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104 LearnersLast updated on September 20, 2025
GCF of 25 and 14
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 25 and 14.
What is the GCF of 25 and 14?
The greatest common factor of 25 and 14 is 1. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
How to find the GCF of 25 and 14?
To find the GCF of 25 and 14, a few methods are described below
- Listing Factors
- Prime Factorization
- Long Division Method / by Euclidean Algorithm
GCF of 25 and 14 by Using Listing of Factors
Steps to find the GCF of 25 and 14 using the listing of factors:
Step 1: Firstly, list the factors of each number
Factors of 25 = 1, 5, 25.
Factors of 14 = 1, 2, 7, 14.
Step 2: Now, identify the common factors of them Common factor of 25 and 14: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1.
The GCF of 25 and 14 is 1.
GCF of 25 and 14 Using Prime Factorization
To find the GCF of 25 and 14 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 25: 25 = 5 x 5 = 5²
Prime Factors of 14: 14 = 2 x 7
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: The GCF is the product of the common prime factors Since there are no common prime factors, the GCF is 1.
The Greatest Common Factor of 25 and 14 is 1.
GCF of 25 and 14 Using Division Method or Euclidean Algorithm Method
Find the GCF of 25 and 14 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 25 by 14 25 ÷ 14 = 1 (quotient),
The remainder is calculated as 25 − (14×1) = 11
The remainder is 11, not zero, so continue the process
Step 2: Now divide the previous divisor (14) by the previous remainder (11)
Divide 14 by 11 14 ÷ 11 = 1 (quotient), remainder = 14 − (11×1) = 3
Step 3: Divide the previous divisor (11) by the new remainder (3) 11 ÷ 3 = 3 (quotient), remainder = 11 − (3×3) = 2
Step 4: Divide 3 by 2 3 ÷ 2 = 1 (quotient), remainder = 3 − (2×1) = 1
Step 5: Divide 2 by 1 2 ÷ 1 = 2 (quotient), remainder = 2 − (1×2) = 0
The remainder is zero, so the divisor will become the GCF.
The GCF of 25 and 14 is 1.
Common Mistakes and How to Avoid Them in GCF of 25 and 14
Finding the GCF of 25 and 14 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
Mistake 1
Listing Incorrect Factors
Students may sometimes list incorrect factors.
For example, while listing factors of 14, students may mention 10, which is incorrect. To avoid this, students should carefully divide the number and list the factors correctly.
Mistake 2
Choosing the wrong common factor
Students may sometimes select the smallest common factor instead of the largest one. To avoid this confusion, students should list all the common factors and find the greatest one.
Mistake 3
Forgetting to include 1 as a factor
Sometimes students may forget 1 as a common factor of the numbers. However, it does not affect the GCF, but it indicates incomplete understanding of the factors. Students should include 1 as a factor.
Mistake 4
Using Multiples instead of factors
Students confuse between factors and multiples. In that confusion, sometimes they may write multiples instead of factors. To avoid this confusion, students should know the definitions of multiples and factors clearly.
Mistake 5
Assuming GCF is always an even number
Students may assume that the GCF of two numbers will always be an even number. But it's not true; a GCF can also be an odd number. To avoid this, students should focus on common factors rather than focusing on even and odd numbers.
Greatest Common Factor of 25 and 14 Examples
Problem 1
A teacher has 25 apples and 14 oranges. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 25 and 14 The GCF of 25 and 14 is 1.
There are 1 equal groups 25 ÷ 1 = 25 14 ÷ 1 = 14
There will be 1 group, and each group gets 25 apples and 14 oranges.
Explanation
As the GCF of 25 and 14 is 1, the teacher can make 1 group.
Now divide 25 and 14 by 1.
Each group gets 25 apples and 14 oranges.
Problem 2
A school has 25 red chairs and 14 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
The GCF of 25 and 14 is 1.
So each row will have 1 chair.
Explanation
There are 25 red and 14 blue chairs.
To find the total number of chairs in each row, we should find the GCF of 25 and 14.
There will be 1 chair in each row.
Problem 3
A tailor has 25 meters of red ribbon and 14 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 25 and 14
The GCF of 25 and 14 is 1.
The ribbon is 1 meter long.
Explanation
For calculating the longest length of the ribbon first we need to calculate the GCF of 25 and 14 which is 1.
The length of each piece of the ribbon will be 1 meter.
Problem 4
A carpenter has two wooden planks, one 25 cm long and the other 14 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood
The GCF of 25 and 14 is 1.
The longest length of each piece is 1 cm.
Explanation
To find the longest length of each piece of the two wooden planks, 25 cm and 14 cm, respectively, we have to find the GCF of 25 and 14, which is 1 cm.
The longest length of each piece is 1 cm.
Problem 5
If the GCF of 25 and ‘a’ is 1, and the LCM is 350, find ‘a’.
The value of ‘a’ is 14.
Explanation
GCF x LCM = product of the numbers
1 × 350 = 25 × a
350 = 25a
a = 350 ÷ 25 = 14
FAQs on the Greatest Common Factor of 25 and 14
1.What is the LCM of 25 and 14?
2.Is 25 divisible by 5?
3.What will be the GCF of any two prime numbers?
4.What is the prime factorization of 14?
5.Are 25 and 14 prime numbers?
Important Glossaries for GCF of 25 and 14
- Factors: Factors are numbers that divide the target number completely. For example, the factors of 14 are 1, 2, 7, and 14.
- Multiple: Multiples are the products we get by multiplying a given number by another. For example, the multiples of 5 are 5, 10, 15, 20, and so on.
- Prime Factors: These are the factors of a number that are prime numbers and divide the given number completely. For example, the prime factors of 25 are 5 and 5.
- Remainder: The value left after division when the number cannot be divided evenly. For example, when 14 is divided by 5, the remainder is 4 and the quotient is 2.
- LCM: The smallest common multiple of two or more numbers is termed LCM. For example, the LCM of 25 and 14 is 350.
- GCF: The largest factor that commonly divides two or more numbers. For example, the GCF of 25 and 14 is 1, as it is their largest common factor that divides the numbers completely.
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Hiralee Lalitkumar Makwana
About the Author
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
Fun Fact
: She loves to read number jokes and games.
