Last updated on May 27th, 2025
When a number is multiplied by itself thrice, the resultant number is called the cube of a number. Cubing is used while comparing sizes of objects or things with cubic measurements. In this topic, we shall learn about cubes of 831.
A cube number is a value obtained by raising a number to the power of 3, or by multiplying the number by itself three times. When you cube a positive number, the result is always positive. When you cube a negative number, the result is always negative. This is because a negative number by itself three times results in a negative number. The cube of 831 can be written as 831³, which is the exponential form. Or it can also be written in arithmetic form as, 831 × 831 × 831.
In order to check whether a number is a cube number or not, we can use the following three methods, such as multiplication method, a factor formula (a³), or by using a calculator. These three methods will help kids to cube the numbers faster and easier without feeling confused or stuck while evaluating the answers. By Multiplication Method Using a Formula Using a Calculator
The multiplication method is a process in mathematics used to find the product of two numbers or quantities by combining them through repeated addition. It is a fundamental operation that forms the basis for more complex mathematical concepts. Step 1: Write down the cube of the given number. 831³ = 831 × 831 × 831 Step 2: You get 574,671,591 as the answer. Hence, the cube of 831 is 574,671,591.
The formula (a + b)³ is a binomial formula for finding the cube of a number. The formula is expanded as a³ + 3a²b + 3ab² + b³. Step 1: Split the number 831 into two parts, as 800 and 31. Let a = 800 and b = 31, so a + b = 831 Step 2: Now, apply the formula (a + b)³ = a³ + 3a²b + 3ab² + b³ Step 3: Calculate each term a³ = 800³ 3a²b = 3 × 800² × 31 3ab² = 3 × 800 × 31² b³ = 31³ Step 4: Add all the terms together: (a + b)³ = a³ + 3a²b + 3ab² + b³ (800 + 31)³ = 800³ + 3 × 800² × 31 + 3 × 800 × 31² + 31³ 831³ = 512,000,000 + 59,520,000 + 2,304,000 + 29,791 831³ = 574,671,591 Step 5: Hence, the cube of 831 is 574,671,591.
To find the cube of 831 using a calculator, input the number 831 and use the cube function (if available) or multiply 831 × 831 × 831. This operation calculates the value of 831³, resulting in 574,671,591. It’s a quick way to determine the cube without manual computation. Step 1: Ensure the calculator is functioning properly. Step 2: Press 8 followed by 3 and 1. Step 3: If the calculator has a cube function, press it to calculate 831³. Step 4: If there is no cube function on the calculator, simply multiply 831 three times manually. Step 5: The calculator will display 574,671,591.
The cube of any even number is always even, while the cube of any odd number is always odd. The product of two or more perfect cube numbers is always a perfect cube. A perfect cube can always be expressed as the product of three identical groups of equal prime factors.
There are some typical errors that kids might make during the process of cubing a number. Let us take a look at five of the major mistakes that kids might make:
What is the cube and cube root of 831?
The cube of 831 is 574,671,591 and the cube root of 831 is approximately 9.446.
First, let’s find the cube of 831. We know that cube of a number, such that x³ = y Where x is the given number, and y is the cubed value of that number So, we get 831³ = 574,671,591 Next, we must find the cube root of 831 We know that cube root of a number ‘x’, such that ∛x = y Where ‘x’ is the given number, and y is the cube root value of the number So, we get ∛831 ≈ 9.446 Hence, the cube of 831 is 574,671,591 and the cube root of 831 is approximately 9.446.
If the side length of the cube is 831 cm, what is the volume?
The volume is 574,671,591 cm³.
Use the volume formula for a cube V = Side³. Substitute 831 for the side length: V = 831³ = 574,671,591 cm³.
How much larger is 831³ than 400³?
831³ – 400³ = 571,071,591.
First find the cube of 831, that is 574,671,591 Next, find the cube of 400, which is 64,000,000 Now, find the difference between them using the subtraction method. 574,671,591 – 64,000,000 = 510,671,591 Therefore, the 831³ is 510,671,591 larger than 400³.
If a cube with a side length of 831 cm is compared to a cube with a side length of 50 cm, how much larger is the volume of the larger cube?
The volume of the cube with a side length of 831 cm is 574,671,591 cm³
To find its volume, we multiply the side length by itself three times (since it’s a 3-dimensional object). Cubing 831 means multiplying 831 by itself three times: 831 × 831 = 690,561, and then 690,561 × 831 = 574,671,591. The unit of volume is cubic centimeters (cm³), because we are calculating the space inside the cube. Therefore, the volume of the cube is 574,671,591 cm³.
Estimate the cube 830.1 using the cube 831.
The cube of 830.1 is approximately 574,671,591.
First, identify the cube of 831, The cube of 831 is 831³ = 574,671,591. Since 830.1 is only slightly less than 831, the cube of 830.1 will be almost the same as the cube of 831. The cube of 830.1 is approximately 574,671,591 because the difference between 830.1 and 831 is very small. So, we can approximate the value as 574,671,591.
Binomial Formula: It is an algebraic expression used to expand the powers of a number, written as (a + b)ⁿ, where ‘n’ is a positive integer raised to the base. The formula is used to find the square and cube of a number. Cube of a Number: Multiplying a number by itself three times is called the cube of a number. Exponential Form: It is a way of expressing numbers using a base and an exponent (or power), where the exponent value indicates how many times the base is multiplied by itself. For example, 2³ represents 2 × 2 × 2 equals 8. Perfect Cube: A number that can be expressed as the cube of an integer. For example, 27 is a perfect cube because it is 3³. Cube Root: The cube root of a number is a value that, when multiplied by itself three times, gives the original number. For example, the cube root of 8 is 2.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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