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Last updated on October 17, 2025
We use the derivative of 1-x, which is -1, as a measuring tool for how the linear function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of 1-x in detail.
We now understand the derivative of 1-x. It is commonly represented as d/dx (1-x) or (1-x)', and its value is -1. The function 1-x has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Linear Function: (1-x is a linear function).
Constant Rule: The derivative of a constant is 0.
Power Rule: Used for differentiating terms of the form xⁿ.
The derivative of 1-x can be denoted as d/dx (1-x) or (1-x)'.
The formula we use to differentiate 1-x is: d/dx (1-x) = -1 (or) (1-x)' = -1
The formula applies to all x in the real number domain.
We can derive the derivative of 1-x using proofs. To show this, we will use basic differentiation rules.
There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of 1-x results in -1 using the above-mentioned methods:
The derivative of 1-x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of 1-x using the first principle, we will consider f(x) = 1-x. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = 1-x, we write f(x + h) = 1-(x + h). Substituting these into equation (1), f'(x) = limₕ→₀ [1-(x + h) - (1-x)] / h = limₕ→₀ [-h] / h = limₕ→₀ -1 f'(x) = -1. Hence, proved.
To prove the differentiation of 1-x using the power rule, We use the formula: 1-x = 1 - x¹ The derivative of a constant is 0, and the derivative of x¹ is 1. Therefore, d/dx (1-x) = 0 - 1 = -1.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be simple for linear functions. To understand them better, think of a constant velocity where the speed remains the same, and the acceleration (second derivative) is zero. Higher-order derivatives make it easier to understand functions like 1-x.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative of a linear function like 1-x is 0, denoted using f′′(x).
For the nth Derivative of 1-x, we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change. In this case, all higher-order derivatives are 0.
For any x, the derivative of 1-x is always -1, as it is a constant slope.
For any change in x, the change in the y-value of the function 1-x is constant.
Students frequently make mistakes when differentiating 1-x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (1-x)²
Here, we have f(x) = (1-x)². Using the chain rule, f'(x) = 2(1-x)(-1) = -2(1-x) = -2 + 2x. Thus, the derivative of the specified function is -2 + 2x.
We find the derivative of the given function by recognizing it as a composite function and applying the chain rule.
The first step is finding its derivative and then simplifying to get the final result.
A company measures its profit by the function P(x) = 1-x, where P represents profit and x represents units of a product. If x = 3, calculate the rate of change of profit.
We have P(x) = 1-x (profit function)...(1) Now, we will differentiate the equation (1). Take the derivative of 1-x: dP/dx = -1. Given x = 3 (substitute this into the derivative), dP/dx = -1. Hence, the rate of change of profit at x = 3 is -1.
We find the rate of change of profit at x = 3 as -1, which means that for each additional unit, the profit decreases by 1 unit.
Derive the second derivative of the function y = 1-x.
The first step is to find the first derivative, dy/dx = -1...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = 0. Therefore, the second derivative of the function y = 1-x is 0.
We use the step-by-step process, where we start with the first derivative, which is a constant.
The second derivative of a constant is 0, indicating no change in the rate of change.
Prove: d/dx ((1-x)²) = -2(1-x).
Let’s start using the chain rule: Consider y = (1-x)². To differentiate, we use the chain rule: dy/dx = 2(1-x)(-1) = -2(1-x). Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation.
We replaced (1-x) with its derivative and simplified to derive the equation.
Solve: d/dx (1-x)³
To differentiate the function, we use the chain rule: Let y = (1-x)³. dy/dx = 3(1-x)²(-1) = -3(1-x)². Therefore, d/dx (1-x)³ = -3(1-x)².
In this process, we differentiate the given function using the chain rule.
As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.