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Last updated on September 9, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 50 and 60.
The greatest common factor of 50 and 60 is 10. The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 50 and 60, a few methods are described below -
Steps to find the GCF of 50 and 60 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 50 = 1, 2, 5, 10, 25, 50. Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Step 2: Now, identify the common factors of them Common factors of 50 and 60: 1, 2, 5, 10.
Step 3: Choose the largest factor The largest factor that both numbers have is 10. The GCF of 50 and 60 is 10.
To find the GCF of 50 and 60 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 50: 50 = 2 x 5 x 5 = 2 x 5² Prime Factors of 60: 60 = 2 x 2 x 3 x 5 = 2² x 3 x 5
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 5
Step 3: Multiply the common prime factors 2 x 5 = 10. The Greatest Common Factor of 50 and 60 is 10.
Find the GCF of 50 and 60 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 60 by 50 60 ÷ 50 = 1 (quotient), The remainder is calculated as 60 − (50×1) = 10 The remainder is 10, not zero, so continue the process
Step 2: Now divide the previous divisor (50) by the previous remainder (10) Divide 50 by 10 50 ÷ 10 = 5 (quotient), remainder = 50 − (10×5) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 50 and 60 is 10.
Finding GCF of 50 and 60 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 50 notebooks and 60 pens. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find GCF of 50 and 60 GCF of 50 and 60 2 x 5 = 10. There are 10 equal groups 50 ÷ 10 = 5 60 ÷ 10 = 6 There will be 10 groups, and each group gets 5 notebooks and 6 pens.
As the GCF of 50 and 60 is 10, the teacher can make 10 groups.
Now divide 50 and 60 by 10.
Each group gets 5 notebooks and 6 pens.
A school has 50 red markers and 60 blue markers. They want to arrange them in rows with the same number of markers in each row, using the largest possible number of markers per row. How many markers will be in each row?
GCF of 50 and 60 2 x 5 = 10. So each row will have 10 markers.
There are 50 red and 60 blue markers.
To find the total number of markers in each row, we should find the GCF of 50 and 60.
There will be 10 markers in each row.
A tailor has 50 meters of red fabric and 60 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating longest equal length, we have to calculate the GCF of 50 and 60 The GCF of 50 and 60 2 x 5 = 10. The fabric is 10 meters long.
For calculating the longest length of the fabric first we need to calculate the GCF of 50 and 60 which is 10.
The length of each piece of the fabric will be 10 meters.
A carpenter has two wooden planks, one 50 cm long and the other 60 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 50 and 60 2 x 5 = 10. The longest length of each piece is 10 cm.
To find the longest length of each piece of the two wooden planks, 50 cm and 60 cm, respectively.
We have to find the GCF of 50 and 60, which is 10 cm.
The longest length of each piece is 10 cm.
If the GCF of 50 and ‘b’ is 10, and the LCM is 300. Find ‘b’.
The value of ‘b’ is 60.
GCF x LCM = product of the numbers
10 x 300
= 50 x b 3000
= 50b b
= 3000 ÷ 50 = 60
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.