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Last updated on September 9, 2025

Derivative of Tan⁻¹x

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The derivative of tan⁻¹(x), often denoted as d/dx (tan⁻¹x) or (tan⁻¹x)', is a crucial tool in calculus for understanding how the inverse tangent function changes in response to variations in x. Derivatives play a significant role in various real-life applications such as physics and engineering. In this discussion, we will explore the derivative of tan⁻¹x in detail.

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What is the Derivative of Tan⁻¹x?

The derivative of tan⁻¹x is represented as d/dx (tan⁻¹x) or (tan⁻¹x)'. The value of this derivative is 1/(1+x²).

The inverse tangent function has a well-defined derivative, indicating it is differentiable across its domain.

Key concepts include:

Inverse Tangent Function: (tan⁻¹x is the inverse of the tangent function).

Chain Rule: Used for differentiating composite functions involving tan⁻¹x.

Domain Consideration: The function is differentiable for all real x.

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Derivative of Tan⁻¹x Formula

The derivative of tan⁻¹x is expressed as: d/dx (tan⁻¹x) = 1/(1+x²) This formula is applicable for all real numbers x.

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Proofs of the Derivative of Tan⁻¹x

We can derive the derivative of tan⁻¹x using several proofs, employing trigonometric identities and differentiation rules. Here are some methods:

By First Principle

Using Chain Rule

We will demonstrate that the derivative of tan⁻¹x results in 1/(1+x²) using these methods:

 

By First Principle

The derivative of tan⁻¹x can be derived using the First Principle, expressing it as the limit of the difference quotient.

Let f(x) = tan⁻¹x. Its derivative is: f'(x) = limₕ→₀ [f(x + h) - f(x)] / h Given f(x) = tan⁻¹x, write f(x + h) = tan⁻¹(x + h).

Substitute into the limit: f'(x) = limₕ→₀ [tan⁻¹(x + h) - tan⁻¹x] / h

Using the identity for tan⁻¹(a) - tan⁻¹(b), f'(x) = limₕ→₀ [1/(1+(x+h)x)(h)] = limₕ→₀ 1/(1+x²)

Hence, f'(x) = 1/(1+x²).

 

Using Chain Rule

To prove the differentiation of tan⁻¹x using the chain rule,

Consider y = tan⁻¹x.

Express tan⁻¹x = y then x = tan(y).

Differentiating both sides, dx/dy = sec²(y) Using the identity sec²(y) = 1 + tan²(y), dx/dy = 1 + x² Thus, dy/dx = 1/(1 + x²).

Therefore, the derivative of tan⁻¹x is 1/(1+x²).

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Higher-Order Derivatives of Tan⁻¹x

Higher-order derivatives involve differentiating a function multiple times.

For example, the speed of a car changes (first derivative), and the rate at which that speed changes (second derivative).

Higher-order derivatives of tan⁻¹x provide deeper insights into its behavior.

First Derivative: f′(x) = 1/(1+x²).

Second Derivative: The derivative of f′(x) provides more information about the curvature.

Nth Derivative: fⁿ(x) represents the nth derivative of the function, indicating changes in the rate of change.

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Special Cases:

When x = 0, the derivative of tan⁻¹x = 1/(1+0²), which is 1. As x approaches ±∞, the derivative approaches 0, indicating the function levels off.

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Common Mistakes and How to Avoid Them in Derivatives of Tan⁻¹x

Students often make errors when differentiating tan⁻¹x. Understanding the correct approach can resolve these mistakes. Here are some common errors and solutions:

Mistake 1

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Not simplifying the expression

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Students might skip simplifying the expression, leading to errors. It is crucial to follow each step methodically, especially when using the chain rule, to avoid mistakes.

Mistake 2

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Ignoring the derivative formula

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Students may forget the derivative formula for tan⁻¹x, which is crucial for correct differentiation. Always remember that d/dx (tan⁻¹x) = 1/(1+x²).

Mistake 3

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Incorrect application of the Chain Rule

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When differentiating functions like tan⁻¹(2x), students may neglect the chain rule. For example, d/dx (tan⁻¹(2x)) ≠ 1/(1+4x²). Correct it by applying: d/dx (tan⁻¹(2x)) = (2)/(1+(2x)²).

Mistake 4

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Misidentifying Undefined Points

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Unlike tan(x), tan⁻¹(x) is defined for all real x, but students might incorrectly assume undefined points exist. Remember, tan⁻¹(x) is continuous everywhere on the real line.

