Last updated on July 21st, 2025
We use the derivative of cos(xy) to understand how the cosine function changes when the product of x and y changes slightly. Derivatives are crucial in many fields for understanding rates of change and are used in real-life applications such as physics and engineering. We will now explore the derivative of cos(xy) in detail.
The derivative of cos(xy) is expressed as d/dx (cos(xy)) or (cos(xy))'. Since cos(xy) is a product of two variables within the cosine function, we apply the chain rule for differentiation. The key concepts include: - Cosine Function: cos(xy) is a trigonometric function. - Chain Rule: A rule for differentiating composite functions. - Product Rule: A rule for differentiating products of two functions.
The derivative of cos(xy) with respect to x can be denoted as d/dx (cos(xy)) or (cos(xy))'. By applying the chain rule, we get: d/dx (cos(xy)) = -sin(xy) * (y + x * dy/dx) This formula applies to all x and y where xy is defined in the domain of the cosine function.
We can derive the derivative of cos(xy) using several methods. These include: - By First Principle - Using Chain Rule - Using Product Rule We will demonstrate the differentiation of cos(xy) using the following methods: Using Chain Rule To prove the differentiation of cos(xy) using the chain rule, we consider the composite function inside the cosine: f(x, y) = xy, so the differentiation involves: d/dx (cos(f(x, y))) = -sin(f(x, y)) * d/dx(f(x, y)) d/dx (cos(xy)) = -sin(xy) * (y + x * dy/dx) The derivative of f(x, y) with respect to x is y, and we apply the chain rule to get the final result. Using Product Rule To differentiate cos(xy) using the product rule, consider: g(x) = x and h(y) = y, hence f(x, y) = xy. d/dx (cos(xy)) = -sin(xy) * d/dx(xy) = -sin(xy) * (y + x * dy/dx) By applying the product rule, we determine the derivative of xy, then apply it in the chain rule to find the derivative of cos(xy).
When a function is differentiated multiple times, the resulting derivatives are referred to as higher-order derivatives. Higher-order derivatives are often more complex. To illustrate, consider a vehicle's acceleration (second derivative) and jerk (third derivative). Understanding higher-order derivatives of functions like cos(xy) can be challenging but is essential in fields like physics and engineering. For the first derivative, we write f′(x), indicating how the function changes at a point. The second derivative, f′′(x), is derived from the first, and this pattern continues for higher-order derivatives.
When x or y is such that xy equals π/2, the derivative is undefined because sin(xy) has a vertical asymptote there. When x or y is 0, the derivative of cos(xy) equals zero, as sin(0) is zero.
Students often make errors when differentiating cos(xy). These can be avoided by understanding the correct methods. Here are a few common mistakes and solutions:
Calculate the derivative of f(x, y) = cos(3xy).
Here, f(x, y) = cos(3xy). Using the chain rule, f'(x) = -sin(3xy) * d/dx(3xy) = -sin(3xy) * (3y + 3x * dy/dx)
We find the derivative by recognizing the function as a composition involving 3xy, applying the chain rule, and differentiating the inner function 3xy.
A Ferris wheel's position can be modeled by the function z = cos(xy), where z represents the height and xy the angle at which the seat is located. If x = 2 meters and y = π/6, calculate the rate of change of height with respect to x.
We have z = cos(xy). Differentiating with respect to x, dz/dx = -sin(xy) * (y + x * dy/dx) Substitute x = 2 and y = π/6, dz/dx = -sin(2π/6) * (π/6) = -sin(π/3) * (π/6) = -(√3/2) * (π/6) = -π√3/12
The derivative gives the rate of change of height concerning x, considering x and y values. Here, the rate of change is calculated using specific values for x and y.
Derive the second derivative of the function z = cos(xy).
First derivative: dz/dx = -sin(xy) * (y + x * dy/dx) Second derivative: d²z/dx² = -cos(xy) * (y + x * dy/dx)² - sin(xy) * (d²(xy)/dx²) This involves further differentiating the first derivative, taking into account the product and chain rules.
The second derivative involves differentiating the first derivative, ensuring all rules are applied correctly. This requires careful application of the chain and product rules.
Prove: d/dx (cos²(xy)) = -2cos(xy)sin(xy)(y + x * dy/dx).
Using the chain rule, Consider u = cos(xy), so u² = cos²(xy) d/dx (u²) = 2u * d/dx(u) d/dx (cos²(xy)) = 2cos(xy) * (-sin(xy) * (y + x * dy/dx)) = -2cos(xy)sin(xy)(y + x * dy/dx)
We use the chain rule to differentiate the square function, then apply the derivative of cos(xy), resulting in the desired expression.
Solve: d/dx (cos(xy)/x).
Using the quotient rule, d/dx (cos(xy)/x) = (x * d/dx(cos(xy)) - cos(xy) * d/dx(x)) / x² = (x * (-sin(xy) * (y + x * dy/dx)) - cos(xy)) / x² = -(xsin(xy)(y + x * dy/dx) + cos(xy)) / x²
The quotient rule is applied, differentiating the numerator and denominator separately, then simplifying the expression to reach the solution.
Derivative: A measure of how a function changes with respect to changes in its input variables. Cosine Function: A trigonometric function representing the cosine of an angle or product of variables. Chain Rule: A fundamental rule for differentiating composite functions. Product Rule: A rule for differentiating products of two functions. Partial Derivative: The derivative of a function with respect to one variable while keeping others constant.
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