Last updated on July 21st, 2025
We use the derivative of (ln(x))² as a tool to understand the rate of change of the natural logarithm squared function with respect to x. Derivatives are crucial in various fields such as physics, engineering, and economics for understanding growth, decay, and optimization. We will now discuss the derivative of (ln(x))² in detail.
We now explore the derivative of (ln(x))². It is commonly represented as d/dx ((ln(x))²) or ((ln(x))²)', and its value is 2ln(x)/x. This function has a clearly defined derivative, indicating it is differentiable within its domain (x > 0). The key concepts involved are mentioned below: Natural Logarithm Function: ln(x) is the natural logarithm of x. Chain Rule: Rule for differentiating composite functions like (ln(x))².
The derivative of (ln(x))² can be denoted as d/dx ((ln(x))²) or ((ln(x))²)'. The formula we use to differentiate (ln(x))² is: d/dx ((ln(x))²) = 2ln(x)/x This formula applies to all x > 0.
We can derive the derivative of (ln(x))² using different methods. To show this, we will use the chain rule along with the properties of logarithms. Below are a few methods to prove this: Using Chain Rule To prove the differentiation of (ln(x))² using the chain rule, we consider it as a composition of functions: Let u = ln(x), so u² = (ln(x))². Using the chain rule: d/dx (u²) = 2u · du/dx Substituting u = ln(x) and du/dx = 1/x, we have: d/dx ((ln(x))²) = 2ln(x) · (1/x) = 2ln(x)/x Using Product Rule We can alternatively consider (ln(x))² as ln(x) · ln(x) and use the product rule: d/dx (ln(x) · ln(x)) = ln(x) · (1/x) + ln(x) · (1/x) = 2ln(x)/x Thus, we obtain the same result.
When a function is differentiated multiple times, the derivatives obtained are called higher-order derivatives. Understanding higher-order derivatives can be a bit complex, but they provide insights into the curvature and concavity of functions. For example, the first derivative gives us the slope, while the second derivative tells us about the rate of change of the slope. For the first derivative of a function, we write f′(x), indicating the function's change or its slope at a certain point. The second derivative, denoted as f′′(x), is derived from the first derivative and indicates the concavity of the function. For the nth derivative of (ln(x))², we generally use fⁿ(x) to represent the nth derivative, which describes the change in the rate of change.
At x = 1, the derivative of (ln(x))² simplifies to 2ln(1)/1, which is 0, since ln(1) = 0. When x approaches 0 from the positive side, the derivative becomes undefined because ln(x) is not defined for non-positive values.
Students frequently make mistakes when differentiating (ln(x))². These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (ln(x)·x³).
Here, we have f(x) = ln(x) · x³. Using the product rule, f'(x) = u′v + uv′ In the given equation, u = ln(x) and v = x³. Let's differentiate each term, u′ = d/dx (ln(x)) = 1/x v′ = d/dx (x³) = 3x² Substituting into the given equation, f'(x) = (1/x) · x³ + ln(x) · 3x² Let's simplify terms to get the final answer, f'(x) = x² + 3x²ln(x) Thus, the derivative of the specified function is x² + 3x²ln(x).
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A research company measures the growth rate of bacteria, represented by the function y = (ln(x))², where y represents the growth rate at a time x. If x = e, measure the growth rate.
We have y = (ln(x))² (growth rate formula)...(1) Now, we will differentiate equation (1): Take the derivative of (ln(x))²: dy/dx = 2ln(x)/x Given x = e (substitute this into the derivative), dy/dx = 2ln(e)/e Since ln(e) = 1, dy/dx = 2/e Hence, we get the growth rate of the bacteria at x = e as 2/e.
We find the growth rate of the bacteria at x = e as 2/e, indicating that at this point, the rate of change of growth is 2/e times the initial rate.
Derive the second derivative of the function y = (ln(x))².
The first step is to find the first derivative, dy/dx = 2ln(x)/x...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [2ln(x)/x] Here we use the quotient rule, d²y/dx² = (x · (2/x) - 2ln(x) · 1)/(x²) = (2 - 2ln(x))/(x²) Therefore, the second derivative of the function y = (ln(x))² is (2 - 2ln(x))/(x²).
We use the step-by-step process, starting with the first derivative. Using the quotient rule, we differentiate 2ln(x)/x, then simplify the expression to find the final answer.
Prove: d/dx ((ln(x))³) = 3(ln(x))²/x.
Let’s start using the chain rule: Consider y = (ln(x))³ = [ln(x)]³ To differentiate, we use the chain rule: dy/dx = 3[ln(x)]² · d/dx [ln(x)] Since the derivative of ln(x) is 1/x, dy/dx = 3[ln(x)]² · (1/x) Substituting y = (ln(x))³, d/dx ((ln(x))³) = 3(ln(x))²/x Hence proved.
In this step-by-step process, we use the chain rule to differentiate the equation. Then, we replace the derivative of ln(x) and simplify the expression to prove the equation.
Solve: d/dx ((ln(x))/x).
To differentiate the function, we use the quotient rule: d/dx ((ln(x))/x) = (d/dx (ln(x)) · x - ln(x) · d/dx(x))/x² We will substitute d/dx (ln(x)) = 1/x and d/dx (x) = 1 = (1/x · x - ln(x) · 1)/x² = (1 - ln(x))/x² Therefore, d/dx ((ln(x))/x) = (1 - ln(x))/x²
In this process, we differentiate the given function using the quotient rule. We substitute the derivatives of each term and simplify the equation to obtain the final result.
Derivative: The derivative of a function measures how the function changes as its input changes. Natural Logarithm: ln(x) is the logarithm to the base e, where e is an irrational constant approximately equal to 2.718. Chain Rule: A rule for differentiating compositions of functions. Quotient Rule: A rule used for differentiating the quotient of two functions. Higher-order Derivative: Derivatives of a function taken multiple times, providing information on the curvature and concavity of the function.
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