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100 LearnersLast updated on October 25, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 55 and 88.
The greatest common factor of 55 and 88 is 11.
The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 55 and 88, a few methods are described below -
Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm
Steps to find the GCF of 55 and 88 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 55 = 1, 5, 11, 55. Factors of 88 = 1, 2, 4, 8, 11, 22, 44, 88.
Step 2: Now, identify the common factors of them Common factors of 55 and 88: 1, 11.
Step 3: Choose the largest factor The largest factor that both numbers have is 11.
The GCF of 55 and 88 is 11.
To find the GCF of 55 and 88 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 55: 55 = 5 x 11 Prime Factors of 88: 88 = 2 x 2 x 2 x 11 = 2³ x 11.
Step 2: Now, identify the common prime factors The common prime factor is: 11.
Step 3: Multiply the common prime factors 11.
The Greatest Common Factor of 55 and 88 is 11.
Find the GCF of 55 and 88 using the division method or Euclidean Algorithm Method.
Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 88 by 55 88 ÷ 55 = 1 (quotient), The remainder is calculated as 88 − (55×1) = 33 The remainder is 33, not zero, so continue the process.
Step 2: Now divide the previous divisor (55) by the previous remainder (33) Divide 55 by 33 55 ÷ 33 = 1 (quotient), remainder = 55 − (33×1) = 22. The remainder is 22, not zero, so continue the process.
Step 3: Now divide the previous divisor (33) by the previous remainder (22) Divide 33 by 22 33 ÷ 22 = 1 (quotient), remainder = 33 − (22×1) = 11. The remainder is 11, not zero, so continue the process.
Step 4: Now divide the previous divisor (22) by the previous remainder (11) Divide 22 by 11 22 ÷ 11 = 2 (quotient), remainder = 22 − (11×2) = 0. The remainder is zero; the divisor will become the GCF.
The GCF of 55 and 88 is 11.
Finding the GCF of 55 and 88 looks simple, but students often make mistakes while calculating the GCF.
Here are some common mistakes to be avoided by the students.
A gardener has 55 rose plants and 88 tulip plants. She wants to arrange them in rows with the same number of plants in each row, using the largest possible number of plants per row. How many plants will be in each row?
We should find the GCF of 55 and 88 GCF of 55 and 88 11.
There will be 11 plants in each row.
As the GCF of 55 and 88 is 11, the gardener can arrange 11 plants in each row.
A musician has 55 drumsticks and 88 guitar picks. He wants to put them into sets with the largest possible number of items in each set. How many items will be in each set?
GCF of 55 and 88 11 So each set will have 11 items.
There are 55 drumsticks and 88 guitar picks.
To find the total number of items in each set, we should find the GCF of 55 and 88.
There will be 11 items in each set.
A baker has 55 kg of flour and 88 kg of sugar. She wants to divide them into portions of equal weight, using the largest possible weight for each portion. What should be the weight of each portion?
For calculating the largest equal weight, we have to calculate the GCF of 55 and 88, The GCF of 55 and 88 is11.
The weight of each portion is 11 kg.
For calculating the largest weight of the portions, we first need to calculate the GCF of 55 and 88, which is 11.
The weight of each portion will be 11 kg.
An event organizer has two banners, one 55 meters long and the other 88 meters long. She wants to cut them into the longest possible equal pieces, without any material left over. What should be the length of each piece?
The organizer needs the longest piece of material GCF of 55 and 88 11, The longest length of each piece is 11 meters.
To find the longest length of each piece of the two banners, 55 meters and 88 meters, respectively, we have to find the GCF of 55 and 88, which is 11 meters.
The longest length of each piece is 11 meters.
If the GCF of 55 and ‘b’ is 11, and the LCM is 440. Find ‘b’.
The value of ‘b’ is 88.
GCF × LCM = product of the numbers 11 × 440 = 55 × b 4840 = 55b b = 4840 ÷ 55 = 88
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






