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1637 LearnersLast updated on November 20, 2025

Events that cannot occur at the same time are called mutually exclusive events. In other words, if event A occurs, then event B cannot occur. Let us now see more about mutually exclusive events and how to use them.
Mutually exclusive events are two or more events that cannot occur at the same time or in the same trial. In mathematics, mutually exclusive events mean that the intersection of these events is an empty set. When one event is happening, the second event cannot happen.
In probability, we express this as:
P(A ∩ B) = 0
Where
There are a lot of differences between mutually exclusive and independent events. Some of the differences are mentioned below:
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Mutually Exclusive Events |
Independent Events |
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One event prevents the other from happening |
One event does not affect the other |
|
Both events cannot occur at the same time |
Both events can occur at the same time |
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Formula is: |
Formula is:\(P(A ∪ B) = P(A) + P(B) − P(A ∩ B)\) |
| If represented by a Venn diagram, the circles or sets don’t overlap
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In a Venn diagram, the circles overlap |
Mutually exclusive events occur when two events, A and B, cannot happen at the same time. In other words, the chance of both events occurring together is zero, which can be written as:
\(\text{P(A and B)=0}\)
To find the probability that either event A or event B happens, we should add the probability of each event:
\(\text{P(A or B)=P(A)+P(B)}\)
The steps to calculate the probability of mutually exclusive events is given as;
Step 1: Identify the two events, A and B, ensuring they do not co-occur.
Step 2: Make sure that the chance of both events happening together is zero:
\(\text{P(A and B)=0}\)
Step 3: Use the formula for the probability that both event happens:
\(\text{P(A or B)=P(A)+P(B)}\)
Step 4: Determine the individual probabilities of events A and B.
Step 5: Add these probabilities to find the combined probability.
Step 6: Remember that this combined probability represents the chance of either event occurring, but not both at once.
This simple approach helps when figuring out outcomes where two possibilities exclude each other, like tossing a coin or rolling a die.
Mutually exclusive events cannot occur at the same time, so the probability of both events occurring together is always zero. Therefore, the probability of two mutually exclusive events A and B is defined as follows:
\(P(AB) = 0\)
We know that,
\(P (A U B) = P(A) + P(B) - P ( A∩B)\)
Considering A and B are mutually exclusive events, we get,
\(P (A U B) = P(A) + P(B)\)
For example, while we are tossing a single die, the events “rolling a 2” and “rolling a 5” are mutually exclusive because the die cannot show both numbers at once. The probability of either event A or event B occurring is the sum of their individual probabilities.
\(P (A U B) = P(A) + P(B)\)
\(\text{P (2 or 5)}= \frac {1}{6} +\frac {1}{6} \)
\(\text{P(2 or 5)}= \frac{2}{6} = \frac {1}{3}\)
Therefore, the probability of rolling either a 2 or a 5 is \(\frac{1}{3}.\)
We can use Venn diagrams to illustrate mutually exclusive events. When a set is represented by a circle in a Venn diagram, mutually exclusive events are shown as two circles that do not overlap, indicating that the sets have no elements in common, as depicted in the image below.
For non-mutually exclusive events: In the case of non-mutually exclusive events, the Venn diagram shows an overlap between the two sets, indicating that they share some common elements, as illustrated in the image below.
Conditional probability refers to the likelihood of event A occurring, assuming that event B has already taken place.
For two independent events A and B, the conditional probability of event B given that event A has occurred is represented by P(B∣A) and is defined by the following formula.
\(P(B|A) = \frac{P (A ∩ B)}{P(A)}\)
According to the multiplication rule,
\(P (A ∩ B) = 0\)
Therefore,
\(P(B|A) = \frac{0}{P(A)}\)
\(P(B|A) = 0\)
Some of the rules of mutually exclusive events are mentioned below:
When understanding the concept of mutually exclusive events, students tend to make mistakes. Here are some common mistakes and their solutions:
There are many uses of mutually exclusive events. Let us now see the uses and applications of mutually exclusive events in different fields:
Medical Diagnosis: Mutually exclusive events are used in medical diagnoses, where specific diseases cannot occur simultaneously. If a patient is diagnosed with a particular disease, then they cannot have another mutually exclusive condition at the same time.
Weather Forecasting: In meteorology, predicting specific weather events like rain or sunshine are mutually exclusive. It either rains or does not at any given time or place.
Traffic Signals: When managing the traffic at intersections, green and red signals are mutually exclusive. If the signal is green, then it cannot be red at the same time.
In a single toss of a fair coin, what is the probability of getting heads or tails?
1 (or 100%).
Identify outcomes:
A coin has two outcomes: heads (H) and tails (T)
Mutual exclusivity: H and T are mutually exclusive (only one can occur)
Calculate:
\(P(H or T) = P(H) + P(T) = \frac{1}{2}+\frac{1}{2} = 1.\)
When rolling a fair six-sided die, what is the probability of rolling a 2 or a 5?
\(\frac{1}{3}.\)
Total Outcomes: 6 (numbers 1 to 6)
Mutual exclusivity: 2 and 5 are mutually exclusive (only one can occur)
Favorable outcomes: 2 and 5
Calculate:
\(\text{P(2 or 5)} = P(2)+P(5)=\frac{1}{6} + \frac{1}{6} \\[1em] \text{P(2 or 5)}= \frac{2}{6} = \frac{1}{3}\)
For a fair die, what is the probability of rolling a 1, 3, or 5?
\(\frac{1}{2}.\)
Favorable outcomes: 1, 3, 5
Mutual exclusivity: 1, 3, and 5 are mutually exclusive (only one can occur)
Calculate:
\(\text{P(1 or 3 or 5)} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6}\\[1em] \text{P(1 or 3 or 5)}= \frac{3}{6} = \frac{1}{2}\)
From a standard 52-card deck, what is the probability of drawing an ace or king?
\(\frac{2}{13}.\)
Favorable outcomes: 4 aces + 4 kings
Mutual exclusivity: aces and kings are mutually exclusive (only one can occur)
Calculate:
\(\text{P(ace or king)} = \frac{8}{52} = \frac{2}{13}\)
From a standard deck of 52 cards, what is the probability of drawing a red card or a black card?
1 (or 100%).
Favorable outcomes: A card is either red (26 cards) or black (26 cards)
Mutual exclusivity: Red cards and black cards are mutually exclusive (only one can occur)
Calculate:
\(\text{P(red or black)} = \frac{52}{52} = 1.\)
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!






