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Last updated on September 10, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 30 and 100.
The greatest common factor of 30 and 100 is 10. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 30 and 100, a few methods are described below:
Steps to find the GCF of 30 and 100 using the listing of factors:
Step 1: Firstly, list the factors of each number
Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Factors of 100 = 1, 2, 4, 5, 10, 20, 25, 50, 100.
Step 2: Now, identify the common factors of them Common factors of 30 and 100: 1, 2, 5, 10.
Step 3: Choose the largest factor The largest factor that both numbers have is 10. The GCF of 30 and 100 is 10.
To find the GCF of 30 and 100 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 30: 30 = 2 x 3 x 5
Prime Factors of 100: 100 = 2 x 2 x 5 x 5
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 5
Step 3: Multiply the common prime factors 2 x 5 = 10
The Greatest Common Factor of 30 and 100 is 10.
Find the GCF of 30 and 100 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 100 by 30 100 ÷ 30 = 3 (quotient), The remainder is calculated as 100 − (30×3) = 10 The remainder is 10, not zero, so continue the process
Step 2: Now divide the previous divisor (30) by the previous remainder (10) Divide 30 by 10 30 ÷ 10 = 3 (quotient), remainder = 30 − (10×3) = 0
The remainder is zero, so the divisor becomes the GCF. The GCF of 30 and 100 is 10.
Finding the GCF of 30 and 100 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A painter has 30 brushes and 100 paint tubes. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 30 and 100. GCF of 30 and 100 is 10.
There are 10 equal groups. 30 ÷ 10 = 3 100 ÷ 10 = 10
There will be 10 groups, and each group gets 3 brushes and 10 paint tubes.
As the GCF of 30 and 100 is 10, the painter can make 10 groups. Now divide 30 and 100 by 10. Each group gets 3 brushes and 10 paint tubes.
A garden has 30 rose bushes and 100 tulip plants. They want to arrange them in rows with the same number of plants in each row, using the largest possible number of plants per row. How many plants will be in each row?
GCF of 30 and 100 The GCF is 10. So each row will have 10 plants.
There are 30 rose bushes and 100 tulip plants. To find the total number of plants in each row, we should find the GCF of 30 and 100. There will be 10 plants in each row.
A tailor has 30 meters of silk ribbon and 100 meters of cotton ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 30 and 100. The GCF of 30 and 100 is 10. The ribbon pieces are 10 meters long.
For calculating the longest length of the ribbon, first we need to calculate the GCF of 30 and 100, which is 10. The length of each piece of the ribbon will be 10 meters.
A carpenter has two wooden planks, one 30 cm long and the other 100 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 30 and 100 is 10. The longest length of each piece is 10 cm.
To find the longest length of each piece of the two wooden planks, 30 cm and 100 cm, respectively, we have to find the GCF of 30 and 100, which is 10 cm. The longest length of each piece is 10 cm.
If the GCF of 30 and ‘b’ is 10, and the LCM is 300. Find ‘b’.
The value of ‘b’ is 100.
GCF x LCM = product of the numbers
10 × 300 = 30 × b
3000 = 30b
b = 3000 ÷ 30 = 100
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.