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Last updated on September 22, 2025

Derivative of u

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We use the derivative of u to understand how the function changes in response to a slight change in x. Derivatives are useful in various real-life applications, such as calculating profit or loss. We will now discuss the derivative of u in detail.

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What is the Derivative of u?

We now understand the derivative of u. It is commonly represented as d/dx (u) or (u)', and its derivative depends on the specific function u represents.

 

If u is a differentiable function, its derivative will be well-defined within its domain.

 

The key concepts to keep in mind include the rules of differentiation and how they apply to various forms of functions.

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Derivative of u Formula

The derivative of u can be denoted as d/dx (u) or (u)'.

 

The specific formula for differentiating u depends on the form of the function u. For instance, if u = tan x, then d/dx (u) = sec²x.

 

The formula applies to all x where the function u is defined and differentiable.

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Proofs of the Derivative of u

We can derive the derivative of u using various proofs depending on the function u. To demonstrate this, we use differentiation rules and identities. Some methods include:

 

By First Principle - The derivative of a function like u can be shown using the First Principle, which expresses the derivative as the limit of the difference quotient.

 

Using Chain Rule-The chain rule helps in differentiating composite functions.

 

Using Product Rule-The product rule is used when u is the product of two or more functions. Here, we will demonstrate the differentiation of specific functions like tan x as an example:

 

By First Principle

 

For f(x) = tan x, the derivative can be expressed as the following limit: f'(x) = limₕ→₀ [f(x + h) - f(x)] / h Given f(x) = tan x, we write f(x + h) = tan(x + h).

 

Substituting these into the equation, we simplify and find f'(x) = sec²x.

 

Using Chain Rule

 

For tan x = sin x/cos x, applying the chain and quotient rule gives: d/dx(tan x) = sec²x.

 

Using Product Rule

 

For tan x = sin x · (cos x)⁻¹, we apply the product rule and find the derivative to be sec²x.

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Higher-Order Derivatives of u

When a function is differentiated multiple times, the resulting derivatives are called higher-order derivatives. These can be complex to understand.

 

Consider a car, where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes.

 

Higher-order derivatives help us understand more about functions like u. For example, if u = tan x, the first derivative is f′(x), and subsequent derivatives can be found similarly.

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Special Cases:

Special cases arise when the function u has undefined points or behaves irregularly. For instance, if u = tan x, the derivative is undefined at x = π/2 due to a vertical asymptote. At x = 0, the derivative is sec²(0), which equals 1.

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Common Mistakes and How to Avoid Them in Derivatives of u

Errors frequently occur when differentiating functions like u. These mistakes can be avoided by understanding the correct procedures. Here are a few common mistakes and how to avoid them:

Mistake 1

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Not simplifying the equation

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Students may neglect to simplify the equation, leading to incorrect results. Often, steps are skipped, especially when using the product or chain rule. Ensure each step is clearly written to avoid errors.

Mistake 2

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Forgetting the Undefined Points

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Students might forget that some functions are undefined at specific points. For example, tan x is undefined at x = π/2. Consider the domain of the function to avoid errors.

Mistake 3

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Incorrect use of Rules

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Misapplication of differentiation rules like the quotient rule can lead to errors. For instance, incorrect differentiation of tan x/x might occur if rules are not properly applied. Always double-check calculations.

Mistake 4

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Not writing Constants and Coefficients

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Students sometimes forget to include constants before functions. For example, d/dx (5u) should equal 5 times the derivative of u. Check for constants and include them properly.

Mistake 5

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Not Applying the Chain Rule

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The chain rule is often overlooked, especially when an inner function is not considered. For example, d/dx (u(2x)) should be differentiated as per the chain rule.

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Examples Using the Derivative of u

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Problem 1

Calculate the derivative of (u·v) where u = tan x and v = sec²x

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Here, f(x) = tan x · sec²x. Using the product rule, f'(x) = u′v + uv′. In the given equation, u = tan x and v = sec²x.

