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Last updated on September 19, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 48 and 84.
The greatest common factor of 48 and 84 is 12. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 48 and 84, a few methods are described below
Steps to find the GCF of 48 and 84 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48.
Factors of 84 = 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84.
Step 2: Now, identify the common factors Common factors of 48 and 84: 1, 2, 3, 4, 6, 12.
Step 3: Choose the largest factor The largest factor that both numbers have is 12.
The GCF of 48 and 84 is 12.
To find the GCF of 48 and 84 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 48: 48 = 2 x 2 x 2 x 2 x 3 = 24 x 3
Prime Factors of 84: 84 = 2 x 2 x 3 x 7 = 22 x 3 x 7
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 2 x 3 = 22 x 3
Step 3: Multiply the common prime factors 22 x 3 = 4 × 3 = 12. The Greatest Common Factor of 48 and 84 is 12.
Find the GCF of 48 and 84 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 84 by 48 84 ÷ 48 = 1 (quotient),
The remainder is calculated as 84 − (48×1) = 36 The remainder is 36, not zero, so continue the process
Step 2: Now divide the previous divisor (48) by the previous remainder (36)
Divide 48 by 36 48 ÷ 36 = 1 (quotient), remainder = 48 − (36×1) = 12
Step 3: Now divide the previous divisor (36) by the previous remainder (12) 36 ÷ 12 = 3 (quotient), remainder = 36 − (12×3) = 0 The remainder is zero, the divisor will become the GCF.
The GCF of 48 and 84 is 12.
Finding the GCF of 48 and 84 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by students.
A teacher has 48 notebooks and 84 markers. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 48 and 84 GCF of 48 and 84 22 x 3 = 4 x 3 = 12.
There are 12 equal groups 48 ÷ 12 = 4 84 ÷ 12 = 7
There will be 12 groups, and each group gets 4 notebooks and 7 markers.
As the GCF of 48 and 84 is 12, the teacher can make 12 groups.
Now divide 48 and 84 by 12.
Each group gets 4 notebooks and 7 markers.
A school has 48 red chairs and 84 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 48 and 84 2^2 x 3 = 4 × 3 = 12.
So each row will have 12 chairs.
There are 48 red and 84 blue chairs.
To find the total number of chairs in each row, we should find the GCF of 48 and 84.
There will be 12 chairs in each row.
A tailor has 48 meters of red ribbon and 84 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 48 and 84
The GCF of 48 and 84 22 x 3 = 4 × 3 = 12.
The ribbon is 12 meters long.
For calculating the longest length of the ribbon first, we need to calculate the GCF of 48 and 84, which is 12.
The length of each piece of the ribbon will be 12 meters.
A carpenter has two wooden planks, one 48 cm long and the other 84 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 48 and 84 22 x 3 = 4 × 3 = 12.
The longest length of each piece is 12 cm.
To find the longest length of each piece of the two wooden planks, 48 cm and 84 cm, respectively, we have to find the GCF of 48 and 84, which is 12 cm.
The longest length of each piece is 12 cm.
If the GCF of 48 and ‘a’ is 12, and the LCM is 336. Find ‘a’.
The value of ‘a’ is 84.
GCF x LCM = product of the numbers
12 × 336 = 48 × a
4032 = 48a
a = 4032 ÷ 48 = 84
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.