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Last updated on September 17, 2025
Calculators are reliable tools for solving simple mathematical problems and advanced calculations like trigonometry. Whether you’re working on algebra, analyzing matrices, or studying differential equations, calculators will make your life easy. In this topic, we are going to talk about characteristic polynomial calculators.
A characteristic polynomial calculator is a tool used to determine the characteristic polynomial of a given square matrix. This polynomial is crucial in linear algebra as it is used to find eigenvalues, which have applications in various fields such as engineering and physics.
This calculator simplifies and speeds up the process, saving time and effort.
Given below is a step-by-step process on how to use the calculator:
Step 1: Enter the matrix: Input the elements of the square matrix into the given field.
Step 2: Click on calculate: Click on the calculate button to generate the characteristic polynomial.
Step 3: View the result: The calculator will display the polynomial instantly.
To find the characteristic polynomial of a matrix A, we use the formula:
\(P(\lambda) = \det(A - \lambda I)\) where \(\lambda\) is a scalar, I is the identity matrix of the same order as A , and det denotes the determinant.
The calculator computes this determinant, yielding a polynomial in terms of \(\lambda\) .
When using a characteristic polynomial calculator, there are a few tips and tricks that can help:
Understand the matrix structure to ensure accurate input.
Be familiar with matrix operations, as these are foundational to the process.
Verify calculations manually for simpler matrices to build intuition.
Mistakes can occur when using any tool, and a characteristic polynomial calculator is no exception.
Find the characteristic polynomial of the matrix \(\begin{bmatrix} 2 & 1 \\ 1 & 2 \end{bmatrix}\).
Use the formula: \(P(\lambda) = \det \left( \begin{bmatrix} 2 & 1 \\ 1 & 2 \end{bmatrix} - \lambda \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} \right)\)
\(P(\lambda) = \det \begin{bmatrix} 2-\lambda & 1 \\ 1 & 2-\lambda \end{bmatrix}\) \(= (2-\lambda)(2-\lambda) - 1 = \lambda^2 - 4\lambda + 3\)
Subtract \(\lambda\) I from the matrix and compute the determinant to get the characteristic polynomial.
Calculate the characteristic polynomial of the matrix \(\begin{bmatrix} 3 & 0 \\ 0 & -1 \end{bmatrix}\).
Use the formula: \(P(\lambda) = \det \left( \begin{bmatrix} 3 & 0 \\ 0 & -1 \end{bmatrix} - \lambda \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} \right)\)
\( P(\lambda) = \det \begin{bmatrix} 3-\lambda & 0 \\ 0 & -1-\lambda \end{bmatrix} \) \(= (3-\lambda)(-1-\lambda) = \lambda^2 - 2\lambda - 3 \)
Subtract \(\lambda \) from the matrix and calculate the determinant to find the polynomial.
Determine the characteristic polynomial of the matrix \(\begin{bmatrix} 4 & 2 \\ 1 & 3 \end{bmatrix}\).
Use the formula: \(P(\lambda) = \det \left( \begin{bmatrix} 4 & 2 \\ 1 & 3 \end{bmatrix} - \lambda \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} \right)\)
\(P(\lambda) = \det \begin{bmatrix} 4-\lambda & 2 \\ 1 & 3-\lambda \end{bmatrix} = (4-\lambda)(3-\lambda) - 2 = \lambda^2 - 7\lambda + 10 \)
Apply the formula by subtracting \(\lambda\) and finding the determinant for the polynomial.
Find the characteristic polynomial of the identity matrix \(\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}\).
Use the formula: \(P(\lambda) = \det \left( \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} - \lambda \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} \right)\)
\(P(\lambda) = \det \begin{bmatrix} 1-\lambda & 0 \\ 0 & 1-\lambda \end{bmatrix} = (1-\lambda)(1-\lambda) = \lambda^2 - 2\lambda + 1\)
Compute the determinant of the matrix after subtracting \(\lambda\) .
Determine the characteristic polynomial for the matrix \(\begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix}\).
Use the formula: \(P(\lambda) = \det \left( \begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix} - \lambda \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} \right)\)
\(P(\lambda) = \det \begin{bmatrix} -\lambda & 1 \\ -1 & -\lambda \end{bmatrix} = (-\lambda)(-\lambda) - (1)(-1) = \lambda^2 + 1\)
By applying the determinant formula to the adjusted matrix, we obtain the characteristic polynomial.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables