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Last updated on October 8, 2025

Derivative of -xy

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We use the derivative of -xy to understand how the product of x and y changes in response to a slight change in either variable. Derivatives help us calculate optimal solutions in various real-life situations. We will now discuss the derivative of -xy in detail.

Derivative of -xy for US Students
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What is the Derivative of -xy?

Let's explore the derivative of -xy. It is commonly represented as d/dx (-xy) or (-xy)', and its value depends on whether x or y is being differentiated.

 

If x is the variable, the derivative is -y. The function -xy has a clearly defined derivative, indicating it is differentiable within its domain.

 

The key concepts are mentioned below: Product Function: (-xy) Product Rule: Rule for differentiating -xy. Partial Derivatives: Derivatives concerning one variable while holding others constant.

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Derivative of -xy Formula

The derivative of -xy can be denoted as d/dx (-xy) or (-xy)'. The formula we use depends on the context: d/dx (-xy) = -y if x is the variable, or d/dy (-xy) = -x if y is the variable.

 

The formula applies to all x and y within their respective domains.

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Proofs of the Derivative of -xy

We can derive the derivative of -xy using various rules. To illustrate, we will use differentiation rules like the product rule.

 

There are several methods we use to prove this, such as:

 

  • Using the Product Rule
     
  • Using Partial Derivatives

 

Using the Product Rule

 

To prove the differentiation of -xy using the product rule: Consider f(x, y) = -xy. Using the product rule: d/dx [u * v] = u' * v + u * v', Let u = -x and v = y. The derivative with respect to x is: d/dx (-xy) = (-1) * y + (-x) * 0 = -y. Thus, d/dx (-xy) = -y.

 

Using Partial Derivatives

 

When y is a constant, the derivative of -xy with respect to x is -y. When x is a constant, the derivative of -xy with respect to y is -x.

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Higher-Order Derivatives of -xy

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be complex.

 

To understand them better, consider a scenario where a change in the product affects the rate of change. Higher-order derivatives provide deeper insights into functions like -xy. For the first derivative of a function, we write f′(x), which indicates how the function changes.

 

The second derivative is derived from the first derivative, denoted as f′′(x). This pattern continues for higher-order derivatives, denoted as fⁿ(x).

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Special Cases

When x or y equals zero, the derivative simplifies significantly as the product becomes zero. When both x and y are constants, the derivative is zero because there is no change.

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Common Mistakes and How to Avoid Them in Derivatives of -xy

Students frequently make mistakes when differentiating -xy. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Ignoring Variable Context

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Students may forget to consider whether x or y is the variable of interest, leading to incorrect results.

 

Always define which variable is being differentiated and apply the derivative accordingly.

Mistake 2

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Misapplying the Product Rule

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They might not properly apply the product rule to -xy.

 

Ensure you correctly apply the rule to obtain the correct derivative, noting which variable is held constant.

Mistake 3

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Confusion with Partial Derivatives

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While differentiating functions like -xy, students may confuse partial derivatives with total derivatives.

 

Understand that partial derivatives involve holding one variable constant.

Mistake 4

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Overlooking Zero Derivatives

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Students sometimes overlook cases where the derivative should be zero, such as when the variable is not present in the expression.

Mistake 5

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Not Simplifying Results

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Students might forget to simplify the derivative expression, leading to unnecessary complexity.

 

Always simplify the result for clarity.

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Examples Using the Derivative of -xy

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Problem 1

Calculate the derivative of (-2x * y) with respect to x.

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Here, we have f(x, y) = -2x * y. Using the product rule, f'(x) = u′v + uv′. In the given equation, u = -2x and v = y. Let’s differentiate each term: u′ = d/dx (-2x) = -2, v′ = d/dx (y) = 0. Substituting into the given equation, f'(x) = (-2) * y + (-2x) * 0 = -2y. Thus, the derivative of the specified function with respect to x is -2y.

Explanation

We find the derivative of the given function by treating y as a constant and applying the product rule to -2x and y.

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Problem 2

A company tracks the interaction between two dependent variables, sales (x) and marketing spend (y), modeled by the function z = -xy. Find the rate of change of z concerning marketing spend when sales are constant at 100 units.

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We have z = -xy. Now, differentiate the equation concerning y: dz/dy = -x. Given x = 100, substitute this into the derivative: dz/dy = -100. Hence, the rate of change of z concerning marketing spend is -100 when sales are constant at 100 units.

Explanation

In this scenario, we find the rate of change by treating sales as a constant and differentiating the function -xy concerning marketing spend (y).

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Problem 3

Derive the second derivative of the function z = -xy with respect to x.

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The first step is to find the first derivative: dz/dx = -y. Now, differentiate the first derivative concerning x to get the second derivative: d²z/dx² = d/dx (-y). As y is treated as a constant with respect to x: d²z/dx² = 0. Therefore, the second derivative of the function z = -xy with respect to x is 0.

Explanation

We start with the first derivative and differentiate it concerning x again, treating y as a constant, resulting in a second derivative of 0.

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Problem 4

Prove: d/dy (-x²y) = -x².

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Consider z = -x²y. To differentiate with respect to y: dz/dy = -x² * d/dy (y). Since d/dy (y) = 1: dz/dy = -x² * 1 = -x². Hence, proved.

Explanation

In this step-by-step process, we differentiate concerning y, treating x as a constant, to arrive at the derivative -x².

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Problem 5

Solve: d/dx (-xy/x).

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To differentiate the function, simplify first: z = -y (since -xy/x = -y). The derivative concerning x is: dz/dx = 0, as y is constant. Therefore, d/dx (-xy/x) = 0.

Explanation

In this process, we simplify the expression, noting that it reduces to -y, and then differentiate concerning x, resulting in 0.

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FAQs on the Derivative of -xy

1.Find the derivative of -xy concerning x.

When differentiating -xy concerning x, we treat y as a constant: d/dx (-xy) = -y.

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2.Can we use the derivative of -xy in real life?

Yes, the derivative of -xy can be used in real-life scenarios to understand the interaction between two changing variables in fields like economics and physics.

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3.Is it possible to take the derivative of -xy when x = 0?

Yes, the derivative with respect to x is -y, which is still valid even when x = 0.

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4.What rule is used to differentiate -xy/x?

When simplifying -xy/x to -y, the derivative concerning x is 0 since it becomes a constant.

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5.Are the derivatives of -xy and xy the same?

No, they differ by a sign. The derivative of -xy with respect to x is -y, whereas for xy, it is y.

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Important Glossaries for the Derivative of -xy

  • Derivative: Indicates how a function changes in response to a change in its variables.

 

  • Product Rule: A rule used for differentiating the product of two functions.

 

  • +Partial Derivative: The derivative of a function concerning one variable while holding others constant.

 

  • Constant: A fixed value that does not change.

 

  • Variable: A symbol representing a changeable value in a function. ```
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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