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Last updated on October 8, 2025
We use the derivative of π/x, which is -π/x², as a measuring tool for how the function π/x changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of π/x in detail.
We now understand the derivative of π/x. It is commonly represented as d/dx (π/x) or (π/x)', and its value is -π/x². The function π/x has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Constant Multiple Rule: The derivative of a constant times a function is the constant times the derivative of the function.
Power Rule: Rule for differentiating x raised to a power.
Reciprocal Function: The function 1/x.
The derivative of π/x can be denoted as d/dx (π/x) or (π/x)'. The formula we use to differentiate π/x is: d/dx (π/x) = -π/x² The formula applies to all x where x ≠ 0.
We can derive the derivative of π/x using proofs. To show this, we will use the rules of differentiation, particularly focusing on the constant multiple rule and the power rule.
There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of π/x results in -π/x² using the above-mentioned methods:
The derivative of π/x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of π/x using the first principle, we will consider f(x) = π/x. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)
Given that f(x) = π/x, we write f(x + h) = π/(x + h). Substituting these into equation (1), f'(x) = limₕ→₀ [π/(x + h) - π/x] / h = limₕ→₀ [πx - π(x + h)] / [h(x + h)x] = limₕ→₀ [πx - πx - πh] / [h(x + h)x] = limₕ→₀ -πh / [h(x + h)x] = limₕ→₀ -π / [(x + h)x] = -π/x² Hence, proved.
To prove the differentiation of π/x using the chain rule, We use the formula: π/x = π * (x⁻¹) Hence, using the chain rule: d/dx (π/x) = π * d/dx (x⁻¹) = π * (-1)x⁻² = -π/x²
We will now prove the derivative of π/x using the quotient rule. The step-by-step process is demonstrated below: Here, we use the formula, π/x = π * (1/x) Using the quotient rule formula: d/dx [u/v] = [u'(v) - u(v')]/v² Let u = π, v = x u' = 0 (since π is a constant) v' = 1 d/dx (π/x) = [0(x) - π(1)]/x² = -π/x² Thus, the derivative of π/x is -π/x².
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like π/x.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.
For the nth Derivative of π/x, we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).
When x = 0, the derivative is undefined because π/x has a vertical asymptote there.
When x = 1, the derivative of π/x = -π/1², which is -π.
Students frequently make mistakes when differentiating π/x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of π/x³.
Here, we have f(x) = π/x³. We use the power rule and constant multiple rule: f'(x) = π * d/dx (x⁻³) = π * (-3)x⁻⁴ = -3π/x⁴ Thus, the derivative of the specified function is -3π/x⁴.
We find the derivative of the given function by applying the power rule to x⁻³ and using the constant multiple rule to incorporate π.
ABC Construction is analyzing the rate of change of a material strength function modeled by f(x) = π/x. If x = 2 units, find the rate of change of material strength.
We have f(x) = π/x (material strength function)...(1) Now, we will differentiate the equation (1) Take the derivative π/x: f'(x) = -π/x² Given x = 2 (substitute this into the derivative) f'(2) = -π/2² = -π/4 Hence, the rate of change of material strength at x = 2 units is -π/4.
We find the rate of change of material strength at x = 2 as -π/4, which indicates a decrease of π/4 units per unit increase in x.
Derive the second derivative of the function y = π/x.
The first step is to find the first derivative, dy/dx = -π/x²...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-π/x²] = π * d/dx (x⁻²) = π * (-2)x⁻³ = 2π/x³ Therefore, the second derivative of the function y = π/x is 2π/x³.
We use the step-by-step process, where we start with the first derivative.
Using the power rule, we differentiate x⁻².
We then simplify the terms to find the final answer.
Prove: d/dx (πx⁻²) = -2πx⁻³.
Let’s start using the power rule: Consider y = πx⁻² To differentiate, we use the power rule: dy/dx = π * d/dx (x⁻²) = π * (-2)x⁻³ = -2πx⁻³ Hence proved.
In this step-by-step process, we used the power rule to differentiate the equation.
We replace the derivative of x⁻² and simplify to derive the equation.
Solve: d/dx (πx/x).
To differentiate the function, we simplify: πx/x = π d/dx (π) = 0 Therefore, d/dx (πx/x) = 0.
In this process, we simplify the given function to a constant and differentiate it to obtain the final result of 0.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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