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Last updated on September 16, 2025
Calculators are reliable tools for solving simple mathematical problems and advanced calculations like linear algebra. Whether you're analyzing data, solving systems of equations, or studying transformations, calculators make your life easier. In this topic, we are going to talk about eigenvalue and eigenvector calculators.
An eigenvalue and eigenvector calculator is a tool to determine the eigenvalues and eigenvectors of a given square matrix.
Since matrices can be complex, the calculator helps simplify the process of finding these values. This calculator makes finding eigenvalues and eigenvectors much easier and faster, saving time and effort.
Given below is a step-by-step process on how to use the calculator:
Step 1: Enter the matrix: Input the elements of the square matrix into the given fields.
Step 2: Click on calculate: Click on the calculate button to find the eigenvalues and eigenvectors.
Step 3: View the result: The calculator will display the eigenvalues and eigenvectors instantly.
To find eigenvalues and eigenvectors, the calculator uses the characteristic equation of a matrix. For a square matrix A, the eigenvalues are found by solving the equation: det(A - λI) = 0 where λ represents the eigenvalues and I is the identity matrix.
Once eigenvalues are determined, eigenvectors can be found by solving the system: (A - λI)v = 0 where v is the eigenvector corresponding to the eigenvalue λ.
When using an eigenvalue and eigenvector calculator, there are a few tips and tricks to make it easier and avoid mistakes:
We may think that when using a calculator, mistakes will not happen. But it is possible for users to make mistakes when using a calculator.
Find the eigenvalues of the matrix \(\begin{bmatrix} 2 & 1 \\ 1 & 2 \end{bmatrix}\).
To find eigenvalues, solve the characteristic equation: det(A - λI) = 0 det\(\begin{bmatrix} 2-λ & 1 \\ 1 & 2-λ \end{bmatrix}\) = 0 (2-λ)(2-λ) - 1×1 = λ² - 4λ + 3 = 0 Solve: λ² - 4λ + 3 = 0 Eigenvalues: λ₁ = 3, λ₂ = 1
By solving the characteristic equation, we find the eigenvalues λ₁ = 3 and λ₂ = 1.
Determine the eigenvectors for the matrix \(\begin{bmatrix} 4 & -2 \\ 1 & 1 \end{bmatrix}\).
First, find eigenvalues by solving: det(A - λI) = 0 det\(\begin{bmatrix} 4-λ & -2 \\ 1 & 1-λ \end{bmatrix}\) = 0 (4-λ)(1-λ) + 2 = λ² - 5λ + 6 = 0 Eigenvalues: λ₁ = 3, λ₂ = 2 For λ₁ = 3, solve (A - 3I)v = 0: \(\begin{bmatrix} 1 & -2 \\ 1 & -2 \end{bmatrix}\)\(\begin{bmatrix} x \\ y \end{bmatrix}\) = \(\begin{bmatrix} 0 \\ 0 \end{bmatrix}\) Eigenvector: v₁ = \(\begin{bmatrix} 2 \\ 1 \end{bmatrix}\) For λ₂ = 2, solve (A - 2I)v = 0: \(\begin{bmatrix} 2 & -2 \\ 1 & -1 \end{bmatrix}\)\(\begin{bmatrix} x \\ y \end{bmatrix}\) = \(\begin{bmatrix} 0 \\ 0 \end{bmatrix}\) Eigenvector: v₂ = \(\begin{bmatrix} 1 \\ 1 \end{bmatrix}\)
Solving the eigenvalue equations provides the eigenvectors v₁ = \(\begin{bmatrix} 2 \\ 1 \end{bmatrix}\) and v₂ = \(\begin{bmatrix} 1 \\ 1 \end{bmatrix}\).
Find the eigenvalues of the matrix \(\begin{bmatrix} 3 & 0 \\ 0 & -1 \end{bmatrix}\).
det(A - λI) = 0 det\(\begin{bmatrix} 3-λ & 0 \\ 0 & -1-λ \end{bmatrix}\) = 0 (3-λ)(-1-λ) = λ² - 2λ - 3 = 0 Eigenvalues: λ₁ = 3, λ₂ = -1
The straightforward calculation shows that the eigenvalues are λ₁ = 3 and λ₂ = -1.
Determine the eigenvectors for the matrix \(\begin{bmatrix} 5 & 4 \\ 2 & 3 \end{bmatrix}\).
Find eigenvalues: det(A - λI) = 0 det\(\begin{bmatrix} 5-λ & 4 \\ 2 & 3-λ \end{bmatrix}\) = 0 (5-λ)(3-λ) - 8 = λ² - 8λ + 7 = 0 Eigenvalues: λ₁ = 7, λ₂ = 1 For λ₁ = 7, solve (A - 7I)v = 0: \(\begin{bmatrix} -2 & 4 \\ 2 & -4 \end{bmatrix}\)\(\begin{bmatrix} x \\ y \end{bmatrix}\) = \(\begin{bmatrix} 0 \\ 0 \end{bmatrix}\) Eigenvector: v₁ = \(\begin{bmatrix} 2 \\ 1 \end{bmatrix}\) For λ₂ = 1, solve (A - 1I)v = 0: \(\begin{bmatrix} 4 & 4 \\ 2 & 2 \end{bmatrix}\)\(\begin{bmatrix} x \\ y \end{bmatrix}\) = \(\begin{bmatrix} 0 \\ 0 \end{bmatrix}\) Eigenvector: v₂ = \(\begin{bmatrix} -1 \\ 1 \end{bmatrix}\)
The eigenvectors are determined for each eigenvalue: v₁ = \(\begin{bmatrix} 2 \\ 1 \end{bmatrix}\) and v₂ = \(\begin{bmatrix} -1 \\ 1 \end{bmatrix}\).
Find the eigenvalues of the matrix \(\begin{bmatrix} 1 & 2 \\ 2 & 4 \end{bmatrix}\).
det(A - λI) = 0 det\(\begin{bmatrix} 1-λ & 2 \\ 2 & 4-λ \end{bmatrix}\) = 0 (1-λ)(4-λ) - 4 = λ² - 5λ = 0 Eigenvalues: λ₁ = 5, λ₂ = 0
The characteristic equation gives us the eigenvalues λ₁ = 5 and λ₂ = 0.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables