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Last updated on September 19, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 60 and 16.
The greatest common factor of 60 and 16 is 4. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 60 and 16, a few methods are described below
Steps to find the GCF of 60 and 16 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Factors of 16 = 1, 2, 4, 8, 16.
Step 2: Now, identify the common factors of them Common factors of 60 and 16: 1, 2, 4.
Step 3: Choose the largest factor The largest factor that both numbers have is 4.
The GCF of 60 and 16 is 4.
To find the GCF of 60 and 16 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 60: 60 = 2 x 2 x 3 x 5 = 2² x 3 x 5
Prime Factors of 16: 16 = 2 x 2 x 2 x 2 = 2⁴
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 2 = 2²
Step 3: Multiply the common prime factors 2² = 4.
The Greatest Common Factor of 60 and 16 is 4.
Find the GCF of 60 and 16 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 60 by 16 60 ÷ 16 = 3 (quotient),
The remainder is calculated as 60 - (16 x 3) = 12 The remainder is 12, not zero, so continue the process
Step 2: Now divide the previous divisor (16) by the previous remainder (12)
Divide 16 by 12 16 ÷ 12 = 1 (quotient), remainder = 16 - (12 x 1) = 4
The remainder is 4, not zero, so continue the process
Step 3: Now divide the previous divisor (12) by the previous remainder (4)
Divide 12 by 4 12 ÷ 4 = 3 (quotient), remainder = 12 - (4 x 3) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 60 and 16 is 4.
Finding GCF of 60 and 16 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A chef has 60 apples and 16 oranges. She wants to create fruit baskets with the largest number of items in each basket. How many items will be in each basket?
We should find the GCF of 60 and 16. GCF of 60 and 16 2² = 4.
There are 4 equal groups. 60 ÷ 4 = 15 16 ÷ 4 = 4
There will be 4 groups, and each group gets 15 apples and 4 oranges.
As the GCF of 60 and 16 is 4, the chef can make 4 groups.
Now divide 60 and 16 by 4.
Each group gets 15 apples and 4 oranges.
A company has 60 desktops and 16 laptops. They want to arrange them in rows with the same number of devices in each row, using the largest possible number of devices per row. How many devices will be in each row?
GCF of 60 and 16 2² = 4.
So each row will have 4 devices.
There are 60 desktops and 16 laptops.
To find the total number of devices in each row, we should find the GCF of 60 and 16.
There will be 4 devices in each row.
A seamstress has 60 meters of silk fabric and 16 meters of cotton fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 60 and 16.
The GCF of 60 and 16 2² = 4.
The fabric is 4 meters long.
For calculating the longest length of the fabric, first we need to calculate the GCF of 60 and 16, which is 4.
The length of each piece of the fabric will be 4 meters.
A gardener has two hoses, one 60 meters long and the other 16 meters long. He wants to cut them into the longest possible equal pieces, without any hose left over. What should be the length of each piece?
The gardener needs the longest piece of hose.
GCF of 60 and 16 2² = 4.
The longest length of each piece is 4 meters.
To find the longest length of each piece of the two hoses, 60 meters and 16 meters, respectively, we have to find the GCF of 60 and 16, which is 4 meters.
The longest length of each piece is 4 meters.
If the GCF of 60 and ‘b’ is 4, and the LCM is 240, find ‘b’.
The value of ‘b’ is 16.
GCF x LCM = product of the numbers
4 x 240 = 60 x b
960 = 60b
b = 960 ÷ 60 = 16
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.