Last updated on June 10th, 2025
Algebraic expressions is a basic concept that is used in mathematics, for example imagine you want to buy x scrapbooks that cost y dollars each. To know the total expense of the given problem above, you need to learn algebraic expressions. These are phrases that contain numbers, letters, or even mathematical symbols. For example: Total expense = x y. Let’s now talk more about the topic.
Algebraic expressions is the most used way to solve unknown variables. Arithmetic operations (+, –, ×, and ÷) are performed on a combination of variables and constants to produce these mathematical expressions. For example: 2p + 3q + 5 (where p and q are variables; 5 is a constant and 2 and 3 are coefficients). An algebraic expression may contain one or more terms, and arithmetic operations help us in differentiating each term.
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The origin of algebraic expressions is seen in ancient Babylonian mathematics. During that time, academicians applied symbols to indicate undefined quantities in equations. Diophantus, a Greek mathematician, brought in well-structured methods to resolve equations. Later, Al-Kwarizmi, a Persian mathematician known as the Father of Algebra, developed systematic solutions for quadratic and linear systems. It was the contributions of René Descartes that developed the algebraic expressions, which involved the use of the expressions in variables and symbols. In the 21st century, algebraic expressions are employed in many sectors such as engineering, computer application, and science.
We now understand that algebraic expressions contain various mathematical symbols, numbers, or letters. Altogether, these elements are known as the components of algebraic expressions. Let’s discuss these components and how they define an expression’s structure:
i) Constants
Constants are the fixed numbers present in the expression. As the term suggests, their value does not change.
For example:
6y + 5 is an expression where 5 is a constant.
ii) Variables
The undefined symbols are represented using letters known as variables. The value of variables keeps changing in different problems.
For example:
4x + 2 is an expression where x represents variable.
iii) Coefficients
There are numbers in a term that have variables in it. Such numbers are coefficients.
They show the number of times the variable in the term is multiplied.
For example:
In 3p + 9q, the numbers 3 and 9 are coefficients of p and q.
iv) Terms
In an algebraic expression we use terms which are connected using arithmetic operations such as multiplication or division.
For example: 6x2 + 4x– 9, where, 6x2, 4x, and -9 are different terms.
v) Operators
The arithmetic operations (+, –, ×, and ÷) using which we connect the terms are referred to as operators.
For example:
In the expression, 5a – 3b + 8, the operators are (–) and (+).
Algebraic expressions may vary based on the number of terms they have. The different types of algebraic expressions are given below:
i) Monomial
If the algebraic expression has only one term in it, the expression is Monomial. A monomial can be a variable, a constant, or a combination of a constant and a variable.
For example:
2 x,
8y2
9pq
ii) Binomial
The algebraic expression that holds 2 terms is known as a binomial. The terms are differentiated by subtraction or addition signs.
For example:
y + 4
4a – 7b
3p + 5q
iii) Trinomial
If the algebraic expression contains three terms, then it is called a Trinomial.
For example: 5a – 6b + 8c
iv) Multinomial
A multinomial is an expression containing two or more terms, which also includes binomials and trinomials.
For example: 5a2 – 6ab + 8c + 4
Algebraic expressions are important for students as the concept improves their logical thinking skills. The concept of algebraic expressions help children understand complex concepts such as geometry and statistics. Learning algebraic expressions can help students in the preparation of math-based exams. They will also learn how to solve equations or problems in an organized way, developing problem-solving skills.
We solve algebraic expressions using arithmetic operations. These mathematical operations help us in differentiating and simplifying the terms in an expression. We will now discuss the four operations of algebraic expression:
i) Addition
We use addition to add up the terms that have the same exponents and variables (like terms).
For example: (2x + 3y + 6) + (5x + 9 y + 8).
To find the sum, we will combine the like terms:
(2x + 5x) + (3y + 9y) + (6 + 8)
7x + 12y + 14
ii) Subtraction
In the subtraction method, we will first remove the negative sign and then combine the similar terms.
For example: (3a + 4b – 2) – (5a – 6b + 8)
Let’s first give out the negative sign:
3a + 4b – 2 –5a + 6b – 8
To subtract the expression, we combine the like terms:
(3a – 5a) + (4b + 6b) + (– 2 – 8)
–2a + 10b – 10
iii) Multiplication
Terms can be expanded and multiplied by applying the distributive property
(9x + 4) (2x – 6)
Let’s multiply the terms using distributive property:
(9x. 2x) +(9x) (– 6) + 4 (2x) + 4(– 6)
18x2 – 54x + 8x – 24
18x2 – 46x – 24.
iv) Division
The Division of algebraic expressions involves taking out and eliminating common terms. The division of algebraic expressions is in two ways : monomial and polynomial division.
16 y3/ 4y
=16/ 4 = 4 (Dividing coefficients)
Now we subtract the exponents: y3 ÷ y1 = y3-1 = y2
4y2
(12x2 + 6x) ÷ 2x
Now we will divide each term individually:
12x2/ 2x + 6x/ 2x
6x + 3
Students find it challenging to solve the algebraic expressions. It can be due to several reasons. Here, we will discuss a few tips and tricks that may help students excel in algebraic expressions:
Algebraic expressions are not just mathematical statements; they are extensively used in various fields. Algebra helps children in estimating the interest rates of their study loans or savings growth. It helps them understand the different load capacities by determining the unknown values. It helps them analyze their favorite player’s statistics and calculate the scores. If you are traveling, you can check the distance covered or the speed. It can be used in determining the area of land or the water needs.
Making mistakes is common while solving algebraic expressions. Spotting these common mistakes and learning the ways to avoid them can help. We will now look into a few such mistakes and their solutions:
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Substitute y= 10 into the expression: 2y2– 5y + 7
2y2– 5y + 7 = 157
Let’s substitute the value y = 10,
2(10)2 – 5 (10) + 7
2(100) – 50 + 7 = 200 – 50 + 7 (simplify the expression)
200 – 50 + 7
157
Find two numbers when multiplied result in 6 and their sum results in 5.
2 and 3 are the numbers.
We need to look for numbers that give 6 when multiplied and 5 as their sum.
2 3 = 6 and 2 + 3 = 5.
Then list their factors: (x +2) (x+ 3).
Find the x in the given expression: 3x + 5 = 14
x = 3 in the given expression.
Let’s find the value of x:
3x = 14 – 5 (Isolating the variable)
3x = 9 (divide both sides by 3)
x = 9/3
x = 3
Simplify the given expression: 8x + 6 – 4x + 5
8x + 6 – 4x + 5 = 4x + 11
Combining the like terms,
8x – 4x = 4x (terms with x)
6+ 5 = 11 (constants).
Solve using distributive property: (5x+ 6) (8x–4)
40x2 + 28x –24
To solve using distributive property,
We distribute 5x to both the terms:
5x. 8x = 40 x2
5x. (– 4) = –20 x
Then 6 to both terms:
6(8x) = 48x
6 (– 4) = –24
Combining the like terms:
40x2– 20x + 48x– 24
40x2 + 28x– 24
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Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.