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Last updated on September 19, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items and schedule events. In this topic, we will learn about the GCF of 80 and 45.
The greatest common factor of 80 and 45 is 5. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 80 and 45, a few methods are described below
Steps to find the GCF of 80 and 45 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 80 = 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.
Factors of 45 = 1, 3, 5, 9, 15, 45.
Step 2: Now, identify the common factors of them Common factors of 80 and 45: 1, 5.
Step 3: Choose the largest factor The largest factor that both numbers have is 5.
The GCF of 80 and 45 is 5.
To find the GCF of 80 and 45 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 80: 80 = 2 × 2 × 2 × 2 × 5 = 24 × 5
Prime Factors of 45: 45 = 3 × 3 × 5 = 32 × 5
Step 2: Now, identify the common prime factors The common prime factor is: 5
Step 3: Multiply the common prime factors
The Greatest Common Factor of 80 and 45 is 5.
Find the GCF of 80 and 45 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 80 by 45 80 ÷ 45 = 1 (quotient),
The remainder is calculated as 80 − (45×1) = 35 The remainder is 35, not zero, so continue the process
Step 2: Now divide the previous divisor (45) by the previous remainder (35)
Divide 45 by 35 45 ÷ 35 = 1 (quotient), remainder = 45 − (35×1) = 10
Step 3: Now divide the previous divisor (35) by the previous remainder (10)
Divide 35 by 10 35 ÷ 10 = 3 (quotient), remainder = 35 − (10×3) = 5
Step 4: Now divide the previous divisor (10) by the previous remainder (5)
Divide 10 by 5 10 ÷ 5 = 2 (quotient), remainder = 10 − (5×2) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 80 and 45 is 5.
Finding the GCF of 80 and 45 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 80 tulip bulbs and 45 daffodil bulbs. She wants to plant them in groups with the largest number of bulbs in each group. How many bulbs will be in each group?
We should find the GCF of 80 and 45. The GCF of 80 and 45 is 5.
There are 5 equal groups. 80 ÷ 5 = 16 45 ÷ 5 = 9
There will be 5 groups, and each group gets 16 tulip bulbs and 9 daffodil bulbs.
As the GCF of 80 and 45 is 5, the gardener can make 5 groups.
Now divide 80 and 45 by 5.
Each group gets 16 tulip bulbs and 9 daffodil bulbs.
A chef has 80 apples and 45 oranges. He wants to create fruit baskets with the same number of fruits in each basket, using the largest possible number of fruits per basket. How many fruits will be in each basket?
The GCF of 80 and 45 is 5.
So each basket will have 5 fruits.
There are 80 apples and 45 oranges.
To find the total number of fruits in each basket, we should find the GCF of 80 and 45.
There will be 5 fruits in each basket.
A tailor has 80 meters of silk ribbon and 45 meters of lace ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 80 and 45.
The GCF of 80 and 45 is 5.
The ribbon is 5 meters long.
For calculating the longest length of the ribbon first we need to calculate the GCF of 80 and 45, which is 5.
The length of each piece of the ribbon will be 5 meters.
A carpenter has two wooden planks, one 80 cm long and the other 45 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood.
The GCF of 80 and 45 is 5.
The longest length of each piece is 5 cm.
To find the longest length of each piece of the two wooden planks, 80 cm and 45 cm, respectively, we have to find the GCF of 80 and 45, which is 5 cm.
The longest length of each piece is 5 cm.
If the GCF of 80 and ‘a’ is 5, and the LCM is 720. Find ‘a’.
The value of ‘a’ is 45.
GCF × LCM = product of the numbers
5 × 720 = 80 × a
3600 = 80a
a = 3600 ÷ 80 = 45
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.