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Last updated on September 26, 2025
In mathematics, an inverse variation describes a relationship between two variables where their product is constant. When one variable increases, the other decreases proportionally. In this topic, we will learn the formula for inverse variation and how it is applied.
Inverse variation describes a situation where two variables change in a way that their product remains constant. Let’s learn the formula to calculate inverse variation.
The inverse variation formula is expressed as \\((xy = k)\), where \((x) \)and \(y\) are variables and \((k)\) is a constant. When\( (x)\) increases,\( (y)\) decreases, so that their product\( (xy)\) is always \((k)\).
Inverse variation can be understood through the relationship\( (y = \frac{k}{x})\). As\( (x) \)increases,\( (y)\) decreases and vice versa, maintaining the constant product \((xy = k)\).
The graph of an inverse variation is a hyperbola. It has two branches, one in the first quadrant and one in the third quadrant if (k > 0), and in the second and fourth quadrants if (k < 0).
Inverse variation formulas are crucial in math and real-life applications for modeling relationships where variables change inversely.
Understanding these concepts helps in fields like physics and engineering where inverse relationships are common.
Students may find inverse variation formulas tricky, but with some strategies, they can master them.
Remember that inverse variation involves multiplication maintaining a constant.
Practice with real-life examples like speed and time for a fixed distance.
Students often make errors when dealing with inverse variation. Here are some common mistakes and how to avoid them.
If \(x = 5\) when \(y = 8\), find the constant of variation \(k\).
The constant of variation k is 40.
The formula for inverse variation is xy = k. Substituting the given values,\( (5 \times 8 = 40)\). Hence, \((k = 40)\).
If \(xy = 24\) and \(x = 6\), find \(y\).
The value of y is 4.
Using the formula xy = k, substitute x = 6 and k = 24: 6y = 24. Solving for y, we get y = 4.
Find \(x\) if \(y = 3\) and \(k = 30\).
The value of x is 10.
From xy = k, substitute y = 3 and k = 30: \((x \times 3 = 30)\). Solving for\( (x)\), \((x = \frac{30}{3} = 10)\).
If the speed of a car is inversely proportional to the time taken to cover a fixed distance, and it takes 2 hours at 60 km/h, find the speed if it takes 3 hours.
The speed is 40 km/h.
Using the inverse variation formula xy = k, where x is speed and y is time,\( (60 \times 2 = 120)\). For y = 3, \\((x \times 3 = 120),\) so\( (x = \frac{120}{3} = 40) \)km/h.
If the area of a rectangle is constant and the length is doubled, what happens to the width?
The width is halved.
In inverse variation, if the length is doubled, the width must be halved to keep the area constant, maintaining the product xy = k.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.