Summarize this article:
Last updated on September 26, 2025
The radius of curvature is a measure of the degree of curvature at a particular point on a curve. It is essential in fields such as physics and engineering to understand the bending of paths. In this topic, we will learn the formula for the radius of curvature.
The radius of curvature is used to describe the bending of a curve at a specific point. Let’s learn the formula to calculate the radius of curvature.
The radius of curvature ( R ) at a point on a curve is given by the formula:
[ R = frac{(1 + (frac{dy}{dx})2){3/2}}{left|frac{d2y}{dx2}right|} ]
where (frac{dy}{dx}) is the first derivative, and (frac{d2y}{dx2}) is the second derivative of the curve.
In math and real life, we use the radius of curvature formula to analyze and understand the curvature of paths.
Here are some important aspects of the radius of curvature:
Students may find the radius of curvature formula tricky.
Here are some tips and tricks to master it:
In real life, the radius of curvature plays a major role in understanding and designing various systems.
Here are some applications:
Students make errors when calculating the radius of curvature.
Here are some mistakes and the ways to avoid them.
Find the radius of curvature for the curve \( y = x^2 \) at point \( x = 1 \).
The radius of curvature is \( R = \frac{\sqrt{5}}{2} \).
First, find the first derivative: (frac{dy}{dx} = 2x).
Second derivative: (frac{d2y}{dx2} = 2).
At ( x = 1 ), (frac{dy}{dx} = 2)
and (frac{d2y}{dx2} = 2).
So, ( R = frac{(1 + (2)2){3/2}}{left|2right|} = frac{sqrt{5}}{2} ).
Calculate the radius of curvature for the curve \( y = \sin(x) \) at \( x = \frac{\pi}{4} \).
The radius of curvature is \( R = 2\sqrt{2} \).
First, find the first derivative: (frac{dy}{dx} = cos(x)).
Second derivative: (frac{d2y}{dx2} = -sin(x)).
At ( x = frac{pi}{4} ), (frac{dy}{dx}
= frac{sqrt{2}}{2}) and (frac{d2y}{dx2}
= -frac{sqrt{2}}{2}).
So, ( R = frac{(1 + (frac{sqrt{2}}{2})2){3/2}}{left|-frac{sqrt{2}}{2}right|}
= 2sqrt{2} ).
Determine the radius of curvature for the curve \( y = \ln(x) \) at \( x = 1 \).
The radius of curvature is \( R = 2 \).
First, find the first derivative: (frac{dy}{dx} = frac{1}{x}).
Second derivative: (frac{d2y}{dx2} = -frac{1}{x2}).
At ( x = 1 ), (frac{dy}{dx} = 1) and (frac{d2y}{dx2} = -1).
So, ( R = frac{(1 + (1)2){3/2}}{left|-1right|} = 2 ).
Find the radius of curvature for the curve \( y = \cos(x) \) at \( x = 0 \).
The radius of curvature is \( R = 1 \).
First, find the first derivative: (frac{dy}{dx} = - sin(x)).
Second derivative: (frac{d2y}{dx2} = -cos(x)).
At ( x = 0 ), (frac{dy}{dx} = 0) and (frac{d2y}{dx2} = -1).
So, ( R = frac{(1 + (0)2){3/2}}{left|-1right|} = 1 ).
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.