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Last updated on September 15, 2025
We use the derivative of sin(x), which is cos(x), as a measuring tool for how the sine function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of sin(x) in detail.
We now understand the derivative of sin x. It is commonly represented as d/dx (sin x) or (sin x)', and its value is cos x. The function sin x has a clearly defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below:
Sine Function: (sin(x) = opposite/hypotenuse in a right triangle).
Chain Rule: Rule for differentiating composite functions involving sin(x).
Cosine Function: cos(x) = adjacent/hypotenuse in a right triangle.
The derivative of sin x can be denoted as d/dx (sin x) or (sin x)'.
The formula we use to differentiate sin x is: d/dx (sin x) = cos x (or) (sin x)' = cos x
The formula applies to all x.
We can derive the derivative of sin x using proofs. To show this, we will use the trigonometric identities along with the rules of differentiation. There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of sin x results in cos x using the above-mentioned methods:
The derivative of sin x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.
To find the derivative of sin x using the first principle, we will consider f(x) = sin x. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)
Given that f(x) = sin x, we write f(x + h) = sin (x + h).
Substituting these into equation (1), f'(x) = limₕ→₀ [sin(x + h) - sin x] / h = limₕ→₀ [ [sin x cos h + cos x sin h] - sin x ] / h = limₕ→₀ [ sin x (cos h - 1) + cos x sin h ] / h = limₕ→₀ [ sin x (cos h - 1)/h + cos x sin h/h ]
Using limit formulas, limₕ→₀ (sin h)/h = 1 and limₕ→₀ (cos h - 1)/h = 0. f'(x) = sin x(0) + cos x(1) = cos x
Hence, proved.
To prove the differentiation of sin x using the chain rule, We consider a composite function, but for simple sin x, it directly gives: d/dx (sin x) = cos x
We will now prove the derivative of sin x using the product rule. The step-by-step process is demonstrated below: Here, we use the formula, sin x = (1).(sin x) Given that, u = 1 and v = sin x
Using the product rule formula: d/dx [u.v] = u'. v + u. v' u' = d/dx (1) = 0 v' = d/dx (sin x) = cos x
Again, use the product rule formula: d/dx (sin x) = u'. v + u. v'
Let’s substitute u = 1, u' = 0, v = sin x, and v' = cos x
When we simplify each term: We get, d/dx (sin x) = 0 + 1(cos x)
Thus: d/dx (sin x) = cos x.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like sin(x).
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth Derivative of sin(x), we generally use fn(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
When x is π/2, the derivative is 0 because cos(x) is 0 at this point. When x is 0, the derivative of sin x = cos(0), which is 1.
Students frequently make mistakes when differentiating sin x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (sin x·tan x).
Here, we have f(x) = sin x·tan x.
Using the product rule, f'(x) = u′v + uv′ In the given equation, u = sin x and v = tan x.
Let’s differentiate each term, u′ = d/dx (sin x) = cos x v′ = d/dx (tan x) = sec²x
Substituting into the given equation, f'(x) = (cos x)(tan x) + (sin x)(sec²x)
Let’s simplify terms to get the final answer, f'(x) = cos x tan x + sin x sec²x
Thus, the derivative of the specified function is cos x tan x + sin x sec²x.
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A company tracks the performance of its product using the function y = sin(x), where y represents the satisfaction level over time x months. If x = π/6 months, measure the rate of change of satisfaction.
We have y = sin(x) (satisfaction level)...(1)
Now, we will differentiate the equation (1) Take the derivative sin(x): dy/dx = cos(x) Given x = π/6 (substitute this into the derivative) cos(π/6) = √3/2
Hence, the rate of change of satisfaction at x = π/6 is √3/2.
We find the rate of change of satisfaction at x = π/6 as √3/2, which indicates how quickly the satisfaction level is changing at that point in time.
Derive the second derivative of the function y = sin(x).
The first step is to find the first derivative, dy/dx = cos(x)...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [cos(x)] d²y/dx² = -sin(x)
Therefore, the second derivative of the function y = sin(x) is -sin(x).
We use the step-by-step process, where we start with the first derivative. By differentiating cos(x), we find the second derivative is -sin(x).
Prove: d/dx (sin²(x)) = 2 sin(x) cos(x).
Let’s start using the chain rule: Consider y = sin²(x) = [sin(x)]²
To differentiate, we use the chain rule: dy/dx = 2 sin(x)·d/dx [sin(x)]
Since the derivative of sin(x) is cos(x), dy/dx = 2 sin(x)·cos(x)
Substituting y = sin²(x), d/dx (sin²(x)) = 2 sin(x)·cos(x)
Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace sin(x) with its derivative. As a final step, we substitute y = sin²(x) to derive the equation.
Solve: d/dx (sin x/x).
To differentiate the function, we use the quotient rule: d/dx (sin x/x) = [d/dx (sin x)·x - sin x·d/dx(x)]/x²
We will substitute d/dx (sin x) = cos x and d/dx (x) = 1 = (cos x·x - sin x·1)/x² = (x cos x - sin x)/x²
Therefore, d/dx (sin x/x) = (x cos x - sin x)/x²
In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.