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Last updated on September 9, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 15 and 28.
The greatest common factor of 15 and 28 is 1. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 15 and 28, a few methods are described below
Steps to find the GCF of 15 and 28 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 15 = 1, 3, 5, 15. Factors of 28 = 1, 2, 4, 7, 14, 28.
Step 2: Now, identify the common factors of them Common factors of 15 and 28: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1. The GCF of 15 and 28 is 1.
To find the GCF of 15 and 28 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 15: 15 = 3 x 5 Prime Factors of 28: 28 = 2 x 2 x 7
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Multiply the common prime factors Since there are no common prime factors, the GCF is 1. The Greatest Common Factor of 15 and 28 is 1.
Find the GCF of 15 and 28 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 28 by 15 28 ÷ 15 = 1 (quotient), The remainder is calculated as 28 − (15×1) = 13 The remainder is 13, not zero, so continue the process
Step 2: Now divide the previous divisor (15) by the previous remainder (13) Divide 15 by 13 15 ÷ 13 = 1 (quotient), remainder = 15 − (13×1) = 2 The remainder is 2, not zero, so continue the process
Step 3: Now divide the previous divisor (13) by the previous remainder (2) Divide 13 by 2 13 ÷ 2 = 6 (quotient), remainder = 13 − (2×6) = 1 The remainder is 1, not zero, so continue the process
Step 4: Now divide the previous divisor (2) by the previous remainder (1) Divide 2 by 1 2 ÷ 1 = 2 (quotient), remainder = 2 − (1×2) = 0 The remainder is zero, the divisor will become the GCF. The GCF of 15 and 28 is 1.
Finding the GCF of 15 and 28 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A farmer has 15 apple trees and 28 orange trees. He wants to plant them in equal groups, with the largest possible number of trees in each group. How many trees will be in each group?
We should find the GCF of 15 and 28 GCF of 15 and 28 is 1. Therefore, each group will have 1 tree.
As the GCF of 15 and 28 is 1, the farmer can only plant one tree in each group.
A baker has 15 loaves of bread and 28 pastries. They want to arrange them on trays with the same number of items on each tray, using the largest possible number of items per tray. How many items will be on each tray?
GCF of 15 and 28 is 1. So each tray will have 1 item.
There are 15 loaves of bread and 28 pastries.
To find the total number of items on each tray, we should find the GCF of 15 and 28.
There will be 1 item on each tray.
A tailor has 15 meters of red fabric and 28 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 15 and 28 The GCF of 15 and 28 is 1. The length of each piece is 1 meter.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 15 and 28, which is 1.
The length of each piece of the fabric will be 1 meter.
A carpenter has two wooden planks, one 15 cm long and the other 28 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 15 and 28 is 1. The longest length of each piece is 1 cm.
To find the longest length of each piece of the two wooden planks, 15 cm and 28 cm, respectively, we have to find the GCF of 15 and 28, which is 1 cm.
The longest length of each piece is 1 cm.
If the GCF of 15 and ‘b’ is 5, and the LCM is 105, find ‘b’.
The value of ‘b’ is 35.
GCF × LCM = product of the numbers
5 × 105
= 15 × b 525
= 15b b
= 525 ÷ 15 = 35
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.