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Last updated on September 10, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 25 and 40.
The greatest common factor of 25 and 40 is 5. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 25 and 40, a few methods are described below -
Steps to find the GCF of 25 and 40 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 25 = 1, 5, 25.
Factors of 40 = 1, 2, 4, 5, 8, 10, 20, 40.
Step 2: Now, identify the common factors of them Common factors of 25 and 40: 1, 5.
Step 3: Choose the largest factor The largest factor that both numbers have is 5. The GCF of 25 and 40 is 5.
To find the GCF of 25 and 40 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 25: 25 = 5 × 5 = 5²
Prime Factors of 40: 40 = 2 × 2 × 2 × 5 = 2³ × 5
Step 2: Now, identify the common prime factors The common prime factor is: 5
Step 3: Multiply the common prime factors 5 = 5. The Greatest Common Factor of 25 and 40 is 5.
Find the GCF of 25 and 40 using the Division Method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 40 by 25 40 ÷ 25 = 1 (quotient), The remainder is calculated as 40 − (25×1) = 15 The remainder is 15, not zero, so continue the process
Step 2: Now divide the previous divisor (25) by the previous remainder (15) Divide 25 by 15 25 ÷ 15 = 1 (quotient), remainder = 25 − (15×1) = 10
Step 3: Divide the previous divisor (15) by the remainder (10) 15 ÷ 10 = 1 (quotient), remainder = 15 − (10×1) = 5
Step 4: Divide the previous divisor (10) by the remainder (5) 10 ÷ 5 = 2 (quotient), remainder = 10 − (5×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 25 and 40 is 5.
Finding the GCF of 25 and 40 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A farmer has 25 apple trees and 40 orange trees. He wants to plant them in rows with the same number of trees in each row, using the largest possible number of trees per row. How many trees will be in each row?
We should find the GCF of 25 and 40 GCF of 25 and 40 5. So, each row will have 5 trees.
As the GCF of 25 and 40 is 5, the farmer can make rows with 5 trees in each.
A chef has 25 kg of flour and 40 kg of sugar. He wants to pack them into bags with the same weight, using the largest possible weight per bag. What should be the weight of each bag?
GCF of 25 and 40 5. So each bag will weigh 5 kg.
To pack the flour and sugar into bags of the same weight, we should find the GCF of 25 and 40. Each bag will weigh 5 kg.
A library has 25 fiction books and 40 non-fiction books. The librarian wants to arrange them in sections with the same number of books in each section, using the largest possible number of books per section. How many books will be in each section?
For calculating the largest number of books per section, we have to calculate the GCF of 25 and 40 The GCF of 25 and 40 5. Each section will have 5 books.
For calculating the largest number of books per section, first, we need to calculate the GCF of 25 and 40, which is 5. Each section will have 5 books.
A woodworker has two wooden planks, one 25 cm long and the other 40 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The woodworker needs the longest piece of wood GCF of 25 and 40 5. The longest length of each piece is 5 cm.
To find the longest length of each piece of the two wooden planks, 25 cm and 40 cm, respectively, we have to find the GCF of 25 and 40, which is 5 cm. The longest length of each piece is 5 cm.
If the GCF of 25 and ‘a’ is 5, and the LCM is 200, find ‘a’.
The value of ‘a’ is 40.
GCF × LCM = product of the numbers 5 × 200 = 25 × a 1000 = 25a a = 1000 ÷ 25 = 40
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.