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104 LearnersLast updated on October 7, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 4 and 15.
The greatest common factor of 4 and 15 is 1.
The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 4 and 15, a few methods are described below -
Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm
Steps to find the GCF of 4 and 15 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 4 = 1, 2, 4. Factors of 15 = 1, 3, 5, 15.
Step 2: Now, identify the common factors of them Common factors of 4 and 15: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1.
The GCF of 4 and 15 is 1.
To find the GCF of 4 and 15 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 4: 4 = 2 x 2 = 2² Prime Factors of 15: 15 = 3 x 5.
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Since there are no common prime factors, the GCF is 1.
Find the GCF of 4 and 15 using the division method or Euclidean Algorithm Method.
Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 15 by 4 15 ÷ 4 = 3 (quotient), The remainder is calculated as 15 − (4×3) = 3 The remainder is 3, not zero, so continue the process.
Step 2: Now divide the previous divisor (4) by the previous remainder (3) Divide 4 by 3 4 ÷ 3 = 1 (quotient), remainder = 4 − (3×1) = 1.
Step 3: Now divide the previous divisor (3) by the previous remainder (1) Divide 3 by 1 3 ÷ 1 = 3 (quotient), remainder = 3 − (1×3) = 0 The remainder is zero, so the divisor will become the GCF.
The GCF of 4 and 15 is 1.
Finding the GCF of 4 and 15 looks simple, but students often make mistakes while calculating the GCF.
Here are some common mistakes to be avoided by the students.
A teacher has 4 books and 15 notebooks. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 4 and 15 The GCF of 4 and 15 is 1.
There are 1 equal group. 4 ÷ 1 = 4 15 ÷ 1 = 15.
There will be 1 group, and each group gets 4 books and 15 notebooks.
As the GCF of 4 and 15 is 1, the teacher can make 1 group.
Now divide 4 and 15 by 1.
Each group gets 4 books and 15 notebooks.
A school has 4 soccer balls and 15 basketballs. They want to arrange them in rows with the same number of balls in each row, using the largest possible number of balls per row. How many balls will be in each row?
The GCF of 4 and 15 is 1.
So each row will have 1 ball.
There are 4 soccer balls and 15 basketballs.
To find the total number of balls in each row, we should find the GCF of 4 and 15.
There will be 1 ball in each row.
A tailor has 4 meters of blue fabric and 15 meters of red fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 4 and 15 The GCF of 4 and 15 is 1.
The fabric is 1 meter long.
For calculating the longest length of the fabric, first we need to calculate the GCF of 4 and 15, which is 1.
The length of each piece of the fabric will be 1 meter.
A carpenter has two wooden planks, one 4 cm long and the other 15 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood The GCF of 4 and 15 is 1.
The longest length of each piece is 1 cm.
To find the longest length of each piece of the two wooden planks, 4 cm and 15 cm, respectively, we have to find the GCF of 4 and 15, which is 1 cm.
The longest length of each piece is 1 cm.
If the GCF of 4 and ‘a’ is 1, and the LCM is 60, find ‘a’.
The value of ‘a’ is 15.
GCF x LCM = product of the numbers 1 × 60 = 4 × a 60 = 4a a = 60 ÷ 4 = 15
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






