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292 LearnersLast updated on November 24, 2025

The binomial distribution is used to measure how much the probabilities differ from the expected value (mean). This value shows the difference between the sampled observations and the expected value. In this topic, we are going to learn more about the variance of binomial distribution.
A binomial distribution is a type of probability model that counts the number of “successes” in a given set of independent trials. It is used only when there are only two possible outcomes per trial (e.g., heads vs. tails or pass vs. fail) and the probability of success is constant. Essentially, it calculates the likelihood of receiving a specific result in a repeated “yes or no” experiment.
\(P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\)
Consider a student guessing randomly on a 10-question multiple-choice test, where each question has four answer options.
This scenario fits a binomial distribution because:
You could use the binomial formula to calculate the exact odds of the student passing (getting 6 or more correct) by pure luck.
The variance of a binomial distribution measures how much the number of successes in your trials is likely to differ from the average (mean) number of successes.
In simpler terms, it tells you how “spread out” your results are.
Low Variance: Results are tightly clustered around the average. You can be confident the outcome will be close to the mean.
High Variance: Results are widely scattered.3 predicting the exact outcome is harder because the possibilities are more spread out.
If you were to graph this:
The formula for the variance (\(\sigma^2\)) of a binomial distribution is:
\(Var(X) = \sigma^2 = n \cdot p \cdot (1 - p)\)
Sometimes written as:
\(Var(X) = npq\)
Where,
n is the Total number of trials,
p is the Probability of success in a single trial, and
q is the Probability of failure (1-p).
Example Calculation:
Imagine you flip a fair coin (p=0.5) 100 times (n=100).
This means that while you expect 50 heads, it is very normal for the result to vary by about 5 heads (getting 45 to 55 heads).


Calculating the variance of a binomial distribution is a straightforward process once you have your variables defined. It essentially measures the “spread” or volatility of your data around the average.
Here is the step-by-step guide to performing this calculation manually.
Step 1: Identify the Total Trials (n)
Determine how many times the experiment or trial is being performed.
Step 2: Identify the Probability of Success (p)
Determine the likelihood of getting the “successful” outcome in a single, individual trial.
Step 3: Calculate the Probability of Failure (q)
Subtract the probability of success from 1. This gives you q, or (1 - p).
(Note: If p was 0.2, then q would be 0.8)
Step 4: Multiply Them All Together
Multiply n by p by q.
Answer: The variance is 12.5.
The binomial distribution represents the probability of getting a specific number of successes in independent trials. The possible outcomes of each trial are success and failure. In every trail the probability of success remains the same. Let X be the number of successes in the n trials. Then the variance of X can be calculated as:
σ2 = E (X2) - (E (X))2
Now, let’s find the E(X), then the mean of X, which is np, here n is the number of trials and p is the probability of success.
Then, we have to identify the E (X2). This refers to the squared values of X. Also, we need to find the expected value of X2. X2 has a distribution where each outcome is squared because X follows a binomial distribution.
\(E (X^2) = \displaystyle\sum_{k=0}^{n}k^2\). P (X = k)
Next, using the probability mass function (PMF) of the binomial distribution, we can find the probability of getting k successes in n trials.
P (X = k) = \(\binom{n}{k}\) pk (1 - p) n - k
We can substitute this formula into an equation for E (X2) and then analyze the sum. Finally, add the values of E (X) and E (X2) into the formula of variance. Then simplify it to get the variance of the binomial distribution as (σ2) = np (1 - p)
The variance of a binomial distribution measures how much the number of successes deviates from the expected mean. In the fields of medical research, finance, sports analysis, and manufacturing, the role of the variance of the binomial distribution is vital.
The variance of the binomial distribution tells us how much our actual results differ from the expected value on average. However, some mistakes can lead to incorrect calculations and interpretations. By understanding the common mistakes of the variance of the binomial distribution, students can improve their statistical skills and practical knowledge.
The variance of the binomial distribution helps us to understand how much the results fluctuate around the mean. Understanding the concepts of variance of binomial distribution is useful in working with statistics, probability, and risk assessment. Here are some of the tricks and tips that help us to effectively work with the fundamental concept.
Find the variance of the binomial distribution having 15 trials and a probability of success of 0.6.
3.6
We can use the formula for the variance of a binomial distribution:
Variance (σ2) = np (1 - p)
Here, n is the number of trials = 15
p is the probability of success = 0.6
Hence, the prob failure = 1 - p = 1 - 0.6 = 0.4
Now, we can substitute the values to the formula: (σ2) = np (1 - p)
15 × 0.6 × 0.4
15 × 0.24 = 3.6
The variance is 3.6.
It means that the number of successes will fluctuate around the mean with a variance of 3.6
A factory produces 10 bulbs daily. The probability of a defective bulb is 0.2. Find the variance of the defective bulbs per day.
1.6
To find the variance of the defective bulbs per day, we can apply the binomial variance formula. Here,
n = 10
p = 0.2
1 - p = 1 - 0.2 = 0.8
The variance formula is:
Variance (σ2) = np (1 - p)
σ2 = 10 × 0.2 × 0.8 = 1.6
Hence, the variance of defective bulbs per day is 1.6
Felix takes 20 quizzes. The probability of passing each quiz is 0.8. Find the variance of the number of quizzes passed.
3.2
Variance (σ2) = np (1 - p) is the formula for the variance of the binomial distribution.
Here, n = 20
p = 0.8
1 - p = 1 - 0.8 = 0.2
Now, we can substitute the values.
σ2 = 20 × 0.8 × 0.2
σ2 = 20 × 0.16 = 3.2
The number of quizzes Felix passes fluctuates around the mean with a variance of 3.2
A basketball player takes 30 free throws. The probability of making a basket is 0.6. Find the variance of successful shots.
7.2
To find the answer, we can use the formula, Variance (σ2) = np (1 - p)
Where, n = 30
p = 0.6
1 - p = 1 - 0.6 = 0.4
So the formula will be:
σ2 = 30 × 0.6 × 0.4
σ2 = 30 × 0.24 = 7.2
The variance of successful shots is 7.2
In a shop, 40 customers visit daily. The probability that a customer makes a purchase is 0.6. Find the variance of the number of customers making a purchase.
9.6
To find the variance of the number of customers making a purchase, we can use the formula.
Here, n = 40
p = 0.6
1 - p = 1 - 0.6 = 0.4
The binomial variance formula is:
Variance (σ2) = np (1 - p)
σ2 = 40 × 0.6 × 0.4
σ2 = 40 × 0.24 = 9.6
The variance of the number of customers making a purchase is 9.6




