Last updated on May 26th, 2025
The smallest positive integer that divides the numbers with no numbers left behind is the LCM of 56 and 70. Did you know? We apply LCM unknowingly in everyday situations like setting alarms and to synchronize traffic lights and when making music. In this article, let’s now learn to find LCMs of 56 and 70.
We can find the LCM using listing multiples method, prime factorization method and the long division method. These methods are explained here, apply a method that fits your understanding well.
Step 1: List the multiples of each of the numbers;
56 = 56,112,168,224,280,…
70 = 70,140,210,280,…
Step 2: Find the smallest number in both the lists
LCM (56,70) = 280
Step 1: Prime factorize the numbers
56 = 2×2×2×7
70 = 7×5×2
Step 2: find highest powers
Step 3: Multiply the highest powers of the numbers
LCM(56,70) = 280
Listed here are a few mistakes children may make when trying to find the LCM due to confusion or due to unclear understanding. Be mindful, understand, learn and avoid!
Find the missing number. If the LCM of 56 and a certain number is 280, what is the missing number?
We know the formula:
LCM(a, b)=a×b/GCD
Where a=56, the LCM is 280, and we need to find b. The GCD of 56 and 70 is 14 (calculated by the Euclidean algorithm).
Let's solve for b:
LCM(56,b)=280
56×b/GCD(56,b)=280
Assume GCD(56, b) = 1 (we'll check later). Now we solve:
56×b=280
b= 280​/56=5
Thus, the missing number is 5.
Find the GCD of 56 and 5, which is 1. This confirms that the missing number is correct.
If the LCM of two numbers is 280, and the product of the two numbers is 3920, find the GCD of the two numbers.
We know the relationship between LCM, GCD, and the product of two numbers:
LCM(a, b)×GCD(a, b)=a×b
Given:
LCM(a, b)=280 and a×b=3920
Substitute the known values into the formula:
280×GCD(a, b)=3920
Solve for GCD(a, b):
GCD(a,b)=3920/280=14
Thus, the GCD of the two numbers is 14.
Find the smallest positive integer x such that the LCM of 56 and x is 840.
We use the formula for LCM:
LCM(56,x)=56×x/GCD(56,x)=840
Step 1: Prime factorize the numbers.
56=23×71
840=23×31×51×71
Step 2: To have the LCM be 840, x must include at least the prime factors 3 and 5 (since they are in 840 but not in 56).
Therefore, x must include:
x=31×51 =15
Thus, the smallest value of x is 15.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.