 40 = 1 (quotient), The remainder is calculated as 50 − (40×1) = 10 The remainder is 10, not zero, so continue the process
Step 2: Now divide the previous divisor (40) by the previous remainder (10) Divide 40 by 10 40 ÷ 10 = 4 (quotient), remainder = 40 − (10×4) = 0 The remainder is zero, the divisor will become the GCF.
The GCF of 40 and 50 is 10.
Finding GCF of 40 and 50 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 40 roses and 50 tulips. She wants to create bouquets with the largest number of flowers in each bouquet. How many flowers will be in each bouquet?
We should find the GCF of 40 and 50 GCF of 40 and 50 2 x 5 = 10. There are 10 equal bouquets 40 ÷ 10 = 4 50 ÷ 10 = 5 There will be 10 bouquets, and each bouquet gets 4 roses and 5 tulips.
As the GCF of 40 and 50 is 10, the gardener can make 10 bouquets.
Now divide 40 and 50 by 10.
Each bouquet gets 4 roses and 5 tulips.
A caterer has 40 plates and 50 cups. They want to arrange them in stacks with the same number of items in each stack, using the largest possible number of items per stack. How many items will be in each stack?
GCF of 40 and 50 2 x 5 = 10. So each stack will have 10 items.
There are 40 plates and 50 cups.
To find the total number of items in each stack, we should find the GCF of 40 and 50.
There will be 10 items in each stack.
A painter has 40 liters of white paint and 50 liters of blue paint. She wants to store them in cans of equal volume, using the largest possible volume. What should be the volume of each can?
For calculating the largest equal volume, we have to calculate the GCF of 40 and 50 The GCF of 40 and 50 2 x 5 = 10. Each can will have 10 liters.
For calculating the largest volume of paint, first, we need to calculate the GCF of 40 and 50, which is 10.
The volume of each can will be 10 liters.
A tailor has two rolls of fabric, one 40 meters long and the other 50 meters long. She wants to cut them into the longest possible equal pieces, without any fabric left over. What should be the length of each piece?
The tailor needs the longest piece of fabric GCF of 40 and 50 2 x 5 = 10. The longest length of each piece is 10 meters.
To find the longest length of each piece of the two fabric rolls, 40 meters and 50 meters, respectively.
We have to find the GCF of 40 and 50, which is 10 meters.
The longest length of each piece is 10 meters.
If the GCF of 40 and ‘a’ is 10, and the LCM is 200. Find ‘a’.
The value of ‘a’ is 50.
GCF x LCM = product of the numbers
10 × 200
= 40 × a 2000
= 40a a
= 2000 ÷ 40 = 50
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.