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Last updated on September 10, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 6 and 27.
The greatest common factor of 6 and 27 is 3. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 6 and 27, a few methods are described below -
Steps to find the GCF of 6 and 27 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 6 = 1, 2, 3, 6.
Factors of 27 = 1, 3, 9, 27.
Step 2: Now, identify the common factors of them Common factors of 6 and 27: 1, 3.
Step 3: Choose the largest factor The largest factor that both numbers have is 3. The GCF of 6 and 27 is 3.
To find the GCF of 6 and 27 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 6: 6 = 2 × 3
Prime Factors of 27: 27 = 3 × 3 × 3
Step 2: Now, identify the common prime factors The common prime factor is: 3
Step 3: Multiply the common prime factors 3 The Greatest Common Factor of 6 and 27 is 3.
Find the GCF of 6 and 27 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 27 by 6 27 ÷ 6 = 4 (quotient), The remainder is calculated as 27 - (6×4) = 3
The remainder is 3, not zero, so continue the process
Step 2: Now divide the previous divisor (6) by the previous remainder (3) Divide 6 by 3 6 ÷ 3 = 2 (quotient), remainder = 6 - (3×2) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 6 and 27 is 3.
Finding GCF of 6 and 27 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A baker has 6 loaves of bread and 27 buns. She wants to package them into equal sets, with the largest number of items in each set. How many items will be in each set?
We should find GCF of 6 and 27 GCF of 6 and 27 is 3. There are 3 equal groups 6 ÷ 3 = 2 27 ÷ 3 = 9
There will be 3 groups, and each group gets 2 loaves of bread and 9 buns.
As the GCF of 6 and 27 is 3, the baker can make 3 groups. Now divide 6 and 27 by 3.
Each group gets 2 loaves of bread and 9 buns.
A gardener has 6 rose plants and 27 tulip plants. They want to arrange them in rows with the same number of plants in each row, using the largest possible number of plants per row. How many plants will be in each row?
GCF of 6 and 27 is 3. So each row will have 3 plants.
There are 6 rose plants and 27 tulip plants. To find the total number of plants in each row, we should find the GCF of 6 and 27. There will be 3 plants in each row.
A tailor has 6 meters of cloth and 27 meters of ribbon. She wants to cut both into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 6 and 27 The GCF of 6 and 27 is 3. The length of each piece is 3 meters.
For calculating the longest length of the cloth and ribbon, first we need to calculate the GCF of 6 and 27, which is 3. The length of each piece will be 3 meters.
A carpenter has two wooden planks, one 6 cm long and the other 27 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 6 and 27 is 3. The longest length of each piece is 3 cm.
To find the longest length of each piece of the two wooden planks, 6 cm and 27 cm, respectively, we have to find the GCF of 6 and 27, which is 3 cm. The longest length of each piece is 3 cm.
If the GCF of 6 and ‘b’ is 3, and the LCM is 54. Find ‘b’.
The value of ‘b’ is 27.
GCF × LCM = product of the numbers
3 × 54 = 6 × b
162 = 6b
b = 162 ÷ 6 = 27
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.