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Last updated on September 25, 2025
In trigonometry, product-to-sum formulas are used to simplify or transform trigonometric expressions. These formulas convert products of trigonometric functions into sums or differences. In this topic, we will learn the formulas for product-to-sum identities.
The product-to-sum formulas are a set of identities in trigonometry that help convert products of sines and cosines into sums or differences. Let’s learn these formulas for trigonometric simplifications.
The product-to-sum formulas are used to simplify trigonometric expressions by expressing products as sums or differences.
The main product-to-sum formulas are: 1. \( \sin A \cdot \sin B = \frac{1}{2} [\cos(A-B) - \cos(A+B)] \) 2. \( \cos A \cdot \cos B = \frac{1}{2} [\cos(A-B) + \cos(A+B)] \) 3. \( \sin A \cdot \cos B = \frac{1}{2} [\sin(A+B) + \sin(A-B)] \)
In trigonometry and other mathematical applications, product-to-sum formulas are essential for simplifying expressions and solving equations.
They are important for:
Students often find product-to-sum formulas tricky and confusing.
Here are some tips and tricks to master these formulas:
Product-to-sum formulas have several real-life applications where simplification of trigonometric expressions is required:
Students make errors when using product-to-sum formulas. Here are some common mistakes and ways to avoid them:
Simplify the expression \( \sin 30^\circ \cdot \sin 45^\circ \) using product-to-sum formulas.
The simplified expression is \( \frac{1}{2} [\cos(15^\circ) - \cos(75^\circ)] \)
Using the formula \( \sin A \cdot \sin B = \frac{1}{2} [\cos(A-B) - \cos(A+B)] \):
\( \sin 30^\circ \cdot \sin 45^\circ = \frac{1}{2} [\cos(30^\circ - 45^\circ) - \cos(30^\circ + 45^\circ)] \) = \( \frac{1}{2} [\cos(-15^\circ) - \cos(75^\circ)] \)
Since \( \cos(-15^\circ) = \cos(15^\circ) \), the result is \( \frac{1}{2} [\cos(15^\circ) - \cos(75^\circ)] \).
Express \( \cos 60^\circ \cdot \cos 90^\circ \) as a sum using the product-to-sum formulas.
The expression is \( \frac{1}{2} [\cos(-30^\circ) + \cos(150^\circ)] \)
Using the formula \( \cos A \cdot \cos B = \frac{1}{2} [\cos(A-B) + \cos(A+B)] \):
\( \cos 60^\circ \cdot \cos 90^\circ = \frac{1}{2} [\cos(60^\circ - 90^\circ) + \cos(60^\circ + 90^\circ)] \) = \( \frac{1}{2} [\cos(-30^\circ) + \cos(150^\circ)] \).
Convert \( \sin 45^\circ \cdot \cos 60^\circ \) to a sum using product-to-sum formulas.
The converted expression is \( \frac{1}{2} [\sin(105^\circ) + \sin(-15^\circ)] \)
Using the formula \( \sin A \cdot \cos B = \frac{1}{2} [\sin(A+B) + \sin(A-B)] \):
\( \sin 45^\circ \cdot \cos 60^\circ = \frac{1}{2} [\sin(45^\circ + 60^\circ) + \sin(45^\circ - 60^\circ)] \) = \( \frac{1}{2} [\sin(105^\circ) + \sin(-15^\circ)] \).
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