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Last updated on September 10, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, group or arrange items, and schedule events. In this topic, we will learn about the GCF of 21 and 56.
The greatest common factor of 21 and 56 is 7. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 21 and 56, a few methods are described below:
Steps to find the GCF of 21 and 56 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 21 = 1, 3, 7, 21. Factors of 56 = 1, 2, 4, 7, 8, 14, 28, 56.
Step 2: Now, identify the common factors of them Common factors of 21 and 56: 1, 7.
Step 3: Choose the largest factor The largest factor that both numbers have is 7. The GCF of 21 and 56 is 7.
To find the GCF of 21 and 56 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 21: 21 = 3 x 7 Prime Factors of 56: 56 = 2 x 2 x 2 x 7 = 2^3 x 7
Step 2: Now, identify the common prime factor The common prime factor is: 7
Step 3: The GCF is 7. The Greatest Common Factor of 21 and 56 is 7.
Find the GCF of 21 and 56 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 56 by 21 56 ÷ 21 = 2 (quotient), The remainder is calculated as 56 − (21×2) = 14
The remainder is 14, not zero, so continue the process
Step 2: Now divide the previous divisor (21) by the previous remainder (14) Divide 21 by 14 21 ÷ 14 = 1 (quotient), remainder = 21 − (14×1) = 7
The remainder is 7, not zero, so continue the process
Step 3: Divide 14 by 7 14 ÷ 7 = 2 (quotient), remainder = 14 − (7×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 21 and 56 is 7.
Finding the GCF of 21 and 56 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 21 apples and 56 oranges. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 21 and 56 GCF of 21 and 56 is 7. There are 7 equal groups 21 ÷ 7 = 3 56 ÷ 7 = 8 There will be 7 groups, and each group gets 3 apples and 8 oranges.
As the GCF of 21 and 56 is 7, the teacher can make 7 groups. Now divide 21 and 56 by 7. Each group gets 3 apples and 8 oranges.
A school has 21 red flags and 56 blue flags. They want to arrange them in rows with the same number of flags in each row, using the largest possible number of flags per row. How many flags will be in each row?
GCF of 21 and 56 is 7. So each row will have 7 flags.
There are 21 red and 56 blue flags.
To find the total number of flags in each row, we should find the GCF of 21 and 56.
There will be 7 flags in each row.
A tailor has 21 meters of red fabric and 56 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 21 and 56 The GCF of 21 and 56 is 7. The fabric is 7 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 21 and 56, which is 7. The length of each piece of the fabric will be 7 meters.
A carpenter has two wooden planks, one 21 cm long and the other 56 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 21 and 56 is 7. The longest length of each piece is 7 cm.
To find the longest length of each piece of the two wooden planks, 21 cm and 56 cm, respectively, we have to find the GCF of 21 and 56, which is 7 cm. The longest length of each piece is 7 cm.
If the GCF of 21 and ‘a’ is 7, and the LCM is 168, find ‘a’.
The value of ‘a’ is 56.
GCF x LCM = product of the numbers
7 × 168 = 21 × a
1176 = 21a
a = 1176 ÷ 21 = 56
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.