Last updated on June 18th, 2025
When we perform experiments that have only two possible outcomes we call them Bernoulli trials. Success or failure, yes or no, and true or false are the possible results of these trials. Bernoulli trials are fundamental in probability and probability distributions. In this topic, we are exploring and analyzing the properties of Bernoulli trials.
The Bernoulli trials are the independent trials in which the probability of getting a possible outcome remains the same. In probability experiments, no matter how many times the same experiment is conducted, the outcome will be either 1 (success) or 0 (failure).
The concept was introduced by a Swiss mathematician, Jacob Bernoulli, in the 17th century.
For a better understanding, take a real-life example: whether Alan wins the running match or not.
Here, the two possible results or outcomes are success or failure, and these answers are independent of each other.
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Bernoulli trials are important in probability and many probability theories are established based on these trials. However, the Bernoulli trials need to meet certain conditions. They are listed below:
Bernoulli trials help us predict the probability of an event happening or not. In our daily lives, the formulas related to the Bernoulli trials assist in calculating the probabilities and estimating the outcomes in advance.
1. We can calculate the probability of success or failure in a probability distribution by using the formula:
P(x = 1) = p,
P(x = 0) = 1 - p = q
Here, x is a random variable in a Bernoulli distribution.
p is the probability of success.
q = 1 - p is the probability of failure.
2. In a binomial experiment that has a number of independent Bernoulli trials, the number of successes is represented by X. Then the formula is:
P (X = k) = nCk pkqn-k
Here, k is the desired number of successes.
p is the probability of success in each trial.
`Ck represents that n chooses k.
q is the probability of failure.
3. When we calculate the probability mass function (PMF) of the Bernoulli distribution when n = 1 in the binomial distribution, the z is a random variable and p is the probability of success:
f(z, p) = {p, if z = 1 and q = 1- p, if z = 0}
Or,
f(z, p) = pz (1 - p)1-z, for z = 0, 1
Or,
f(z, p) = pz + (1 - p)(1 - z), for z = 0, 1
4. A Bernoulli random variable X’s mean or the expected value can be calculated by using the formula:
E(X) = p
5. A Bernoulli random variable X’s variance can be calculated as:
Var[X] = p(1 - p) = pq
In our daily lives, we have lots of situations that only have two possible results. Bernoulli trials are widely used in various fields and scenarios to calculate probabilities.
The possible outcomes of Bernoulli trials are success or failure. Understanding the concepts and properties of this trail will assist kids in solving probability-related math problems and it helps them to check whether their conclusions are accurate and correct. Here are some common errors that kids encounter while performing Bernoulli trials, along with helpful solutions.
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A Quarter coin is tossed once. Is this a Bernoulli trial? Why?
Yes, it is a Bernoulli trial.
Heads (H) and Tails (T) are the two possible outcomes when we flip a coin.
If we consider Heads as Success and Tails as Failure, this meets the criteria of a Bernoulli trial.
The probability of getting heads (success) remains the same at ½.
The Bernoulli trial is independent because the outcome does not affect any future tosses.
So, it is a Bernoulli trial.
Roll a fair six-sided die once and check if the number is odd. Is this a Bernoulli trial?
Yes, it is a Bernoulli trial.
The die roll has six possible outcomes: {1, 2, 3, 4, 5, 6}. If we define success as rolling an odd number (1, 3, or 5), then success happens in three out of six cases.
Even though there are more than two outcomes originally, we are only considering two categories: Odd (Success) and Even (Failure).
The probability of success remains 3/6 = ½ and does not change.
The trials are independent.
Hence, it is a Bernoulli trial.
A bag contains 5 green and 5 black balls. A ball is drawn, its color noted, and it is not replaced. Another ball is drawn. Are these Bernoulli trials?
No, this is not a Bernoulli trial.
The first draw determines the color of the ball. If the ball is not replaced, the total number of balls changes, affecting the probability of the second draw. Since the probability of success is not constant, these are not independent trials. Therefore, this is not a Bernoulli trial.
A basketball player attempts a penalty kick. The shot is either successful or missed. If the player’s success rate is 65%, is this a Bernoulli trial?
Yes, this is a Bernoulli trial.
The player either scores the penalty (success) or misses it (failure).
The probability of success is 65%, which remains the same for each attempt.
Each attempt is independent, assuming no external factors like fatigue or psychological factors.
Hence, this is a Bernoulli trial.
Adam plays a video game, and the score depends on how well he plays. Is this a Bernoulli trial?
No, this is not a Bernoulli trial.
The score is not just two possible outcomes (success/failure).
The outcome is not binary, as the player (Adam) could score various points.
So, this is not a Bernoulli trial.
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