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104 LearnersLast updated on October 7, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 18 and 5.
The greatest common factor of 18 and 5 is 1.
The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 18 and 5, a few methods are described below -
Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm
Steps to find the GCF of 18 and 5 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 18 = 1, 2, 3, 6, 9, 18. Factors of 5 = 1, 5.
Step 2: Now, identify the common factors of them Common factor of 18 and 5: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1.
The GCF of 18 and 5 is 1.
To find the GCF of 18 and 5 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime factors of 18: 18 = 2 x 3 x 3 = 2 x 3² Prime factors of 5: 5 = 5.
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Since there are no common prime factors, the GCF is 1.
Find the GCF of 18 and 5 using the division method or Euclidean Algorithm Method.
Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 18 by 5 18 ÷ 5 = 3 (quotient), The remainder is calculated as 18 − (5×3) = 3 The remainder is 3, not zero, so continue the process.
Step 2: Now divide the previous divisor (5) by the previous remainder (3) Divide 5 by 3 5 ÷ 3 = 1 (quotient), remainder = 5 − (3×1) = 2.
Step 3: Now divide the previous divisor (3) by the previous remainder (2) Divide 3 by 2 3 ÷ 2 = 1 (quotient), remainder = 3 − (2×1) = 1.
Step 4: Now divide the previous divisor (2) by the previous remainder (1) Divide 2 by 1 2 ÷ 1 = 2 (quotient), remainder = 2 − (1×2) = 0, The remainder is zero; the divisor will become the GCF.
The GCF of 18 and 5 is 1.
Finding the GCF of 18 and 5 looks simple, but students often make mistakes while calculating the GCF.
Here are some common mistakes to be avoided by the students.
A gardener has 18 roses and 5 lilies. She wants to group them into equal sets with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 18 and 5. GCF of 18 and 5 is 1.
There will be 1 group, and each group gets 18 roses and 5 lilies.
As the GCF of 18 and 5 is 1, the gardener can make only 1 group.
This means all 18 roses and 5 lilies will be in one group.
A chef has 18 apples and 5 oranges. He wants to arrange them in rows with the same number of fruits in each row, using the largest possible number of fruits per row. How many fruits will be in each row?
GCF of 18 and 5 is 1.
So each row will have 1 fruit.
There are 18 apples and 5 oranges.
To find the total number of fruits in each row, we should find the GCF of 18 and 5.
There will be 1 fruit in each row.
A jeweler has 18 grams of gold and 5 grams of silver. She wants to split both into pieces of equal weight, using the longest possible length. What should be the weight of each piece?
For calculating the longest equal weight, we have to calculate the GCF of 18 and 5.
The GCF of 18 and 5 is 1.
The weight of each piece is 1 gram.
For calculating the longest weight of the pieces, first, we need to calculate the GCF of 18 and 5, which is 1.
The weight of each piece will be 1 gram.
A construction worker has two metal rods, one 18 cm long and the other 5 cm long. He wants to cut them into the longest possible equal pieces, without any metal left over. What should be the length of each piece?
The worker needs the longest piece of metal. GCF of 18 and 5 is 1.
The longest length of each piece is 1 cm.
To find the longest length of each piece of the two metal rods, 18 cm and 5 cm, respectively, we have to find the GCF of 18 and 5, which is 1 cm.
The longest length of each piece is 1 cm.
If the GCF of 18 and 'b' is 1, and the LCM is 90, find 'b'.
The value of 'b' is 5.
GCF x LCM = product of the numbers 1 × 90 = 18 × b 90 = 18b b = 90 ÷ 18 = 5
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