Mistake 5

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Confusing with other inverse functions

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Students might confuse the derivative of tan⁻¹x with those of other inverse functions. Ensure clarity by memorizing that d/dx (tan⁻¹x) = 1/(1+x²).

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Examples Using the Derivative of Tan⁻¹x

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Problem 1

Calculate the derivative of tan⁻¹(x)·(1+x²).

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Let f(x) = tan⁻¹(x)·(1+x²).

Using the product rule, f'(x) = u′v + uv′

Here, u = tan⁻¹x and v = 1+x².

Differentiate each term: u′ = d/dx (tan⁻¹x) = 1/(1+x²) v′ = d/dx (1+x²) = 2x

Substitute back into the equation: f'(x) = [1/(1+x²)](1+x²) + (tan⁻¹x)(2x) = 1 + 2x tan⁻¹x

Thus, the derivative is 1 + 2x tan⁻¹x.

Explanation

We find the derivative by breaking the function into two parts, differentiating each, and then applying the product rule to combine them for the final result.

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Problem 2

A bridge's slope is modeled by y = tan⁻¹(x). If x = 1 meter, find the slope of the bridge.

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Given y = tan⁻¹(x), the slope is represented by dy/dx.

Differentiate y = tan⁻¹(x): dy/dx = 1/(1+x²)

Substitute x = 1: dy/dx = 1/(1+1²) = 1/2

Hence, the slope of the bridge at x = 1 meter is 1/2.

Explanation

We compute the slope by differentiating the function and substituting the given value of x to find the rate of elevation change.

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Problem 3

Derive the second derivative of y = tan⁻¹(x).

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First, find the first derivative: dy/dx = 1/(1+x²)

Now, differentiate again to find the second derivative: d²y/dx² = d/dx [1/(1+x²)]

Using the chain rule: d²y/dx² = -2x/(1+x²)²

Thus, the second derivative is -2x/(1+x²)².

Explanation

We calculate the second derivative by differentiating the first derivative using the chain rule and simplifying the expression.

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Problem 4

Prove: d/dx (tan⁻¹(x²)) = 2x/(1+x⁴).

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Apply the chain rule: Let y = tan⁻¹(x²).

Then dy/dx = (d/dx [x²])/(1+(x²)²) = (2x)/(1+x⁴).

Thus, d/dx (tan⁻¹(x²)) = 2x/(1+x⁴), proving the statement.

Explanation

The chain rule is used to differentiate the composite function, and the derivative of the inner function is substituted to derive the final result.

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Problem 5

Solve: d/dx (tan⁻¹(3x)).

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Differentiate using the chain rule: d/dx (tan⁻¹(3x)) = (3)/(1+(3x)²) = 3/(1+9x²). Thus, d/dx (tan⁻¹(3x)) = 3/(1+9x²).

Explanation

We apply the chain rule to differentiate the function, considering the derivative of the inner function 3x and simplifying to obtain the result.

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FAQs on the Derivative of Tan⁻¹x

1.Find the derivative of tan⁻¹x.

The derivative of tan⁻¹x is 1/(1+x²), obtained using the derivative formula.

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2.Can we use the derivative of tan⁻¹x in real life?

Yes, it is used in real-life applications such as calculating angles, slopes, and in various engineering and physics problems.

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3.Is it possible to take the derivative of tan⁻¹x at the point where x = 0?

Yes, at x = 0, the derivative of tan⁻¹x is 1/(1+0²) = 1.

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4.What rule is used to differentiate tan⁻¹(3x)?

The chain rule is used to differentiate tan⁻¹(3x): d/dx (tan⁻¹(3x)) = (3)/(1+(3x)²).

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5.Are the derivatives of tan x and tan⁻¹x the same?

No, they are different. The derivative of tan x is sec²x, while the derivative of tan⁻¹x is 1/(1+x²).

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Important Glossaries for the Derivative of Tan⁻¹x

  • Derivative: The derivative of a function indicates its rate of change with respect to a variable.

 

  • Inverse Function: A function that reverses the effect of another function, such as tan⁻¹x.

 

  • Chain Rule: A rule for differentiating composite functions.

 

  • Limit: A fundamental concept in calculus used to define derivatives.

 

  • Domain: The set of input values for which a function is defined.
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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