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Last updated on September 29, 2025
In mathematics, an arithmetic progression (AP) is a sequence of numbers in which the difference between consecutive terms is constant. The formulae associated with AP are crucial for solving problems related to sequences and series. In this topic, we will learn the formulas used in arithmetic progressions.
Arithmetic progression (AP) is a sequence where the difference between any two consecutive terms is constant. Let’s learn the formula to calculate the nth term and the sum of the first n terms in an AP.
The nth term of an arithmetic progression is given by the formula: \\([ a_n = a + (n - 1) \cdot d ]\) where a is the first term, d is the common difference, and n is the term number.
The sum of the first n terms of an arithmetic progression is given by the formula:\( [ S_n = \frac{n}{2} \cdot (2a + (n - 1) \cdot d) ]\) or \([ S_n = \frac{n}{2} \cdot (a + l) ] \)where S_n is the sum of the first n terms, a is the first term, l is the last term, and d is the common difference.
In math and real life, we use arithmetic progression formulas to analyze and understand sequences. Here are some important aspects of arithmetic progressions.
Students may find math formulas tricky and confusing. Here are some tips and tricks to master the AP formulas.
In real life, AP formulas play a major role in understanding sequences. Here are some applications of the AP formulas.
Students make errors when calculating terms and sums in an AP. Here are some mistakes and the ways to avoid them, to master them.
Find the 5th term of an AP where the first term is 3 and the common difference is 4.
The 5th term is 19
To find the 5th term, use the formula: \([ a_n = a + (n - 1) \cdot d ]\) Here, \(( a = 3 )\), \(( d = 4 ),\) and \(( n = 5 )\). So, \(( a_5 = 3 + (5 - 1) \cdot 4 = 3 + 16 = 19 )\).
Calculate the sum of the first 7 terms of an AP with the first term 2 and common difference 3.
The sum is 77
To find the sum of the first 7 terms, use the formula:\( [ S_n = \frac{n}{2} \cdot (2a + (n - 1) \cdot d) ] \)Here, \(( a = 2 )\), \(( d = 3 ),\) and \(( n = 7 ). \)So,\( ( S_7 = \frac{7}{2} \cdot (2 \cdot 2 + (7 - 1) \cdot 3) \)= \(\frac{7}{2} \cdot (4 + 18) \)= \(\frac{7}{2} \cdot 22 = 77 )\).
Find the nth term of an AP where the first term is 5 and the common difference is 2 if the term is 21.
The term number n is 9
To find the term number, use the formula: [\( a_n = a + (n - 1) \cdot d ]\) We know \(( a_n = 21 ),\) a = 5 , and d = 2 . So, \\(( 21 = 5 + (n - 1) \cdot 2 )\). This gives\( ( 21 - 5 = (n - 1) \cdot 2 ).\) Hence, \(( 16 = (n - 1) \cdot 2 ) \)Thus,\( ( n - 1 = 8 ) \)and \(( n = 9 )\).
Find the sum of the first 10 terms of an AP where the first term is 1 and the last term is 19.
The sum is 100
To find the sum when the last term is known, use the formula:\( [ S_n = \frac{n}{2} \cdot (a + l) ]\) Here, a = 1 , l = 19 , and n = 10 . So, \(S_{10}\) = \(\frac{10}{2} \cdot (1 + 19)\) = \(5 \cdot 20 = 100 \)
Find the common difference of an AP if the 4th term is 14 and the first term is 5.
The common difference is 3
To find the common difference, use the nth term formula: \([ a_n = a + (n - 1) \cdot d ]\) We know \\(( a_4 = 14 ),\) ( a = 5 ), and ( n = 4 ). So,\( ( 14 = 5 + (4 - 1) \cdot d )\). This gives \(( 14 = 5 + 3d )\). Hence, \(( 14 - 5 = 3d )\). Thus,\( ( 9 = 3d ) \)and\( ( d = 3 )\).
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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