Last updated on August 11th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items and schedule events. In this topic, we will learn about the GCF of 54 and 42.
The greatest common factor of 54 and 42 is 6. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 54 and 42, a few methods are described below:
Steps to find the GCF of 54 and 42 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 54 = 1, 2, 3, 6, 9, 18, 27, 54.
Factors of 42 = 1, 2, 3, 6, 7, 14, 21, 42.
Step 2: Now, identify the common factors of them Common factors of 54 and 42: 1, 2, 3, 6.
Step 3: Choose the largest factor The largest factor that both numbers have is 6. The GCF of 54 and 42 is 6.
To find the GCF of 54 and 42 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime Factors of each number Prime Factors of 54: 54 = 2 x 3 x 3 x 3 = 2 x 33
Prime Factors of 42: 42 = 2 x 3 x 7
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 3 = 6
Step 3: Multiply the common prime factors 2 x 3 = 6. The Greatest Common Factor of 54 and 42 is 6.
Find the GCF of 54 and 42 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 54 by 42 54 ÷ 42 = 1 (quotient), The remainder is calculated as 54 − (42×1) = 12.
The remainder is 12, not zero, so continue the process
Step 2: Now divide the previous divisor (42) by the previous remainder (12) Divide 42 by 12 42 ÷ 12 = 3 (quotient), remainder = 42 − (12×3) = 6.
Step 3: Now, divide the previous divisor (12) by the previous remainder (6) 12 ÷ 6 = 2 (quotient), remainder = 12 − (6×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 54 and 42 is 6.
Finding the GCF of 54 and 42 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A farmer has 54 apples and 42 oranges. He wants to pack them into boxes with the largest number of each fruit in every box. How many pieces of fruit will each box contain?
We should find the GCF of 54 and 42 GCF of 54 and 42 is 6. There are 6 equal groups. 54 ÷ 6 = 9 42 ÷ 6 = 7 There will be 6 boxes, and each box gets 9 apples and 7 oranges.
As the GCF of 54 and 42 is 6, the farmer can make 6 boxes. Now divide 54 and 42 by 6. Each box gets 9 apples and 7 oranges.
A concert hall has 54 chairs in one section and 42 chairs in another section. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 54 and 42 is 6. So each row will have 6 chairs.
There are 54 chairs in one section and 42 chairs in another section. To find the total number of chairs in each row, we should find the GCF of 54 and 42. There will be 6 chairs in each row.
A ribbon supplier has 54 meters of red ribbon and 42 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 54 and 42. The GCF of 54 and 42 is 6. The ribbon pieces are 6 meters long.
For calculating the longest length of the ribbon first, we need to calculate the GCF of 54 and 42, which is 6. The length of each piece of the ribbon will be 6 meters.
A carpenter has two wooden planks, one 54 cm long and the other 42 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 54 and 42 is 6. The longest length of each piece is 6 cm.
To find the longest length of each piece of the two wooden planks, 54 cm and 42 cm, respectively, we have to find the GCF of 54 and 42, which is 6 cm. The longest length of each piece is 6 cm.
If the GCF of 54 and ‘a’ is 6, and the LCM is 378. Find ‘a’.
The value of ‘a’ is 42.
GCF x LCM = product of the numbers 6 × 378 = 54 × a 2268 = 54a a = 2268 ÷ 54 = 42
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.