Last updated on August 5th, 2025
The Lagrange interpolation formula is a method for finding a polynomial that passes through a given set of points. In this topic, we will explore the formula for Lagrange interpolation and understand its application in numerical analysis.
Lagrange interpolation is a technique used to estimate a polynomial that fits a given set of data points. Let’s learn the formula for Lagrange interpolation and how it is applied.
The Lagrange interpolation formula is used to construct a polynomial of degree n-1 that passes through n given points (x₀, y₀), (x₁, y₁), ..., (xn₋₁, yn₋₁).
The formula is: [ P(x) = sum_{i=0}{n-1} y_i L_i(x) ] where: [ L_i(x) = prod_{j=0, j neq i}{n-1} frac{x - x_j}{x_i - x_j} ] Each ( L_i(x) ) is a Lagrange basis polynomial.
The Lagrange interpolation formula is crucial in numerical analysis for approximating functions and solving problems that require interpolation.
Here are some key points about its importance:
The Lagrange interpolation formula might seem complex, but here are some tips to master it:
Lagrange interpolation is widely used in real-life scenarios where estimating unknown values is required.
Here are a few applications:
Errors can occur when applying the Lagrange interpolation formula. Here are some common mistakes and how to avoid them.
Find the Lagrange interpolating polynomial for points (1, 2), (2, 3), and (3, 5).
The Lagrange interpolating polynomial is ( P(x) = -0.5x^2 + 3.5x - 2 )
To find the polynomial, calculate each ( L_i(x) ): [ L_0(x) = frac{(x-2)(x-3)}{(1-2)(1-3)}
= frac{(x-2)(x-3)}{2} ] [ L_1(x)
= frac{(x-1)(x-3)}{(2-1)(2-3)}
= -(x-1)(x-3) ] [ L_2(x)
= frac{(x-1)(x-2)}{(3-1)(3-2)}
= frac{(x-1)(x-2)}{2} ]
Then, construct ( P(x) ): [ P(x) = 2 cdot L_0(x) + 3 cdot L_1(x) + 5 cdot L_2(x) = -0.5x2 + 3.5x - 2 ]
Use Lagrange interpolation to estimate the value of the polynomial at x = 4 for points (1, 1), (2, 4), and (3, 9).
The estimated value of the polynomial at x = 4 is 16
First, find ( L_i(x) ): [ L_0(x) = frac{(x-2)(x-3)}{2} ] [ L_1(x)
= -(x-1)(x-3) ] [ L_2(x)
= frac{(x-1)(x-2)}{2} ]
The polynomial is: [ P(x) = 1 cdot L_0(x) + 4 cdot L_1(x) + 9 cdot L_2(x) ]
Evaluating at x = 4 yields ( P(4) = 16 ).
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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