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210 LearnersLast updated on September 9, 2025

We use the derivative of x⁴, which is 4x³, as a measuring tool for how the function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of x⁴ in detail.
We now understand the derivative of x⁴. It is commonly represented as d/dx (x⁴) or (x⁴)', and its value is 4x³.
The function x⁴ has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Polynomial Function: (x⁴ is a polynomial function).
Power Rule: Rule for differentiating x⁴ (since it involves raising x to a power).
Coefficient: The constant that multiplies the variable x in the derivative.
The derivative of x⁴ can be denoted as d/dx (x⁴) or (x⁴)'. The formula we use to differentiate x⁴ is: d/dx (x⁴) = 4x³ (or) (x⁴)' = 4x³ The formula applies to all x in the domain of the real numbers.
We can derive the derivative of x⁴ using proofs.
To show this, we will use algebraic manipulation along with the rules of differentiation.
There are several methods we use to prove this, such as:
By First Principle
Using Power Rule
Using Product Rule
We will now demonstrate that the differentiation of x⁴ results in 4x³ using the above-mentioned methods:
By First Principle
The derivative of x⁴ can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.
To find the derivative of x⁴ using the first principle, we will consider f(x) = x⁴.
Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)
Given that f(x) = x⁴, we write f(x + h) = (x + h)⁴.
Substituting these into equation (1), f'(x) = limₕ→₀ [(x + h)⁴ - x⁴] / h = limₕ→₀ [x⁴ + 4x³h + 6x²h² + 4xh³ + h⁴ - x⁴] / h = limₕ→₀ [4x³h + 6x²h² + 4xh³ + h⁴] / h = limₕ→₀ [4x³ + 6x²h + 4xh² + h³]
As h approaches 0, we have, f'(x) = 4x³.
Hence, proved.
Using Power Rule
To prove the differentiation of x⁴ using the power rule,
We use the formula: d/dx (xⁿ) = n*xⁿ⁻¹
For x⁴, n = 4, so: d/dx (x⁴) = 4*x³
This is a straightforward application of the power rule.
Using Product Rule
We will now prove the derivative of x⁴ using the product rule.
The step-by-step process is demonstrated below:
Here, we rewrite x⁴ as x*x*x*x.
Using the product rule formula:
d/dx [u.v] = u'.v + u.v'
Consider u = x and v = x³. u' = d/dx (x) = 1 v' = d/dx (x³) = 3x²
Using the product rule: d/dx (x⁴) = u'.v + u.v' = 1*x³ + x*3x² = x³ + 3x³ = 4x³
Thus: d/dx (x⁴) = 4x³.


When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes.
Higher-order derivatives make it easier to understand functions like x⁴.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point.
The second derivative is derived from the first derivative, which is denoted using f′′(x).
Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth Derivative of x⁴, we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
When x is 0, the derivative of x⁴ = 4x³, which is 0. When x is 1, the derivative of x⁴ = 4x³, which is 4. When x is -1, the derivative of x⁴ = 4x³, which is -4.
Students frequently make mistakes when differentiating x⁴. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (x⁴·x²).
Here, we have f(x) = x⁴·x².
Using the product rule, f'(x) = u′v + uv′
In the given equation, u = x⁴ and v = x².
Let’s differentiate each term, u′ = d/dx (x⁴) = 4x³ v′ = d/dx (x²) = 2x substituting into the given equation, f'(x) = (4x³)(x²) + (x⁴)(2x)
Let’s simplify terms to get the final answer, f'(x) = 4x⁵ + 2x⁵
Thus, the derivative of the specified function is 6x⁵.
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
An engineer is designing a component with a variable resistance modeled by the function R(x) = x⁴, where R represents resistance at distance x. If x = 2 meters, measure the rate of change of resistance.
We have R(x) = x⁴ (resistance of the component)...(1)
Now, we will differentiate equation (1)
Take the derivative of x⁴: dR/dx = 4x³
Given x = 2 (substitute this into the derivative) dR/dx = 4(2)³ dR/dx = 4*8 = 32
Hence, the rate of change of resistance at a distance x = 2 is 32.
We find the rate of change of resistance at x = 2 as 32, which means that at a given point, the resistance of the component would change at this rate.
Derive the second derivative of the function y = x⁴.
The first step is to find the first derivative, dy/dx = 4x³...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [4x³]
Here we use the power rule, d²y/dx² = 4*3x² d²y/dx² = 12x²
Therefore, the second derivative of the function y = x⁴ is 12x².
We use the step-by-step process, where we start with the first derivative. Using the power rule, we differentiate 4x³. We then simplify the terms to find the final answer.
Prove: d/dx (x⁴) = 4x³.
Let’s start using the power rule: Consider y = x⁴ To differentiate, we apply the power rule: dy/dx = 4x³ This directly follows from the formula for the derivative of a power function. Hence proved.
In this step-by-step process, we used the power rule to differentiate the equation, showing that the derivative of x⁴ is 4x³.
Solve: d/dx (x⁴/x).
To differentiate the function, we use the quotient rule: d/dx (x⁴/x) = (d/dx (x⁴).x - x⁴.d/dx(x))/x²
We will substitute d/dx (x⁴) = 4x³ and d/dx (x) = 1 (4x³.x - x⁴*1)/x² = (4x⁴ - x⁴)/x² = (3x⁴)/x²
Therefore, d/dx (x⁴/x) = 3x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






