Last updated on May 26th, 2025
The smallest positive integer that divides the numbers with no numbers left behind is the LCM of 3,4 and 5. Did you know? We apply LCM unknowingly in everyday situations like setting alarms and to synchronize traffic lights and when making music. In this article, let’s now learn to find LCMs of 3,4 and 5.
We can find the LCM using listing multiples method, prime factorization method and the long division method. These methods are explained here, apply a method that fits your understanding well.
Step 1: List the multiples of each of the numbers;
3 =3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,…60
4= 4,8,12,16,20,…60
5= 5,10,15,20,…60
Step 2:Find the smallest number in both the lists
LCM (3,4,5) = 60
Step 1: Prime factorize the numbers
3 = 3
4 = 2×2
5 = 5
Step 2: find highest powers
Step 3: Multiply the highest powers of the numbers
LCM(3,4,5) = 60
Listed here are a few mistakes children may make when trying to find the LCM due to confusion or due to unclear understanding. Be mindful, understand, learn and avoid!
A number is divisible by both 3 and 4 but not divisible by 5. If the LCM of 3, 4, and another number is 60, what is the missing number?
Since the number is divisible by both 3 and 4, its LCM with these numbers must be divisible by their LCM (which is 12).
However, it should not include a factor of 5.
The number that satisfies this condition is 12, since:
LCM(3, 4, 12) = 60.
The missing number is 12.
If n=LCM(3,4,5), find the number of divisors of n.
First, find the LCM(3, 4, 5) = 60 (already solved).
Now, find the number of divisors of 60. The prime factorization of 60 is:
60=22×3×5
The number of divisors of a number is given by the formula:
Number of divisors=(e1+1)(e2+1)…(ek+1)
where e1, e2, …, ek are the exponents in the prime factorization.
For 60:
Number of divisors=(2+1)(1+1)(1+1)=3×2×2=12
The number of divisors of 60 is 12.
If the GCF of two numbers is 1 and their LCM is 60, what can you say about the numbers if one of them is 4?
Let the two numbers be 4 and x. We are given:
GCF(4,x)=1 and LCM(4,x)=60
Since GCF(4, x) = 1, x must not share any prime factors with 4 (which has the prime factorization 22).
Thus, x must be divisible by 3 and 5 (since 60=22×3×5, and we already accounted for the 22in 4).
Therefore,
x=15x = 15x=15.
The other number is 15.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.