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Last updated on September 20, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 36 and 51.
The greatest common factor of 36 and 51 is 3. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 36 and 51, a few methods are described below
Steps to find the GCF of 36 and 51 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18, 36.
Factors of 51 = 1, 3, 17, 51.
Step 2: Now, identify the common factors of them Common factors of 36 and 51: 1, 3.
Step 3: Choose the largest factor The largest factor that both numbers have is 3.
The GCF of 36 and 51 is 3.
To find the GCF of 36 and 51 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 36: 36 = 2 x 2 x 3 x 3 = 22 x 32
Prime Factors of 51: 51 = 3 x 17
Step 2: Now, identify the common prime factors The common prime factor is: 3
Step 3: Multiply the common prime factor 3 = 3.
The Greatest Common Factor of 36 and 51 is 3.
Find the GCF of 36 and 51 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 51 by 36 51 ÷ 36 = 1 (quotient),
The remainder is calculated as 51 − (36×1) = 15
The remainder is 15, not zero, so continue the process
Step 2: Now divide the previous divisor (36) by the previous remainder (15)
Divide 36 by 15 36 ÷ 15 = 2 (quotient), remainder = 36 − (15×2) = 6
Step 3: Now divide the previous divisor (15) by the previous remainder (6)
Divide 15 by 6 15 ÷ 6 = 2 (quotient), remainder = 15 − (6×2) = 3
Step 4: Now divide the previous divisor (6) by the previous remainder (3)
Divide 6 by 3 6 ÷ 3 = 2 (quotient), remainder = 6 − (3×2) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 36 and 51 is 3.
Finding the GCF of 36 and 51 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A library has 36 fiction books and 51 nonfiction books. They want to organize them into the largest possible groups with the same number of books in each. How many books will be in each group?
We should find the GCF of 36 and 51 GCF of 36 and 51 3
There are 3 equal groups 36 ÷ 3 = 12 51 ÷ 3 = 17
There will be 3 groups, and each group gets 12 fiction books and 17 nonfiction books.
As the GCF of 36 and 51 is 3, the library can make 3 groups.
\Now divide 36 and 51 by 3.
Each group gets 12 fiction books and 17 nonfiction books.
A conference has 36 chairs for panelists and 51 chairs for attendees. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 36 and 51 3 So each row will have 3 chairs.
There are 36 chairs for panelists and 51 chairs for attendees.
To find the total number of chairs in each row, we should find the GCF of 36 and 51.
There will be 3 chairs in each row.
A gardener has 36 roses and 51 tulips. She wants to plant them in rows with the same number of flowers in each row, using the longest possible row. How many flowers should be in each row?
For calculating the longest equal length, we have to calculate the GCF of 36 and 51
The GCF of 36 and 51 3
The length of each row is 3 flowers.
For calculating the longest row of flowers, first, we need to calculate the GCF of 36 and 51, which is 3.
The length of each row of flowers will be 3.
A carpenter has two wooden planks, one 36 cm long and the other 51 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 36 and 51 3
The longest length of each piece is 3 cm.
To find the longest length of each piece of the two wooden planks, 36 cm and 51 cm, respectively, we have to find the GCF of 36 and 51, which is 3 cm.
The longest length of each piece is 3 cm.
If the GCF of 36 and ‘b’ is 3, and the LCM is 612, find ‘b’.
The value of ‘b’ is 51.
GCF x LCM = product of the numbers
3 × 612 = 36 × b
1836 = 36b
b = 1836 ÷ 36 = 51
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.