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Last updated on September 9, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items and schedule events. In this topic, we will learn about the GCF of 60 and 84.
The greatest common factor of 60 and 84 is 12. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 60 and 84, a few methods are described below
Steps to find the GCF of 60 and 84 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Factors of 84 = 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84.
Step 2: Now, identify the common factors of them Common factors of 60 and 84: 1, 2, 3, 4, 6, 12.
Step 3: Choose the largest factor The largest factor that both numbers have is 12. The GCF of 60 and 84 is 12.
To find the GCF of 60 and 84 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 60: 60 = 2 x 2 x 3 x 5 = 2² x 3 x 5 Prime Factors of 84: 84 = 2 x 2 x 3 x 7 = 2² x 3 x 7
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 2 x 3 = 2² x 3
Step 3: Multiply the common prime factors 2² x 3 = 4 x 3 = 12. The Greatest Common Factor of 60 and 84 is 12.
Find the GCF of 60 and 84 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 84 by 60 84 ÷ 60 = 1 (quotient), remainder is calculated as 84 − (60×1) = 24 The remainder is 24, not zero, so continue the process
Step 2: Now divide the previous divisor (60) by the previous remainder (24) Divide 60 by 24 60 ÷ 24 = 2 (quotient), remainder = 60 − (24×2) = 12 The remainder is 12, not zero, so continue the process
Step 3: Now divide the previous divisor (24) by the previous remainder (12) Divide 24 by 12 24 ÷ 12 = 2 (quotient), remainder = 24 − (12×2) = 0 The remainder is zero, the divisor will become the GCF. The GCF of 60 and 84 is 12.
Finding GCF of 60 and 84 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A chef has 60 apples and 84 oranges. He wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 60 and 84 GCF of 60 and 84 2² x 3 = 4 x 3 = 12. There are 12 equal groups 60 ÷ 12 = 5 84 ÷ 12 = 7 There will be 12 groups, and each group gets 5 apples and 7 oranges.
As the GCF of 60 and 84 is 12, the chef can make 12 groups.
Now divide 60 and 84 by 12.
Each group gets 5 apples and 7 oranges.
A school has 60 red chairs and 84 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 60 and 84 2² x 3 = 4 × 3 = 12. So each row will have 12 chairs.
There are 60 red and 84 blue chairs.
To find the total number of chairs in each row, we should find the GCF of 60 and 84.
There will be 12 chairs in each row.
A tailor has 60 meters of red ribbon and 84 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 60 and 84 The GCF of 60 and 84 2² x 3 = 4 × 3 = 12. The ribbon is 12 meters long.
For calculating the longest length of the ribbon, first we need to calculate the GCF of 60 and 84, which is 12.
The length of each piece of the ribbon will be 12 meters.
A carpenter has two wooden planks, one 60 cm long and the other 84 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 60 and 84 2² x 3 = 4 × 3 = 12. The longest length of each piece is 12 cm.
To find the longest length of each piece of the two wooden planks, 60 cm and 84 cm respectively, we have to find the GCF of 60 and 84, which is 12 cm.
The longest length of each piece is 12 cm.
If the GCF of 60 and ‘a’ is 12, and the LCM is 420, find ‘a’.
The value of ‘a’ is 84.
GCF x LCM = product of the numbers
12 × 420
= 60 × a 5040
= 60a a
= 5040 ÷ 60 = 84
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.