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Last updated on September 9, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 56 and 98.
The greatest common factor of 56 and 98 is 14. The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 56 and 98, a few methods are described below:
Steps to find the GCF of 56 and 98 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 56 = 1, 2, 4, 7, 8, 14, 28, 56. Factors of 98 = 1, 2, 7, 14, 49, 98.
Step 2: Now, identify the common factors of them Common factors of 56 and 98: 1, 2, 7, 14.
Step 3: Choose the largest factor The largest factor that both numbers have is 14. The GCF of 56 and 98 is 14.
To find the GCF of 56 and 98 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 56: 56 = 2 x 2 x 2 x 7 = 2³ x 7 Prime Factors of 98: 98 = 2 x 7 x 7 = 2 x 7²
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 7 = 2¹ x 7¹
Step 3: Multiply the common prime factors 2 x 7 = 14. The Greatest Common Factor of 56 and 98 is 14.
Find the GCF of 56 and 98 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 98 by 56 98 ÷ 56 = 1 (quotient), The remainder is calculated as 98 − (56×1) = 42 The remainder is 42, not zero, so continue the process
Step 2: Now divide the previous divisor (56) by the previous remainder (42) Divide 56 by 42 56 ÷ 42 = 1 (quotient), remainder = 56 − (42×1) = 14 The remainder is 14, not zero, so continue the process
Step 3: Now divide the previous divisor (42) by the previous remainder (14) 42 ÷ 14 = 3 (quotient), remainder = 42 − (14×3) = 0 The remainder is zero, the divisor will become the GCF. The GCF of 56 and 98 is 14.
Finding the GCF of 56 and 98 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A farmer has 56 apples and 98 oranges. He wants to create baskets with the largest number of each fruit in each basket. How many fruits will be in each basket?
We should find the GCF of 56 and 98 GCF of 56 and 98 is 14. There are 14 equal baskets 56 ÷ 14 = 4 98 ÷ 14 = 7 There will be 14 baskets, and each basket gets 4 apples and 7 oranges.
As the GCF of 56 and 98 is 14, the farmer can make 14 baskets.
Now divide 56 and 98 by 14.
Each basket gets 4 apples and 7 oranges.
A concert organizer has 56 chairs and 98 tickets. They want to arrange the chairs in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 56 and 98 is 14. So each row will have 14 chairs.
There are 56 chairs and 98 tickets.
To find the total number of chairs in each row, we should find the GCF of 56 and 98.
There will be 14 chairs in each row.
A tailor has 56 meters of red fabric and 98 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 56 and 98 The GCF of 56 and 98 is 14. Each piece of fabric is 14 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 56 and 98, which is 14.
The length of each piece of fabric will be 14 meters.
A carpenter has two wooden planks, one 56 cm long and the other 98 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 56 and 98 is 14. The longest length of each piece is 14 cm.
To find the longest length of each piece of the two wooden planks, 56 cm and 98 cm, respectively, we have to find the GCF of 56 and 98, which is 14 cm.
The longest length of each piece is 14 cm.
If the GCF of 56 and ‘b’ is 14, and the LCM is 392. Find ‘b’.
The value of ‘b’ is 98.
GCF x LCM = product of the numbers
14 × 392
= 56 × b 5488
= 56b b
= 5488 ÷ 56 = 98
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.