 

Let’s differentiate each term: u′ = d/dx (tan x) = sec²x v′ = d/dx (sec²x) = 2 sec²x tan x Substituting into the equation, f'(x) = sec⁴x + 2 sec²x tan²x.

 

Thus, the derivative of the specified function is sec⁴x + 2 sec²x tan²x.

Explanation

Divide the function into two parts. Find each derivative and combine them using the product rule to get the final result.

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Problem 2

An engineering firm is designing a slope represented by y = tan(x) where y is the elevation at a distance x. If x = π/4 meters, measure the slope of the slope.

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We have y = tan(x) (slope of the slope)...(1)

 

Differentiate equation (1): dy/dx = sec²(x) Given x = π/4, substitute this into the derivative: sec²(π/4) = 2 (since tan(π/4) = 1)

 

Hence, the slope at x = π/4 is 2.

Explanation

The slope at x = π/4 is 2, indicating that at this point, the elevation rises at a rate twice the horizontal distance.

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Problem 3

Derive the second derivative of the function y = tan(x).

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First, find the first derivative: dy/dx = sec²(x)...(1)

 

Now differentiate equation (1) for the second derivative: d²y/dx² = d/dx [sec²(x)]

 

Use the product rule: d²y/dx² = 2 sec(x) · [sec(x) tan(x)] = 2 sec²(x) tan(x)

 

Therefore, the second derivative of y = tan(x) is 2 sec²(x) tan(x).

Explanation

Start with the first derivative, then use the product rule to differentiate sec²(x) and simplify to find the second derivative.

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Problem 4

Prove: d/dx (tan²(x)) = 2 tan(x) sec²(x).

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Using the chain rule, consider y = tan²(x). Rewriting, [tan(x)]².

 

Differentiate using the chain rule: dy/dx = 2 tan(x) · d/dx [tan(x)]

 

Since the derivative of tan(x) is sec²(x), dy/dx = 2 tan(x) · sec²(x). Thus, d/dx (tan²(x)) = 2 tan(x) sec²(x).

Explanation

Use the chain rule to differentiate, replace tan(x) with its derivative, and substitute y = tan²(x) to derive the equation.

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Problem 5

Solve: d/dx (u/x) where u = tan x

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Differentiate using the quotient rule: d/dx (tan x/x) = (d/dx (tan x) · x - tan x · d/dx(x))/ x²

 

Substitute d/dx (tan x) = sec²x and d/dx(x) = 1: (x sec²x - tan x) / x² = (x sec²x - tan x) / x²

 

Therefore, d/dx (tan x/x) = (x sec²x - tan x) / x²

Explanation

Differentiate the function using the product and quotient rules, then simplify to obtain the final result.

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FAQs on the Derivative of u

1.Find the derivative of u = tan x.

Using the quotient rule for tan x = sin x/cos x, we find: d/dx (tan x) = sec²x.

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2.Can we use the derivative of u in real life?

Yes, derivatives like that of u are used in calculating rates of change, applicable in mathematics, physics, and economics.

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3.Is it possible to take the derivative of u at x = π/2 if u = tan x?

No, at x = π/2, tan x is undefined, so the derivative cannot be found.

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4.What rule is used to differentiate u/x where u = tan x?

The quotient rule is used, resulting in: d/dx (tan x/x) = (x sec²x - tan x) / x².

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5.Are the derivatives of u = tan x and u = tan⁻¹x the same?

No, they differ. The derivative of tan x is sec²x, while that of tan⁻¹x is 1/(1 + x²).

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6.Can we find the derivative for the formula u = tan x?

Yes, using the quotient rule: y’ = [cos x · d/dx (sin x) - sin x · d/dx (cos x)] / (cos²x) = sec²x.

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Important Glossaries for the Derivative of u

  • Derivative: Indicates how a function changes with a slight change in x.

 

  • First Principle: A method to derive a function's derivative as a limit.

 

  • Chain Rule: A rule for differentiating composite functions.

 

  • Quotient Rule: A rule for differentiating a function that is a ratio of two functions.

 

  • Product Rule: A rule used for differentiating the product of two functions.
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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