Last updated on July 5th, 2025
In the polar form of a complex number, it is the distance from the origin and the angle it makes with the positive real axis. In rectangular form, a complex number is written as z = a + bi. The modulus and argument are used to represent the complex number in polar form. It is represented in the equation of z = r(cos θ + i sin θ), where r is the modulus and θ is the argument. In this article, we will discuss the polar form, its modulus and argument, and their applications.
A complex number in polar form is represented using its modulus and argument. The polar form of a complex number z = x + iy with coordinates (x, y) is z = r (cosθ+ i r sinθ) = r (cosθ + i sinθ), where r is the modulus and θ is the argument.
The modulus of a complex number is the distance from the origin in the complex plane. It represents the length of the vector from (0, 0) to (a, b). Using the Pythagorean theorem, the formula to find modulus (r) = |z| = √(a2 + b2).
The argument is the angle θ, measured counterclockwise from the positive real axis, to the vector representing the complex number in the complex plane. It can be calculated using the formula θ = tan-1 (b/a), in the range (-π/2, π/2). The argument depends on the quadrant and can range from -π to π, based on the quadrant adjustment.
Euler’s formula is a simpler way to write the polar form, and it is the link between the exponential and trigonometric functions. Euler’s formula = eiθ = cosθ + i sinθ, where e is the base of the natural logarithm, i is the imaginary unit, and θ is the angle in radians.
The complex number in polar form is written as z = r (cosθ + i sinθ),
Therefore, the polar form of a complex number is given by z = reiθ, as eiθ = cosθ + i sinθ.
To convert the complex number from rectangular form to polar form, we use the formulas r = √(a2 + b2), θ = tan-1 (b/a). To convert, follow these steps.
Step 1: Calculate the modulus: r = √a2 + b2
Step 2: Find the argument θ
Step 3: Express it in the form r(cosθ + i sinθ)
For example, to convert z = 1 + √3i in polar form, where a = 1 and b = √3
Finding the value of r
r = √a2 + b2 = √(12 + (√3)2)
= √1 + 3 = √4 = 2
Finding the value of θ
θ = tan-1(√3/1) = tan-1(√3)
So,
In polar form, it can be expressed as z = r(cosθ + i sinθ)
z = 2(cos 60° + i sin 60°)
The complex plane is a two-dimensional plane, with the horizontal axis representing the real part and the vertical axis representing the imaginary part of the complex number. Follow these steps for the graphical representation of complex numbers in polar form.
Step 1: Find the value of the modulus
The value of the modulus can be calculated using the formula, r = √a2 + b².
Step 2: Find the value of θ
The value of θ is calculated using the formula, θ = tan-1(b/a)
Step 3: Find the polar form of the complex number
Now we express the value of r and θ in z = r (cosθ + i sinθ)
Step 4: Graphical representation
In the graph, the x-axis represents the real part and the y-axis represents the imaginary part. Mark the center (0, 0), in the direction of θ, move a distance r (modulus) from the origin at an angle θ, and mark the point. Then connect the point with the center.
For example, graphically represent z= 3 + 3i
Find the value of modulus, r = √a² + b²
Here, r = √3² + 3²
= √9 + 9 = √18 = 3√2
Finding the value of θ
θ = tan-1(b/a)
= tan-1(3/3) = tan-1(1) = 45°
Quadrant check: If the complex number has a negative part, the angle would be adjusted depending on the quadrant. Since both a and b are positive here, we don't need to adjust the angle.
In polar form z can be expressed as z = 3√2(cos 45° + i sin 45°)
Polar form is the efficient method for multiplying and dividing complex numbers. It is used in the fields of engineering, physics, and signal processing.
Multiplication in Polar Form
In polar form to multiply complex numbers, we first multiply the moduli and add the arguments. For example, z1 = r1(cosθ1 + i sinθ1) and z2 = r2(cosθ2 + i sinθ2)
z1 × z2 = r1 × r2(cos(θ1 + θ2) + i sin(θ1 + θ2))
Division in Polar Form
To divide complex numbers in polar form we divide the moduli and subtract the arguments. For example z1 = r1(cosθ1 + i sinθ1) and z2 = r2(cosθ2 + i sinθ2)
z1/z2 = r1/r2((cos(θ1 - θ2) + i sin(θ1 - θ2))
Powers and Roots in Polar Form
In this section, we will learn how to find the value of power and roots of complex numbers using De Moivre’s theorem. Let's learn them in detail.
De Moivre’s theorem is a simple way to raise complex numbers to powers for the polar form. The formula is [r (cosθ + i sinθ)]n = rn (cos nθ + i sin nθ).
Finding the roots of a complex number: The nth root of a complex number uses the formula.
Zk = r1/n (cos θ + 2kπ/n + i sin θ + 2kπ/n), where k = 0, 1, 2, … n-1.
The polar form of complex numbers is used in fields like engineering, physics, and computer science. Some applications of the polar form of complex numbers are given below:
Students usually make errors when working with complex numbers in polar form. So let’s learn about some mistakes and the ways to avoid them.
Convert 1 + i to polar form
In polar form 1 + i is √2 (cosπ/4 + i sinπ/4)
To convert a rectangular form to a polar form, we first find the value of r and θ.
r = √a2 + b2
Here, a = 1 and b = 1
Therefore, r = √12 + 12
= √2
The argument θ = tan-1(b/a)
= tan-1(1) = π/4
In polar form, it can be expressed as √2 (cos π/4 + i sin π/4)
Convert 3(cosπ/6 + i sinπ/6) to rectangular form
In rectangular form 3(cosπ/6 + i sinπ/6) can be expressed as 3(√3/2) + i(3/2)
The value of cosπ/6 = √3/2
The value of sinπ/6 = 1/2
Multiplying by 3:
3 (cosπ/6) = 3 × √3/2
=3√3/2
3 (sinπ/6) = 3 × ½
=3/2
So, in rectangular form, it can be expressed as 3(√3/2) + i(3/2)
Find the product of 3√2 (cosπ/4 + i sinπ/4) and √2 (cos(-π/4) + i sin(-π/4)
The product of 3√2 (cosπ/4 + i sinπ/4) and √2 (cos(-π/4) + i sin(-π/4) is 6.
When multiplying the polar form, we first multiply the moduli and then add the arguments.
Multiplying the moduli: 3√2 × √2 = 3 ×2 = 6
Adding the argument: π/4 + (-π/4) = 0
That is 6 (cos0 + i sin0) = 6 (1 + 0i)
= 6
Find the quotient of √2 (cosπ/4 + i sinπ/4) by 2 (cosπ/6 + i sinπ/6)
The quotient of √2 (cosπ/4 + i sinπ/4) by 2 (cosπ/6 + i sinπ/6) is √2/2 (cosπ/12 + i sinπ/12)
When dividing the polar form, first we divide the moduli and then subtract the arguments.
Dividing the moduli: √2/2
Subtracting the argument: π/4 - π/6
= 3π/12 - 2π/12
= π/12
So, the quotient is √2/2 (cosπ/12 + i sinπ/12)
Convert -6 to polar form.
-6 in polar form can be expressed as 6 (cosπ + i sinπ)
The number -6 lies on the negative real axis
So, r = |-6| = 6
θ = π, as the number is on the negative real axis
So, in polar form, it can be expressed as 6(cosπ + i sinπ)
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.