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1247 LearnersLast updated on November 18, 2025

Variance and standard deviation help us see whether a group of numbers stays close together or spreads out, just like checking whether friends stand in a tight group or scatter around the playground.
Standard deviation is a measure of how far the values in a data set are from the mean. In simple terms, it tells us whether the data points are close to the average or widely scattered. A slight standard deviation means the values are close to the mean, while a large one means the values are more spread out. This idea is used in descriptive statistics to understand variation within a sample, a population, or a probability distribution.
To calculate standard deviation, we first look at how each value differs from the mean. If we have n observations \(x_1,x_2,...,x_n\). We find the squared differences from the mean and add them:
\(\ \sum_{i=1}^{n} (x_i - \bar{x})^{2} \ \).
This sum shows how much the data varies. A small sum means low dispersion, while a large sum means high dispersion.
Because the sum of squared deviations alone is not a complete measure, we take its square root. This gives us the standard deviation formula, also known as the standard deviation equation, which is the square root of variance. This value is represented using the standard deviation symbol (σ for population, s for sample).
Understanding variance vs. standard deviation helps us see why taking the square root gives a clearer picture of how spread out the data is.
Whether you're learning how to find standard deviation, how to calculate standard deviation, or specifically how to find sample standard deviation, these steps remain essential.
Standard deviation is often displayed in a standard deviation chart or computed using tools like a standard deviation calculator.
To understand and measure the risk, consistency, and distribution of data, the measures of variance and standard deviations are employed in the fields of finance, accounting, and statistics. They are used to calculate the deviation of the values from their mean and assess the spread of data. Some of the main differences between these two fundamental measurements are listed below:
| Variance | Standard Deviation |
| Variance tells us how much the numbers in a group change from one another. | Standard deviation shows how spread out the numbers are in the same units as the data. |
| It is the average of the squared differences from the mean. | It is the square root of the variance. |
| Variance is written in squared units. | Standard deviation is written in the same units as the original data. |
| It is represented as \(σ^2\). | It is represented as σ. |
| Variance helps describe how far individual values are from the group’s average. | Standard deviation helps understand how tightly or loosely the numbers are grouped. |
Standard deviation helps us measure how spread out the values in a data set are. It shows how far the data points move away from the average. This idea is linked to dispersion, which tells us how much the numbers vary within a group. Variance represents the average of the squared distances between each value and the mean, while standard deviation shows how much the data values spread out around that mean. To calculate the standard deviation, we use two formulas: one for a sample and one for an entire population.
Population:
\(\ \sigma = \frac{\sum (X - \mu)^2}{N} \ \)
X - The value in the data distribution
μ - The population Mean
N - Total number of observations
Sample:
\(\ \sigma = \frac{\sum (X - \mu)^2}{N} \ \)
X - The value in the data distribution
x - The sample mean
n - Total number of observations
Notice that both formulas are nearly the same, except for the denominator: the population standard deviation uses N, while the sample standard deviation uses n-1. When we calculate a sample mean, we do not use every value from the full population, so the sample mean is only an estimate of the actual population mean. This introduces some uncertainty or bias into the calculation. To fix this, we use n-1 instead of n in the sample formula. This adjustment is called Bessel’s correction.
When data values are not arranged in groups, we measure how much each value deviates from the average. There are three primary methods to calculate standard deviation:
Actual mean method
In this method, we first find the actual mean (x) and then calculate how far each value is from it.
Formula:
\(\ \sigma = \sqrt{ \frac{\sum (X - \mu)^2}{N} } \ \)
For example,
Data: 3, 2, 5, 6
Mean = \((3 + 2 + 5 + 6) ÷ 4 = 4\)
Squared differences:
\((4-3)2+(2-4)2+(5-4)2+(6-4)2=10\)
Variance = 104 = 2.5
Standard deviation = 2.5 = 1.58
Assumed mean method
When the values are large or complex to handle, we pick a simple value A as the assumed mean.
Let \(d = x-A\)
Formula:
\(\ \sigma = \frac{\sum (X - \mu)^{2}}{N} \ \)
Step deviation method
Used when data has a common factor to simplify calculations.
Let
Formula:
\(\ \sigma = \sqrt{\frac{\sum (X - \mu)^2}{N}} \ \)
Standard Deviation for Grouped Data
For grouped data, we first prepare a frequency table, then use the same three methods:
These methods work the same way as for ungrouped data, except that frequencies are included in each calculation.
Standard deviation measures how much data values differ from the mean. Understanding it helps students interpret data variability and make sense of real-world statistics.
Variance and standard deviation play an important role in measuring the deviation and spread of data in a given dataset. However, students make some errors during their calculations. Understanding these mistakes helps make the process less prone to errors.
The real-world applications of variance and standard deviation are countless. They help measure the spread and deviation of the given data from its average or mean.
The weights of 5 students in a class are: 28, 30, 32, 34, and 36 kilograms. Find the variance and standard deviation.
The variance is 8 and the standard deviation is approximately 2.83.
Here, we have to find the mean first.
\(\ \text{Mean} = \frac{\text{Sum of all values}}{\text{Total number of values}} \ \)
\(Mean = (28 + 30 + 32 + 34 + 36) / 5 = 160 / 5 = 32\)
Therefore, 32 is the mean.
Find each value’s deviation from the mean \((x_i − μ)\):
\((28 − 32 = −4) (30 − 32 = −2) (32 − 32 = 0) (34 − 32 = 2) (36 − 32 = 4)\).
Square each deviation:
\((−4)^2 = 16; (−2)^2 = 4; 0^2 = 0; 2^2 = 4; 4^2 = 16\)
Calculate the variance using the formula:
\(\sigma^{2} = \frac{\sum_{i=1}^{N} (x_{i} - \mu)^{2}}{N}\)
\(σ² = (16 + 4 + 0 + 4 + 16) / 5 = 40 / 5 = 8\)
So the variance is 8.
Find the standard deviation by taking the square root of the variance:
Standard deviation = √Variance
\(√8 = 2.83\)
Thus, the standard deviation is approximately 2.83.
Find the variance of the given numbers: 2, 4, 6, 8, 10.
8 is the variance.
To find the variance, first we have to find the mean.
\(Mean = (2 + 4 + 6 + 8 + 10) / 5 \)
= \(\frac{30}{5}\) = 6
Next, find each number’s deviation from the mean and square it.
For the numbers, the deviation can be calculated by (x − Mean)
\(Mean = (2 + 4 + 6 + 8 + 10) / 5 \)
Then, we can find the squared deviation (x − Mean)2:
\((−4)^2 = 16\)
\((−2)^2 = 4\)
\(0^2 = 0\)
\(2^2 = 4\)
\(4^2 = 16\)
Now, we can find the variance by using the formula:
\(\sigma^{2} = \frac{\sum_{i=1}^{N} (x_{i} - \mu)^{2}}{N}\)
\(σ² = (16 + 4 + 0 + 4 + 16) / 5 \)
=\( 40 / 5 = 8 \).
The heights (in cm) of 3 students in a class are: 150, 160, 170. Find the variance and standard deviation.
Variance (𝜎²) = 66.67.
Standard Deviation (𝜎) = 8.165 cm.
Find the mean.
Mean = Sum of all values / Total number of values
\(Mean = (150 + 160 + 170) / 3 = 480 / 3 = 160\)
So, 160 is the mean height.
Next, we can calculate the squared differences from the mean.
The formula for finding variance is:
\(\sigma^{2} = \frac{\sum_{i=1}^{N} (x_{i} - \mu)^{2}}{N}\)
Here, we have to find the \((xi − μ) and (xi − μ)^2\):
\( (xi − μ) = (150 − 160 = −10); (160 − 160 = 0); (170 − 160 = 10)\)
\((xi − μ)^2 = (−10)^2 = 100; 0^2 = 0; (10)^2 = 100\)
\(Variance = σ² = ∑Ni = 1(xi − μ)^2 / N \)
\(100 + 0 + 100 = 200\)
\(So, 200 / 3 = 66.67\)
Now, we can calculate the standard deviation:
Standard deviation = √Variance
= √66.667 \(\approx \) 8.167
So, the standard deviation is 8.17 cm.
2 friends took a math test, and their scores were 90 and 95. How much do their scores vary from the average score?
Variance (𝜎²) = 6.25
Standard Deviation (𝜎) = 2.5.
To find the variance and standard deviation, we have to calculate the mean first:
\(Mean = \frac{(90 + 95)}{2} = \frac{185}{2} = 92.5 \)
92.5 is the mean score.
Next, we can find the squared differences from the mean:
\(Mean = \frac{(90 + 95)}{2} = \frac{185}{2} = 92.5 \)
Now we have to square the deviations:
\((-2.5)² = 6.25 \)
\((2.5)² = 6.25\)
\(\sigma^{2} = \frac{\sum_{i=1}^{N} (x_{i} - \mu)^{2}}{N}\)
\(∑(xi − 𝜇)2 = 6.25 + 6.25 = 12.5\)
= \(\frac{12.5}{2}\) = 6.25
So, the variance is 6.25
The formula for standard deviation is:
Standard deviation = √Variance
= √6.25 = 2.5
2.5 is the standard deviation of the given scores.
Five kids counted their steps while walking to school. They recorded 2000, 2200, 3600, 4000, and 4400 steps respectively. Find the variance.
934,400.
To calculate the variance, first we have to find the mean:
\(Mean = (2000 + 2200 + 3600 + 4000 + 4400) / 5 \)
\(= 16200 / 5 = 3240 \)
3240 is the mean number of steps.
Next, we can calculate the squared differences from the mean:
\((x − 𝜇) = (2000 − 3240 = −1240)\)
\((2200 − 3240 = −1040)\)
\((3600 − 3240 = 360) \)
\((4000 − 3240 = 760)\)
\((4400 − 3240 = 1160)\)
Now, we can calculate \((x − 𝜇)2:\)
\((−1240)² = 1,537,600\)
\((−1040)² = 1,081,600\)
\((360)² = 129,600\)
\((760)² = 577,600\)
\((1160)² = 1,345,600\)
The formula for calculating variance is:
\(\sigma^{2} = \frac{\sum_{i=1}^{N} (x_{i} - \mu)^{2}}{N}\)
\((1,537,600 + 1,081,600 + 129,600 + 577,600 + 1,345,600) / 5 \)
\(σ² = 4,672,000 / 5 = 934,400\)
The variance is 934,400.
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!






